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a,bc + ab,c= 21,12
=> a,bc + a,bc x 10 = 21,12
=> a,bc x (1 + 10) = 21,12
=> a,bc x 11 = 21,12
=> a,bc = 1,92
Vậy abc = 192
a,bc+ab,c=21,21
=>a,bc+a,bcx10=21,21
=>a,bcx(1+10)=21,21
=>a,bcx11=21,21
=>a,bc=21,21:11
=>a,bc=1,92
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nhân cả 2 vế cho 100,ta có:
(a,bc+ab,c) x 100=21,12 x 100
=>abc+abc0=2112
=>abc+abc x 10=2112
=>abc x (1+10)=2112
=>abc x 11=2112
=>abc =2112:11=192
Vậy abc=192
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Ta có:a,bc+ab,c=21,12
a,bc+a,bc x 10=21,12
a,bc x(10+1)=21,12
a,bc x11=21,12
a,bc=21,12:11
a,bc=1,92
Vậy abc=192
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Ta có \(a,bc+ab,c=21,12\)
Ta nhận thấy \(c=2\) \(\Rightarrow a,b2+ab,2=21,12\)
Suy ra \(b=9\) \(\Rightarrow a,92+a9,2=21,12\)
Suy ra \(a=1\) \(\Rightarrow1,92+19,2=21,12\)
Vậy a=1, b=9, c=2
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Bài 1:a)abc1-1abc=7506
(=)(abcx10+1)-(1000+abc)=7506
(=)abcx10+1-1000-abc=7506
(=)(abcx10-abc)+1-1000=7506
(=)abcx9=7506+1000-1
(=)abcx9=8505=)abc=8505:9=945
=)a=9,b=4,c=5
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ab,c gấp a,bc 10 lần.Ta có sơ đồ:
a,bc:!--------!
ab,c:!--------!---------!---------!----------!---------!----------!----------!----------!----------!-----------!) 21,12
a,bc là:21,12:(10+1)=1,92
ab,c là:21,12-1,92=19,2
Đáp số:a,bc:1,92
ab,c:19,2
abc = 192
a= 1
b= 9
c= 2
Nha bạn hehe