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\(a,25\%x=42,6-3,28\\ \Leftrightarrow\dfrac{1}{4}x=39,32\\ \Leftrightarrow x=157,28\)
\(b,x:40\%=7,25+6,75\\ \Leftrightarrow x:40\%=14\\ \Leftrightarrow x=5,6\)
\(c,\dfrac{7011}{25}:\left(x-42,6\right)=117,14-47,03\\ \Leftrightarrow\dfrac{7011}{25}:\left(x-42,6\right)=70,11\\ \Leftrightarrow x-42,6=4\\ \Leftrightarrow x=46,6\)
\(d,0,3\left(x+\dfrac{1}{3}\right)=\dfrac{1}{2}\cdot\left(0,81:27\right)\\ \Leftrightarrow0,3\left(x+\dfrac{1}{3}\right)=0,015\\ \Leftrightarrow x+\dfrac{1}{3}=0,05\\ \Leftrightarrow x=-\dfrac{17}{60}\)
(x+0,2)+(x+0.7)+...+(x+4,7)=65,5
có số x là:(4,7-0,2):0,5+1=10(số)
=> x.10+(0,2+0,7+...+4,7)=65,5
=>x.10+24,5=65,5
=>x.10=65,5-24,5
=>x.10=41
=>x =41:10
x=4,1
vậy x=1 tí nữa mik làm tiếp cho
(x+0,2)+(x+0.7)+...+(x+4,7)=65,5
có số x là:(4,7-0,2):0,5+1=10(số)
=> x.10+(0,2+0,7+...+4,7)=65,5
=>x.10+24,5=65,5
=>x.10=65,5-24,5
=>x.10=41
=>x =41:10
x=4,1
vậy x=1
\(\dfrac{7011}{25}:\left(x-42.6\right).15=13\)
\(\Rightarrow\dfrac{7011}{\dfrac{25}{\left(x-42,6\right)}}.0,15=13\)
\(\Rightarrow\dfrac{280,44}{\left(x-42,6\right)}.0,15=13\)
\(x-\left(280,44-42,6\right)\)
\(x=237.8+86,7\)
\(x=324,54\)
\(\)Vậy x=324,54
b.
\(7,2-\left(x+3,75:2,1\right):1,9=5,2\)
\(\Rightarrow7,2+\dfrac{-\left(x-\dfrac{3,75}{2,1}\right)}{1,9}=5,2\)
\(7,2+\dfrac{-\left(x-1,8\right)}{1,9}=5,2\)
`-(x-42,6+47,03): 27/4=0`
`-[x-(42,6-47,03)]=0`
`-(x+4,43)=0`
`x+4,43=0`
`x=-4,43`
\(\left(\frac{1}{4}.x-\frac{1}{8}\right).\frac{3}{4}=\frac{1}{4}\)
<=> \(\frac{1}{4}x-\frac{1}{8}=\frac{1}{3}\)
<=> \(\frac{1}{4}x=\frac{11}{24}\)
<=> \(x=\frac{11}{6}\)
\(\frac{1}{2}:x+\frac{3}{4}=1\frac{2}{3}\)
<=> \(\frac{1}{2}:x+\frac{3}{4}=\frac{5}{3}\)
<=> \(\frac{x}{2}=\frac{11}{12}\)
=> \(12x=22\)
<=> \(x=\frac{11}{6}\)
\(2x-\frac{3}{7}=\frac{2}{7}+\frac{3}{4}\)
<=> \(2x-\frac{3}{7}=\frac{29}{28}\)
<=> \(2x=\frac{41}{28}\)
<=> \(x=\frac{41}{56}\)
\(25\%.x=42,6-3,28\)
<=> \(0,25x=39,32\)
<=> \(x=157,28\)
\(\frac{15}{12}.x+\frac{3}{7}.x=\frac{6}{5}-\frac{1}{2}\)
<=> \(\left(\frac{15}{12}+\frac{3}{7}\right).x=\frac{7}{10}\)
<=> \(\frac{47}{28}.x=\frac{7}{10}\)
<=> \(x=\frac{98}{235}\)
\(\left(x-\frac{1}{2}\right).\frac{5}{3}=\frac{7}{4}-\frac{1}{2}\)
<=> \(\left(x-\frac{1}{2}\right).\frac{5}{3}=\frac{5}{4}\)
<=> \(x-\frac{1}{2}=\frac{3}{4}\)
<=> \(x=\frac{5}{4}\)
học tốt
a/ \(\left|x\right|=3\dfrac{1}{5}\)
\(\Leftrightarrow\left[{}\begin{matrix}x=3\dfrac{1}{5}\\x=-3\dfrac{1}{5}\end{matrix}\right.\)
Vậy ............
b/ \(\left|x\right|=-2,7\) \(\Leftrightarrow x\in\varnothing\)
Vậy ....
c/ \(\left|x-3,5\right|=5\)
\(\Leftrightarrow\left[{}\begin{matrix}x-3,5=5\\x-3,5=-5\end{matrix}\right.\)
\(\Leftrightarrow\left[{}\begin{matrix}x=8,5\\x=-1,5\end{matrix}\right.\)
Vậy ....
a. \(\left|x\right|=\dfrac{31}{5}\) \(\Rightarrow\left[{}\begin{matrix}x=\dfrac{31}{5}\\x=\dfrac{-31}{5}\end{matrix}\right.\)
Vậy....
b. \(\left|x\right|=-2,7\)
không có giá trị nào thỏa mãn vì \(\left|x\right|\ge0\) với \(\forall x\in Q\)
c. \(\left|x-3,5\right|=5\)
\(\Rightarrow\left[{}\begin{matrix}x-3,5=5\\x-3,5=-5\end{matrix}\right.\) \(\Rightarrow\left[{}\begin{matrix}x=8,5\\x=-1,5\end{matrix}\right.\)
Vậy......
a) \(x.3,9+x.0,1=2,7\)
x . (3,9+0,1) = 2,7
x . 4 = 2,7
x = 2,7 : 4
x = 0,675
b) x.3 + x.5 = 9,84
x . ( 3+5) = 9,84
x . 8 = 9,84
x = 9,84 : 8
x = 1,23
c) 12,3:x - 4,5:x = 15
(12,3-4,5) : x = 15
7,8 : x = 15
x = 7,8 : 15
x = 0,52
d) 7.x - 2.x = 1,85
(7-2) . x = 1,85
5 . x = 1,85
x = 1,85 : 5
x = 0,37
\(a,\frac{7011}{25}:\left(x-42,6\right)=117,14-47,03\)
\(=\frac{7011}{25}:\left(x-42,6\right)=70,11\)
\(\Rightarrow\left(x-42,6\right)=\frac{7011}{25}:70,11\)
\(\Rightarrow x=4+42,6\)
\(\Rightarrow x=46,6\)
b ko co bai b a