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1 a= 300.3=900
b= 204.(-8).5
= (-1632).5=(-8160)
2
A= 365.72.(-11).(-10)
B= (-714).(-232).(-72)
A= 26280.110
B= 165648.(-72)
A= 2890800
B= (-11926656) A lớn hơn B
3 a 2x-5=15
2x= 15+5
2x= 20
x = 20:2
x=10
a) \(\left(2x+10\right)\left(x^2-9\right)=0\)
\(\Leftrightarrow\)\(2\left(x+5\right)\left(x^2-3x+3x-9\right)=0\)
\(\Leftrightarrow\)\(2\left(x+5\right)\left(x-3\right)\left(x+3\right)=0\)
\(\Leftrightarrow\)\(x+5=0\) \(\Leftrightarrow\)\(x=-5\)
hoặc \(x-3=0\) hoặc \(x=3\)
hoặc \(x+3=0\) hoặc \(x=-3\)
Vậy....
a) -3(x-4)+5(x-1)=-7
=>-3x+12+5x-5=-7
=>2x+7=-7
=>2x=-14=>x=-7
b) -4./x-8/+12=0
=>/x-8/=3
=>x-8=3 hoặc -3
(tự tính)
c) =>x mũ 2 -9<0 hoăc x mũ 2 +1 <0
Mà x mũ 2+1>0 => x mũ 2+1 ko thể <0
=>x mũ 2 -9< 0
=>x mũ 2 <9
=>x<3 hoặc x> -3
Mk làm nhầm bạn sửa dấu > và < thành dấu bằng là đc nhé sorry
Bài 1:tìm x thuộc Z
a)x.(x-1)=0
\(\Leftrightarrow\left[\begin{matrix}x=0\\x-1=0\end{matrix}\right.\Leftrightarrow\left[\begin{matrix}x=0\\x=1\end{matrix}\right.\)
Vậy: \(x=0;1\)
b)(x-3).(x+4)=0
\(\Leftrightarrow\left[\begin{matrix}x-3=0\\x+4=0\end{matrix}\right.\Leftrightarrow\left[\begin{matrix}x=3\\x=-4\end{matrix}\right.\)
Vậy: \(x=3;-4\)
c)(2x-4).(x+2)=0
\(\Leftrightarrow2\left(x-2\right).\left(x+2\right)=0\)
\(\Leftrightarrow\left[\begin{matrix}x-2=0\\x+2=0\end{matrix}\right.\Leftrightarrow\left[\begin{matrix}x=2\\x=-2\end{matrix}\right.\)
Vậy: \(x=2;-2\)
d)(x+1)^2.(x-2)^2=0
\(\Leftrightarrow\left[\begin{matrix}x+1=0\\x-2=0\end{matrix}\right.\Leftrightarrow\left[\begin{matrix}x=-1\\x=2\end{matrix}\right.\)
Vậy: \(x=-1;2\)
e) x(x+1).(x+2)^2.(x+3)^3=0
\(\Leftrightarrow\left[\begin{matrix}x=0\\x+1=0\\x+2=0\\x+3=0\end{matrix}\right.\Leftrightarrow\left[\begin{matrix}x=0\\x=-1\\x=-2\\x=-3\end{matrix}\right.\)
Vậy: \(x=0;-1;-2;-3\)
f)(x-9)^5.(x-5)^8=0
\(\Leftrightarrow\left[\begin{matrix}x-9=0\\x-5=0\end{matrix}\right.\Leftrightarrow\left[\begin{matrix}x=9\\x=5\end{matrix}\right.\)
Vậy: \(x=9;5\)
g)x(x+100)^10.(x+2000)^20.(x+300)^300=0
\(\Leftrightarrow\left[\begin{matrix}x=0\\x+100=0\\x+200=0\\x+300=0\end{matrix}\right.\Leftrightarrow\left[\begin{matrix}x=0\\x=-100\\x=-200\\x=-300\end{matrix}\right.\)
Vậy: \(x=0;-100;-200;-300\)
h)(x-2)^2=0
\(\Leftrightarrow x-2=0\)
\(\Leftrightarrow x=2\)
Vậy: \(x=2\)
\(a,80-\left(10x-5\right)=45\\ \Rightarrow80-10x+5=45\\ \Rightarrow-10x=-40\\ \Rightarrow x=4\)
\(b,\left(x+1\right)\left(x-2\right)=0\\ \Rightarrow\left[{}\begin{matrix}x+1=0\\x-2=0\end{matrix}\right.\\ \Rightarrow\left[{}\begin{matrix}x=-1\\x=2\end{matrix}\right.\)
\(c,\left|5+5x\right|=2^2.5\\ \Rightarrow\left|5+5x\right|=20\\ \Rightarrow\left[{}\begin{matrix}5+5x=20\\5+5x=-20\end{matrix}\right.\\ \Rightarrow\left[{}\begin{matrix}5x=15\\5x=-25\end{matrix}\right.\\ \Rightarrow\left[{}\begin{matrix}x=3\\x=-5\end{matrix}\right.\)
\(d,-10-\left(-5\right)+\left(3-x\right)=-8\\ \Rightarrow-10+5+3-x=-8\\ \Rightarrow-x=-6\\ \Rightarrow x=6\)
a) 80-(10x-5)=45
=> 80 - 10 x + 5 =45
=>-10x = -40
=>x=4
b)(x+1)×(x-2)=0
\(\Rightarrow\left[{}\begin{matrix}x+1=0\\x=2+0\end{matrix}\right.\Rightarrow\left[{}\begin{matrix}x=-1\\x=2\end{matrix}\right.\)
c) |5+5x|=2^2×5
=>|5+5x|=20
\(\Rightarrow\left[{}\begin{matrix}5+5x=-20\\5+5x=20\end{matrix}\right.\Rightarrow\left[{}\begin{matrix}x=-5\\x=3\end{matrix}\right.\)
d) -10-(-5)+(3-x)=-8
=>-10+5 +3-x=-8
=>2+x=8
=>x=6
a) \(x^3=-8\)
\(\Rightarrow x=-2\)
b) \(x^{10}-x^8=0\)
\(\Leftrightarrow x^{10}=x^8\)
\(\Rightarrow x=1\)
\(\Rightarrow x=-1\)
\(\Rightarrow x=0\)
c) \(\left(x+1\right)^5-\left(x+1\right)^2=0\)
\(\Leftrightarrow\left(x+1\right)^5=\left(x+1\right)^2\)
\(thay\) x vào thì ta sẽ có giá trị thỏa mãn.
d) \(2^5-4=2^n-1\)
\(\Rightarrow32-4=2^{n-1}\)
\(\Rightarrow28=2^{n-1}\)
\(\leftrightarrow\) \(n\) không có giá trị thỏa mãn
a) x3 = -8
=> x = -2
b) x10 - x8 = 0
x10 = x8
=> x = 1 ; x = -1 ; x = 0