Hãy nhập câu hỏi của bạn vào đây, nếu là tài khoản VIP, bạn sẽ được ưu tiên trả lời.
a) \(BaCl_2+LiOH\rightarrow\text{không phản ứng}\)
b) \(CH_3COONa+NaOH\xrightarrow[CaO]{t^\circ}Na_2CO_3+CH_4\uparrow\)
Ion RG: \(CH_3COO^-+OH^-\xrightarrow[CaO]{t^\circ}CO_3^{2-}+CH_4\uparrow\)
c) \(CaCO_3+2HNO_3\rightarrow Ca\left(NO_3\right)_2+H_2O+CO_2\uparrow\)
Ion RG: \(CaCO_3+2H^+\rightarrow Ca^{2+}+H_2O+CO_2\uparrow\)
d) \(3Cu+8HCl+8NaNO_3\rightarrow3Cu\left(NO_3\right)_2+8HCl+2NO\uparrow+4H_2O\)
Ion RG: \(3Cu+8H^++2NO_3^-\rightarrow3Cu^{2+}+2NO\uparrow+4H_2O\)
e) \(NH_4Cl+NaNO_2\xrightarrow[]{t^\circ}NaCl+N_2\uparrow+2H_2O\)
Ion RG: \(NH_4^++NO_2^-\rightarrow N_2\uparrow+2H_2O\)
f) \(2NaCl+2H_2O\xrightarrow[cmn]{đpdd}2NaOH+Cl_2\uparrow+H_2\uparrow\)
Ion RG: \(2Cl^-+2H_2O\xrightarrow[cmn]{đpdd}2OH^-+Cl_2\uparrow+H_2\uparrow\)
Câu 1 :
\(a.\)
\(CaCl_2+2AgNO_3\rightarrow Ca\left(NO_3\right)_2+2AgCl\)
\(Ag^++Cl^-\rightarrow AgCl\)
\(b.\)
\(c.\)
\(Fe_2\left(SO_4\right)_3+6KOH\rightarrow2Fe\left(OH\right)_3+3K_2SO_4\)
\(Fe^{3+}+3OH^-\rightarrow Fe\left(OH\right)_3\)
\(d.\)
\(Na_2SO_3+2HCl\rightarrow2NaCl+SO_2+H_2O\)
\(SO_3^{2-}+2H^+\rightarrow SO_2+H_2O\)
Câu 2 :
\(a.\)
\(MgCl_2+Na_2CO_3\rightarrow MgCO_3+2NaCl\)
\(Mg^{2+}+CO_3^{2-}\rightarrow MgCO_3\)
\(b.\)
\(c.\)
\(FeCl_3+3KOH\rightarrow Fe\left(OH\right)_3+3NaCl\)
\(Fe^{3+}+3OH^-\rightarrow Fe\left(OH\right)_3\)
\(d.\)
\(Na_2CO_3+H_2SO_4\rightarrow Na_2SO_4+CO_2+H_2O\)
\(CO_3^{2-}+2H^+\rightarrow CO_2+H_2O\)
Những câu còn lại em tách ra 1 2 bài gì đó đi nha !
(1) 2K3PO4 + 3Ba(NO3)2 → Ba3(PO4)2 ↓ + 6KNO3
Ba2+ + 2PO43- → Ba3(PO4)2 ↓
(2) 2Na3PO4 + 3CaCl2 → Ca3(PO4)2 ↓ + 6NaCl
Ca2+ + 2PO43- → Ca3(PO4)2 ↓
(3) Ca(H2PO4)2 + Ca(OH)2 → 2CaHPO4 + 2H2O
H2PO4- + OH- → HPO42- + H2O
(4) 2(NH4)3PO4 + 3Ba(OH)2 → Ba3(PO4)2 ↓ + 6NH3 ↑ + 6H2O
6NH4+ + 2PO43- + 3Ba2+ + 6OH- → Ba3(PO4)2 ↓ + 6NH3 ↑ + 6H2O
Câu 1:
a, \(ZnS+2HCl\rightarrow ZnCl_2+H_2S\)
b, \(Al\left(NO_3\right)_3+3NaOH\rightarrow Al\left(OH\right)_3+3NaNO_3\)
c, \(Cu\left(OH\right)_2+2HCl\rightarrow CuCl_2+2H_2O\)
d, \(Ca\left(OH\right)_2+Na_2CO_3\rightarrow CaCO_{3\downarrow}+2NaOH\)
e, \(BaCl_2+Na_2SO_4\rightarrow2NaCl+BaSO_{4\downarrow}\)
Bạn tham khảo nhé!