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Câu 2:
a: \(=9\cdot8-72:4=72-18=54\)
b: \(=125\cdot26+125\cdot32+125\cdot42\)
\(=125\left(26+32+42\right)=125\cdot100=12500\)
c: \(=5871:\left(928-825\right)+1=5871:103+1=57+1=58\)
d: \(=2012+78-178-2012=-100\)
1)58.75+58.50-58.25
=58.(75+50-25)
=58.100=5800
5) 47 - (45.24 - 25.12 ):14
=47-2^4.(45-12.2):14
=47-16.(45-24):14
=47-8/7.21
=47-24=23
6)102 -60: ( 56:54-3.5)
=100-60:(5^2-15)
=100-60:(25-15)
=100-60:10
=100-6=94
7)29 - [16+3.(51 -49)]
=29-[16+3.2]
=29-22
=7
8)-|-|33|+(-15)+20-|45-40|-57
=-33-15+20-|5|-57
=-33-15+20-5-57=-90
9)9.|40-37|-|2.13 - 52 |
=9.|3|-|26-52|
=9.3-|-26|
=27-26
=3
BÀI TÌM UCLN VÀ BCNN bạn tự làm nhé, bạn phân tịhs ra thừa số nguyên tố zồi giải
Bài 3: Tìm x
a) 89-(73 -x ) =20
73-x=89-20=69
x=79-69=4
b) (x+7)-25 = 13
x+7=13+25=38
x=28-7=21
c)98-(x + 4)=20
x+4=98-20=78
x=78-4=74
d)140:(x-8)=7
x-8=140:7=20
x=20+8=28
e)4(x+41)=400
x+41=400:4=100
x=100-41=59
f)x - [ 42 +(-28)]=-8
x=-8+42+(-28)
x=-8+42-28
x=6
m)2x-49=5.32
2x-49=5.9
2x=45+49
2x=94
x=94:2=47
mấy câu sau bạn phân tích giống mấy câu trước zồi giải nhé
a) 12 : { 400 : [500 – (125 + 25 . 7)]}
=12 : { 400 : [500 – (125 + 175)]}
=12 : [ 400 : [500 – 300)]
=12 : (400:200)
=12:2=6
b) 5 . 22 – 18 : 3
=5.4-6
=20-6=14
c) 18 : 3 + 182 + 3.(51 : 17)
=5+182+3.3
=187+9=196
d) 25 . 8 – 12.5 + 170 : 17 – 8
=200-60+10-8
=142
e) 2.52+ 3: 710 – 54: 33
=2.25+3:1-54:27
=50+3-2
=51
f) 189 + 73 + 211 + 127
=(189+211)+(73+127)
=400+200=600
g) 375 : {32 – [ 4 + (5. 32– 42)]} – 14 )
=375 : {32 – [ 4 + (160– 42)]} – 14 )
=375 : [32 – ( 4 + 118) – 14 ]
=375:(32-122-14)
=375:-104
=-375/104
h) (52022 + 52021) : 52021
=(52022:52021)+(52021:52021)
=5+1=6
sau 58 ,7,50 ,2,-60 là phép tính khác .
mấy b giúp mk nha ?
J.
=2345-1000:[19-2*(3^2)]
=2345-1000:[19-18]
=2345-1000:1
=2345-1000
=1345
F.
=(11^2)-(3^2)*-3+50
=[(11-3)^2]*-3+50
=(8^2)*-3+50
=64-3+50
=61+50
=111
E.
=295+(31-4*5)
=295+(31-20)
=295+11
=306
mik het bit làm r
J. 2345-1000 : [ 19 - 2 ( 21 - 18 )2 ]
= 2345 - 1000 : [ 19 - 2.32 ]
= 2345 - 1000 : (19 - 18)
= 2345 - 1000
= 1345.
F. 1125 : 1123 - 33 + 50
= 112 - 27 + 50
= 121 - 27 + 50
= 144
E. 295 + ( 31 - 22 . 5 )2
= 295 + (31 - 4.5)2
= 295 + 112
= 295 + 121
= 416
H. 47 + ( 45 . 24 - 52 . 12) : 14
= 47 + (45 . 16 - 25.12) : 14
= 47 + 420 : 14
= 47 + 30
= 77
I. 102 - 60 : ( 56 : 54 - 3 . 5 )
= 100 - 60 : (25 - 15)
= 100 - 60 : 10
= 100 - 6
= 94.
K. 205 + [ 1200 - ( 42 - 2 . 3 ) 3 ] : 40
= 205 + [1200 - (16 - 6)3 ] : 40
= 205 + [1200 - 1000] : 40
= 205 + 200 : 40
= 205 + 5
= 210
L. 500 - { 5 . [ 409 - ( 23 . 3 - 21 ) 2 ] + 103 } : 15
= 500 - {5 . [409 - (24 - 21)2 ] + 1000} : 15
= 500 - {5 . [409 - 9] + 1000}: 15
= 500 - {5.400+1000}:15
= 500 -3000:15
= 500 - 200
= 300.
a) \(9\cdot2^3-72:2^2\)
\(=72-18=54\)
b) \(125\cdot26+5^3\cdot32+25\cdot42\cdot5\)
\(=125\cdot26+125\cdot32+125\cdot42\)
\(=125\cdot\left(26+32+42\right)=125\cdot100=12500\)
c) \(5871:\left[928-\left(247-82\right)\cdot5\right]+2012^0\)
\(=5871:\left[928-\left(247-82\right)\cdot5\right]+1\)
\(=5871:\left(928-165\cdot5\right)+1\)
\(=5871:103+1\)
\(=58\)
d) \(2012+78+\left(-178\right)+\left(-2012\right)\)
\(=\left[2012+\left(-2012\right)\right]+\left[78+\left(-178\right)\right]\)
\(=-100\)
a, \(9.2^3-\frac{72}{2^2}=9.8-\frac{72}{4}=72-18=54\)
b, \(125.26+5^3.32+25.42.5\)
\(=125.26+125.32+125.42\)
\(=125.\left(26+32+42\right)\)
\(=125.100\)
\(=12500\)
c, \(\frac{5871}{\left[928-\left(247-82\right).5\right]}+2012^0\)
\(=\frac{5871}{103}+1\)
\(=57+1\)
\(=58\)
d, \(2012+78+\left(-178\right)+\left(-2012\right)\)
\(=\left[2012+\left(-2012\right)\right]+\left[78+\left(-178\right)\right]\)
\(=0+100\)
\(=100\)
a) 160 - ( 23 . 52 - 6 . 25 ) = 160-( 8 . 25 - 6 . 25 ) = 160 - ( 25 . ( 8-6)) = 160-(25 . 2) = 160- 50 = 110
b) 4 . 52 - 32 : 24 = 4 . 25 - 4 . 8 : 16 = 4 . ( 25 - 8 : 16 ) = 4 . 24,5 = 98
a)35-(12-(-14+(-2)))
=35-(12-(-12))
=35-(12+12)
=35-24
=11
b)49-(-54)-23
=49+54-23
=103-23
=80
c)5871:(928-((-82)+247))×5)
=5871:(928-165×5)
=5871:(928-825)
=5871:103
=57
a) = 35
b) = 80
còn lại mình xin bí