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a: =-5/9-4/9+8/15+7/15-2/11=-2/11
b: =10/17+7/17-5/13-8/13+11/25
=11/25
c: =(9/12-2/12)*3/2=7/12*3/2=21/24=7/8
d: =(31/10-25/10)*3-2
=3/5*3-2
=9/5-2
=-1/5
a: =35/17-18/17-9/5+4/5
=1-1=0
b: =-7/19(3/17+8/11-1)
=7/19*18/187=126/3553
c: =26/15-11/15-17/3-6/13
=1-6/13-17/3
=7/13-17/3=-200/39
Bài 1:
Ta có: \(x-35\%\cdot x=\dfrac{1}{25}\)
\(\Leftrightarrow65\%\cdot x=\dfrac{1}{25}\)
\(\Leftrightarrow x=\dfrac{1}{25}:\dfrac{13}{20}=\dfrac{1}{25}\cdot\dfrac{20}{13}=\dfrac{4}{65}\)
Vậy: \(x=\dfrac{4}{65}\)
Bài 2:
a) Ta có: \(17\dfrac{2}{31}-\left(\dfrac{15}{17}+6\dfrac{2}{31}\right)\)
\(=17\dfrac{2}{31}-\dfrac{15}{17}-6\dfrac{2}{31}\)
\(=11+\dfrac{2}{31}-\dfrac{15}{17}\)
\(=\dfrac{5366}{527}\)
\(-\frac{1}{10}< =x< =\frac{3}{5}\)
\(\frac{-4}{9}< x< =\frac{2}{3}\)
a: \(\dfrac{31}{17}+\dfrac{-5}{13}+\dfrac{-8}{15}-\dfrac{4}{17}\)
\(=\dfrac{31-4}{17}+\dfrac{-5\cdot15+\left(-8\right)\cdot13}{195}\)
\(=\dfrac{27}{17}+\dfrac{-179}{195}=\dfrac{2222}{3315}\)
b: \(\left(-2\right)^3-1\dfrac{5}{7}\cdot\left(-\dfrac{3}{2}\right)^3\)
\(=-8-\dfrac{12}{7}\cdot\dfrac{-27}{8}\)
\(=-8+\dfrac{12}{7}\cdot\dfrac{27}{8}\)
\(=-8+\dfrac{12}{8}\cdot\dfrac{27}{7}\)
\(=-8+\dfrac{3}{2}\cdot\dfrac{27}{7}=-8+\dfrac{81}{14}=\dfrac{-112+81}{14}=\dfrac{-31}{14}\)