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DD
10 tháng 9 2017
\(A=4y^2-\left(x^2-10x+25\right)\)
\(A=4y^2-\left(x-5\right)^2\)
\(A=\left(2y-x-5\right)\left(2y+x-5\right)\)
\(B=\left(x-4\right)^4-\left(x+a\right)^4\)
\(B=\left(\left(x-4\right)^2\right)^2-\left(\left(x+a\right)^2\right)^2\)
\(B=\left(\left(x-4\right)^2-\left(x+a\right)^2\right)\left(\left(x-4\right)^2+\left(x+a\right)^2\right)\)
\(B=\left(x-4\right)\left(x+a\right)\left(\left(x-4\right)^2+\left(x+a\right)^2\right)\)
\(C=\left(x^2+x\right)^2+2\left(x^2+x\right)+1\)
\(C=\left(x^2+x\right)\left(x^2+x+2\right)+1\)
28 tháng 7 2022
1: \(=a\left(x+y\right)-4\left(x+y\right)=\left(x+y\right)\left(a-4\right)\)
2: \(=x\left(x+b\right)+a\left(x+b\right)=\left(x+b\right)\left(x+q\right)\)
3: \(=a\left(x+1\right)-b\left(x+1\right)+c\left(x+1\right)\)
\(=\left(x+1\right)\left(a-b+c\right)\)
6: \(=\left(x-y\right)^2-4=\left(x-y-2\right)\left(x-y+2\right)\)
HH
21 tháng 6 2018
Bài 1:
a) \(x^2-2xy-25+y^2\) (Sửa đề)
\(=x^2-2xy+y^2-25\)
\(=\left(x-y\right)^2-5^2\)
\(=\left(x-y-5\right)\left(x-y+5\right)\)
Vậy ...
b) \(x\left(x-1\right)+y\left(1-x\right)\)
\(=x\left(x-1\right)-y\left(x-1\right)\)
\(=\left(x-1\right)\left(x-y\right)\)
Vậy ...
c) \(7x+7y-\left(x+y\right)\) (Sửa đề)
\(=7\left(x+y\right)-\left(x+y\right)\)
\(=\left(x+y\right)\left(7-1\right)\)
\(=6\left(x+y\right)\)
Vậy ...
d) \(x^4+y^4\)
\(=\left(x^2\right)^2+\left(y^2\right)^2\)
\(=\left(x^2+y^2\right)^2-2x^2y^2\)
\(=\left(x^2+y^2-\sqrt{2}xy\right)\left(x^2+y^2+\sqrt{2}xy\right)\)
Vậy ...
12 tháng 9 2020
a) x2 - y2 + 4x + 4
= ( x2 + 4x + 4 ) - y2
= ( x + 2 )2 - y2
= ( x + 2 - y )( x + 2 + y )
b) x2 - 2xy + y2 - 1
= ( x2 - 2xy + y2 ) - 1
= ( x - y )2 - 12
= ( x - y - 1 )( x - y + 1 )
c) x2 - 2xy + y2 - 4
= ( x2 - 2xy + y2 ) - 4
= ( x - y )2 - 22
= ( x - y - 2 )( x - y + 2 )
d) x2 - 2xy + y2 - z2
= ( x2 - 2xy + y2 ) - z2
= ( x - y )2 - z2
= ( x - y - z )( x - y + z )
e) 25 - x2 + 4xy - 4y2
= 25 - ( x2 - 4xy + 4y2 )
= 52 - ( x - 2y )2
= ( 5 - x + 2y )( 5 + x - 2y )
f) x2 + y2 - 2xy - 4z2
= ( x2 - 2xy + y2 ) - 4z2
= ( x - y )2 - ( 2z )2
= ( x - y - 2z )( x - y + 2z )
N
3
XO
21 tháng 9 2020
a) x2 - y2 - 4x + 4y
= (x2 - 4x + 4) - (y2 - 4y + 4)
= (x - 2)2 - (y - 2)2
= (x - 2 - y + 2)(x - 2 + y - 2)
= (x - y)(x + y - 4)
b) (xy + 4)2 - 4(x + y)2
= (xy + 4)2 - [2(x + y)]2
= (xy + 4)2 - (2x + 2y)2
= (xy + 4 - 2x - 2y)(xy + 4 + 2x + 2y)
c) 25 - x2 + 2xy - y2
= 25 - (x2 - 2xy + y2)
= 52 - (x - y)2
=> (5 - x + y)(5 + x - y)
G
21 tháng 9 2020
a) \(x^2-y^2-4x+4y=\left(x^2-y^2\right)-\left(4x-4y\right)=\left(x+y\right)\left(x-y\right)-4\left(x-y\right)\)
\(=\left(x-y\right)\left(x+y-4\right)\)
b) \(\left(xy+4\right)^2-4\left(x+y\right)^2=\left(xy+4\right)^2-\left(2x+2y\right)^2=\left(xy+4+2x+2y\right)\left(xy+4-2x-2y\right)\)
c) \(25-x^2+2xy-y^2=25-\left(x^2-2xy+y^2\right)=5^2-\left(x-y\right)^2=\left(5+x-y\right)\left(5-x+y\right)\)
PT
3
28 tháng 8 2023
`#040911`
`a)`
`x^2 + y^2 + 2xy - 25`
`= (x^2 + 2xy + y^2) - 25`
`= [ (x)^2 + 2*x*y + (y)^2] - 5^2`
`= (x + y)^2 - 5^2`
`= (x + y - 5)(x + y + 5)`
`b)`
`x^2 + 2x - 15`
`= x^2 + 5x - 3x - 15`
`= (x^2 + 5x) - (3x + 15)`
`= x(x + 5) - 3(x + 5)`
`= (x - 3)(x + 5)`
`c)`
`x^2 - x - 2`
`= x^2 - 2x + x - 2`
`= (x^2 - 2x) + (x - 2)`
`= x(x - 2) + (x - 2)`
`= (x + 1)(x - 2)`
`d)`
`3x^2 - 11x + 6`
`= 3x^2 - 9x - 2x + 6`
`= (3x^2 - 9x) - (2x - 6)`
`= 3x(x - 3) - 2(x - 3)`
`= (3x - 2)(x - 3)`
28 tháng 8 2023
`a, (x+y)^2-25 = (x+y+5)(x+y-5)`.
`b, x^2+2x-15 = (x+1)^2-16 = (x-3)(x+5)`.
`c, x^2-x-2=(x-2)(x+1)`
`d, 3x^2-11x+6 = (3x-2)(x-3)`.