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\(\frac{4}{5}\)+ \(\frac{1}{5}\): \(\frac{-2}{15}\)= \(\frac{4}{5}\)+ \(\frac{1}{5}\)* \(\frac{-15}{2}\)=\(\frac{4}{5}\) + \(\frac{-3}{2}\)= \(\frac{-7}{10}\)
b = \(\frac{-7}{12}\). (\(\frac{3}{11}\)+ \(\frac{-14}{11}\)) + \(\frac{5}{6}\)= \(\frac{-7}{12}\). (-1) + \(\frac{5}{6}\)= \(\frac{7}{12}\)+ \(\frac{10}{12}\)= \(\frac{17}{12}\)
cái chữ này cj nhìn khó hiểu quá nên em thông cảm nếu muốn bt đáp án thì viết rõ ra đc chứ^^
a) \(\dfrac{2}{3}x-\dfrac{1}{2}=\dfrac{1}{10}\)
\(\dfrac{2}{3}x=\dfrac{1}{10}+\dfrac{1}{2}=\dfrac{3}{5}\)
\(x=\dfrac{3}{5}:\dfrac{2}{3}=\dfrac{9}{10}\)
b) \(\dfrac{39}{7}:x=13\)
\(x=\dfrac{\dfrac{39}{7}}{13}=\dfrac{3}{7}\)
c) \(\left(\dfrac{14}{5}x-50\right):\dfrac{2}{3}=51\)
\(\dfrac{14}{5}x-50=51\cdot\dfrac{2}{3}=34\)
\(\dfrac{14}{5}x=34+50=84\)
\(x=\dfrac{84}{\dfrac{14}{5}}=30\)
d) \(\left(x+\dfrac{1}{2}\right)\left(\dfrac{2}{3}-2x\right)=0\)
\(\Leftrightarrow\left[{}\begin{matrix}x+\dfrac{1}{2}=0\\\dfrac{2}{3}-2x=0\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=-\dfrac{1}{2}\\x=\dfrac{1}{3}\end{matrix}\right.\)
e) \(\dfrac{2}{3}x-\dfrac{1}{2}x=\dfrac{5}{12}\)
\(\dfrac{1}{6}x=\dfrac{5}{12}\)
\(x=\dfrac{5}{12}:\dfrac{1}{6}=\dfrac{5}{2}\)
g) \(\left(x\cdot\dfrac{44}{7}+\dfrac{3}{7}\right)\dfrac{11}{5}-\dfrac{3}{7}=-2\)
\(\left(x\cdot\dfrac{44}{7}+\dfrac{3}{7}\right)\cdot\dfrac{11}{5}=-2+\dfrac{3}{7}=-\dfrac{11}{7}\)
\(x\cdot\dfrac{44}{7}+\dfrac{3}{7}=-\dfrac{11}{7}:\dfrac{11}{5}=-\dfrac{5}{7}\)
\(\dfrac{44}{7}x=-\dfrac{5}{7}-\dfrac{3}{7}=-\dfrac{8}{7}\)
\(x=-\dfrac{8}{7}:\dfrac{44}{7}=-\dfrac{2}{11}\)
h) \(\dfrac{13}{4}x+\left(-\dfrac{7}{6}\right)x-\dfrac{5}{3}=\dfrac{5}{12}\)
\(\dfrac{25}{12}x-\dfrac{5}{3}=\dfrac{5}{12}\)
\(\dfrac{25}{12}x=\dfrac{5}{12}+\dfrac{5}{3}=\dfrac{25}{12}\)
\(x=1\)
Mỏi tay woa bn làm nốt nha!!
a.
\(\frac{5}{24}+x=\frac{7}{12}\)
\(x=\frac{7}{12}-\frac{5}{24}\)
\(x=\frac{3}{8}\)
b.
\(x-\frac{3}{4}=\frac{1}{2}\)
\(x=\frac{1}{2}+\frac{3}{4}\)
\(x=\frac{5}{4}\)
Trả lời:
a, \(\frac{5}{24}+x=\frac{7}{12}\)
\(\Rightarrow x=\frac{7}{12}-\frac{5}{24}\)
\(\Rightarrow x=\frac{3}{8}\)
b, \(x-\frac{3}{4}=\frac{1}{2}\)
\(\Rightarrow x=\frac{1}{2}+\frac{3}{4}\)
\(\Rightarrow x=\frac{5}{4}\)
c, \(\left(\frac{2}{7}x+\frac{3}{7}\right)\div2\frac{1}{5}-\frac{3}{7}=1\)
\(\Rightarrow\left(\frac{2}{7}x+\frac{3}{7}\right)\div\frac{11}{5}-\frac{3}{7}=1\)
\(\Rightarrow\left(\frac{2}{7}x+\frac{3}{7}\right)\div\frac{11}{5}=1+\frac{3}{7}\)
\(\Rightarrow\left(\frac{2}{7}x+\frac{3}{7}\right).\frac{5}{11}=\frac{10}{7}\)
\(\Rightarrow\frac{2}{7}x+\frac{3}{7}=\frac{10}{7}\div\frac{5}{11}\)
\(\Rightarrow\frac{2}{7}x+\frac{3}{7}=\frac{22}{7}\)
\(\Rightarrow\frac{2}{7}x=\frac{22}{7}-\frac{3}{7}\)
\(\Rightarrow\frac{2}{7}x=\frac{19}{7}\)
\(\Rightarrow x=\frac{19}{7}\div\frac{2}{7}\)
\(\Rightarrow x=\frac{19}{2}\)