\(\dfrac{-6}{20}\)

b) \(\dfrac{-31}{36}:\dfrac{37}...">

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a)\(\left(-5\right).-\dfrac{6}{20}=\dfrac{3}{2}\)

b)\(-\dfrac{31}{36}:\dfrac{37}{-72}=\dfrac{62}{37}\)

c)\(-\dfrac{5}{17}:\left(-15\right)=\dfrac{1}{51}\)

d)\(-\dfrac{9}{34}\times\dfrac{17}{4}=-\dfrac{9}{8}\)

e)\(1\dfrac{4}{5}:\left(-\dfrac{3}{4}\right)=\dfrac{9}{5}:\left(-\dfrac{3}{4}\right)=-\dfrac{12}{5}\)

27 tháng 7 2022

`(-5) . (-6)/20 = 5 . 3/10 = (5.3)/10 = 15/10 =3/2`

`(-31)/36 : 27/(-72) = (-31)/36 . (-72)/37 = 31/36 . 72/37=  62/37`

`(-5)/17 : (-15) = (-5)/17 . (-1/15) =5/17 . 1/15 = 1/52`

`(-9)/34 . 17/4 = -9/8`

`1 4/5 : (-3/4) = 9/5 : (-3/4) = 9/5 . (-4/3) = -12/5`

11 tháng 9 2018

dễ mà bạn

29 tháng 7 2018

A)0,25:(10,3-9,8)-3/4

=1/4:(103/10-49/5)-3/4

=1/4:1/2-3/4

=1/2-3/4

=2/4-3/4

=-1/4

B)-5/9.13/28-13/28.4/9

=-5/9-4/9.13/28

=-1.13/28

=-13/28

c)6/7+5/8:5-3/16

=6/7+1/8-3/16

=55/56-3/16

=89/112

d)-5/7.2/11+-5/7.9/11+1/5/7

=-5/7.(2/11+9/11)+12/7

=-5/7.1+12/7

=-5/7+12/7

=1

e)-7/12-8/15+11/20

=-67/60+11/20

=-17/30

f)-17/25.20/33+-17/25.13/33+-3/25

=-17/25.(20/33+13/33)-3/25

=-17/25.1-3/25

=-17/25-3/25

=-4/5

CHÚC BẠN HỌC TỐT...............

NẾU ĐÚNG THÌ TICK CHO MK VỚI NHA HELLO HELLO..........

hihihihihihi

Bài 1: 

a: \(=17+\dfrac{2}{31}-\dfrac{15}{17}-6-\dfrac{2}{31}=11-\dfrac{15}{17}=\dfrac{172}{17}\)

b: \(=31+\dfrac{6}{13}+5+\dfrac{9}{41}-36-\dfrac{9}{41}-36-\dfrac{6}{13}\)

=36

c: \(=27+\dfrac{51}{59}-7-\dfrac{51}{59}+\dfrac{1}{3}=20+\dfrac{1}{3}=\dfrac{61}{3}\)

10 tháng 8 2018

\(A=17\dfrac{2}{31}-\left(\dfrac{15}{17}+6\dfrac{2}{31}\right)=17\dfrac{2}{31}-\dfrac{15}{17}-6\dfrac{2}{31}\)

\(=11-\dfrac{15}{17}=\dfrac{172}{17}\)

\(B=\left(31\dfrac{6}{13}+5\dfrac{9}{41}\right)-36\dfrac{6}{12}=36\dfrac{363}{533}-36\dfrac{6}{12}=\dfrac{193}{1066}\)

\(C=27\dfrac{51}{59}-\left(7\dfrac{51}{59}-\dfrac{1}{3}\right)=27\dfrac{51}{59}-7\dfrac{51}{59}+\dfrac{1}{3}=20+\dfrac{1}{3}=\dfrac{61}{3}\)

10 tháng 8 2018

\(A=17\dfrac{2}{31}-\left(\dfrac{15}{17}+6\dfrac{2}{31}\right)=17\dfrac{2}{31}-\dfrac{15}{17}-6\dfrac{2}{31}\)

\(=\left(17\dfrac{2}{31}-6\dfrac{2}{31}\right)-\dfrac{15}{17}=11-\dfrac{15}{17}=\dfrac{172}{17}\)

\(B=\left(31\dfrac{6}{13}+5\dfrac{9}{41}\right)-36\dfrac{6}{12}=36\dfrac{363}{533}-36\dfrac{1}{2}=\dfrac{193}{1066}\) (Casio :>)

\(C=27\dfrac{51}{59}-\left(7\dfrac{51}{59}-\dfrac{1}{3}\right)=27\dfrac{51}{59}-7\dfrac{51}{59}+\dfrac{1}{3}\)

\(=20+\dfrac{1}{3}=\dfrac{61}{3}\)

26 tháng 7 2018

a) \(\dfrac{x}{48}=-\dfrac{4}{7}\Rightarrow x=-\dfrac{192}{7}\)

b) \(\left(x+\dfrac{4}{5}\right)-\dfrac{2}{5}=\dfrac{3}{5}\Rightarrow x+\dfrac{4}{5}=1\)

\(\Rightarrow x=\dfrac{1}{5}\)

c) \(2\left|x-1\right|^2=72\Rightarrow\left|x-1\right|^2=36\)

\(\Rightarrow\left|x-1\right|=6\)

TH1: x - 1 = -6 => x = -5

TH2: x - 1 = 6 => x = 7

e) \(\dfrac{x}{2,5}=\dfrac{4}{5}\Rightarrow x=2\)

f) | x - 2 | = 1 + 4 = 5

TH1: x - 2 = -5 => x = -3

TH2: x - 2 = 5 => x = 7

26 tháng 7 2018

a) \(\dfrac{x}{48}=\dfrac{-4}{7}\)

⇒ x.7=48.(-4)

7x = -192

x=\(\dfrac{-192}{7}\) Vậy x=\(\dfrac{-192}{7}\)

b) \(\left(x+\dfrac{4}{5}\right)-\dfrac{2}{5}=\dfrac{3}{5}\)

\(\left(x+\dfrac{4}{5}\right)=\dfrac{3}{5}+\dfrac{2}{5}\)

\(x+\dfrac{4}{5}=1\)

\(x=1-\dfrac{4}{5}\)

\(x=\dfrac{1}{5}\)

c) chưa từng gặp dạng với giá trị tuyệt đối sory

d) \(\dfrac{1}{6}x-\dfrac{2}{3}=2\)

\(\dfrac{1}{6}x=2+\dfrac{2}{3}\)

\(\dfrac{1}{6}x=\dfrac{8}{3}\)

\(x=\dfrac{8}{3}:\dfrac{1}{6}\)

\(x=16\)

e) \(\dfrac{x}{2,5}=\dfrac{4}{5}\)

=> x.5 = 4.2,5

5x=10

x=10:5

x=2

f) |x-2|-4=1

|x-2|=1+4

|x-2|=5

=>\(\left[{}\begin{matrix}x-2=5\\x-2=-5\end{matrix}\right.\) =>\(\left[{}\begin{matrix}x=5+2\\x=-5+2\end{matrix}\right.\) =>\(\left[{}\begin{matrix}x=7\\x=-3\end{matrix}\right.\)

đôi khi cũng có sai sót , hãy xem lại thật kĩ

2 tháng 8 2018

a, 1/3-3/4+3/5+1/4-2/9-1/36+1/15

=(1/3+3/5+1/15)-(3/4-1/4+2/9+1/36)

=1 - 3/4

=1/4

b, 3-1/4+2/3-5-1/3+6/5-6+7/4-3/2

=(3-5-6)-(1/4-7/4)+(2/3-1/3)+(6/5-3/2)

=-8 +3/2 +1/3 -3/10

=-97/15

27 tháng 7 2018

B1

a. = 7/3. ( 37/5 - 32/5)

= 7/3 . 1

= 7/3

humPhần b có gì đó sai sao lại có 3:+

c. = 4 + 6 - 3 + 5

= 12

d. = -5/21 : -19/21 : 4/5

= 25/76

B2

a. 1/4 : x =1/2 - 3/4

x = -1/4

x = 1/4 : -1/4

x = -1

b. 2 . | 2x - 3 | = 4 - (-8)

2 . | 2x - 3| = 12

| 2x - 3 | = 12:2

| 2x - 3 | = 6

| x - 3 | = 6:2

| x - 3 | = 3

=> x - 3 = +- 3

* x - 3 = 3

x = 6

* x - 3 = -3

x = 0

Chúc bạn vui vẻ yeu

28 tháng 7 2018

b. = 3 : 9/4 + 1/9 .6

= 4/3 + 2/3

= 2

3 tháng 8 2018

\(a)\dfrac{3}{4}+\dfrac{6}{12}-\dfrac{5}{24}\)

\(=\dfrac{18}{24}+\dfrac{12}{24}+\left(-\dfrac{5}{24}\right)\)

\(=\dfrac{18+12+\left(-5\right)}{24}\)

\(=\dfrac{25}{24}\)

\(b)\dfrac{-5}{7}.\dfrac{2}{13}-\dfrac{5}{7}.\dfrac{11}{13}+\dfrac{5}{7}\)

\(=\dfrac{5}{7}.\dfrac{-2}{13}-\dfrac{5}{7}.\dfrac{11}{13}+\dfrac{5}{7}\)

\(=\dfrac{5}{7}\left(\dfrac{-2}{13}+\dfrac{-11}{13}+\dfrac{13}{13}\right)\)

\(=\dfrac{5}{7}.0=0\)

\(c)\dfrac{27}{23}+\dfrac{5}{21}+\dfrac{1}{2}-\dfrac{4}{23}+\dfrac{16}{21}\)

\(=\left(\dfrac{27}{23}-\dfrac{4}{23}\right)+\left(\dfrac{5}{21}+\dfrac{16}{21}\right)+\dfrac{1}{2}\)

\(=1+1+\dfrac{1}{2}\)

\(=2\dfrac{1}{2}\)

\(d)\dfrac{15}{34}+\dfrac{7}{21}+\dfrac{19}{34}.\dfrac{20}{15}+\dfrac{3}{7}\)

\(=\dfrac{315}{714}+\dfrac{238}{714}+\dfrac{38}{51}+\dfrac{306}{714}\)

\(=\dfrac{315}{714}+\dfrac{238}{714}+\dfrac{532}{714}+\dfrac{306}{714}\)

\(=\dfrac{1391}{714}\)

3 tháng 8 2018

a)\(\dfrac{3}{4}+\dfrac{6}{12}-\dfrac{5}{24}=\dfrac{18}{24}+\dfrac{12}{24}-\dfrac{5}{24}=\dfrac{25}{24}\)

b)\(\dfrac{-5}{7}.\dfrac{2}{13}-\dfrac{5}{7}.\dfrac{11}{13}+\dfrac{5}{7}=\dfrac{5}{7}\left(\dfrac{-2}{13}-\dfrac{11}{13}+1\right)=\dfrac{5}{7}.0=0\)

c)\(\dfrac{27}{23}+\dfrac{5}{21}+\dfrac{1}{2}-\dfrac{4}{23}+\dfrac{16}{21}=\left(\dfrac{27}{23}-\dfrac{4}{23}\right)+\left(\dfrac{5}{21}+\dfrac{16}{21}\right)+\dfrac{1}{2}=1+1+\dfrac{1}{2}=2,5\)

d)\(\dfrac{15}{34}+\dfrac{7}{21}+\dfrac{19}{34}.\dfrac{20}{15}+\dfrac{3}{7}=\dfrac{15}{34}+\left(\dfrac{1}{3}+\dfrac{38}{51}+\dfrac{3}{7}\right)=\dfrac{15}{34}+\dfrac{538}{357}=\dfrac{1391}{714}\)

8 tháng 12 2018

Cậu không làm được hay cần gấp con nào nhỉ ?

Bài 1:

a: \(\Leftrightarrow\dfrac{x+2}{2}=x-5\)

=>2x-10=x+2

=>x=12

b: \(\Leftrightarrow\left(x+2\right)^2=100\)

=>x+2=10 hoặc x+2=-10

=>x=-12 hoặc x=8

c: \(\Leftrightarrow\left(2x-5\right)^3=27\)

=>2x-5=3

=>2x=8

=>x=4