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1 tháng 7 2017

a)15/16:3/8x3/4

=15/16:6/16x12/16

=15/16x16/6x12/16

=15/6x12/16

=30/16=15/8

1 tháng 7 2017

b)5/11x18/29-5/11x8/29+5/11x19/29

=5/11x(18/29-8/29+19/29)

=5/11x1=5/11

27 tháng 4 2017

x-7=15-(-21)

x-7=36

x=36-7

x=29

27 tháng 4 2017

x = 29 đấy bạn

k cho mình nha

11 tháng 4 2019

\(a,0,5x-\frac{2}{3}x=\frac{7}{12}\Rightarrow\frac{1}{2}x-\frac{2}{3}x=\frac{7}{12}\)

\(\Rightarrow x\left(\frac{1}{2}-\frac{2}{3}\right)=\frac{7}{12}\Rightarrow x\cdot\left(\frac{3}{6}-\frac{4}{6}\right)=\frac{7}{12}\)

\(\Rightarrow x\cdot\left(-1\right)=\frac{7}{12}\Rightarrow x=\frac{7}{12}:\left(-1\right)=\frac{7}{-12}\)

\(c,\frac{\left(x-5\right)}{12}\cdot\frac{9}{29}=\frac{-6}{29}\Rightarrow\frac{\left(x-5\right)}{12}=\frac{-6}{29}:\frac{9}{26}\)

\(\frac{\Rightarrow\left(x-5\right)}{12}=\frac{-6}{9}=\frac{-2}{3}\Rightarrow x-5=-\frac{2}{3}\cdot12\)

\(\Rightarrow x-5=\frac{-24}{3}=-8\Rightarrow x=-8+5=-3\)

11 tháng 4 2019

\(a,0,5x-\frac{2}{3}x=\frac{7}{12}\)

\(\Rightarrow\frac{1}{2}x-\frac{2}{3}x=\frac{7}{12}\)

\(\Rightarrow-\frac{1}{6}x=\frac{7}{12}\)

\(\Rightarrow x=-\frac{7}{2}\)

\(c,\frac{x-5}{12}\cdot\frac{9}{29}=-\frac{6}{29}\)

\(\Rightarrow\frac{x-5}{12}=-\frac{2}{3}\)

\(\Rightarrow x-5=12.\left(-\frac{2}{3}\right)\)

\(\Rightarrow x-5=-8\)

\(\Rightarrow x=-3\)

3 tháng 2 2017

a) \(12x-60+21-7x-5=0\)

\(\Rightarrow5x-44=0\)

\(\Rightarrow5x=44\)

\(\Rightarrow x=\frac{44}{5}\)

Vậy: \(x=\frac{44}{5}\)

3 tháng 2 2017

b) \(2x^2-3=29\)

\(\Rightarrow2x^2=3+29=32\)

\(\Rightarrow x^2=\frac{32}{2}=16\)

\(\Rightarrow x=\sqrt{16}=4\)

Vậy: \(x=4\)

25 tháng 6 2017

a) \(5-\left[x+1\right]=29\)

\(x+1=5-29\)

\(x+1=-24\)

\(x=-24-1\)

\(x=-25\)

Vậy \(x=-25\) là giá trị cần tìm

b) \(\left(-1\right)+3+\left(-5\right)+7+\left(-9\right)+........+x=600\)

\(\Rightarrow\left[\left(-1\right)+3\right]+\left[\left(-5\right)+7\right]+............+\left[-\left(x-2\right)+x\right]=600\)

\(\Rightarrow2+2+2+.......+2=600\)

\(\Rightarrow2\left(1+1+......+1\right)=600\)

\(\Rightarrow1+1+........+1=300\)

Số dấu ngoặc [] là :

\(\dfrac{x-3}{4+1}\)

\(\Rightarrow\dfrac{x-3}{4+1}=300\)

\(\Rightarrow\dfrac{x-3}{4}=299\)

\(\Rightarrow x-3=299.4\)

\(\Rightarrow x=299.4+3\)

\(\Rightarrow x=1199\)

25 tháng 6 2017

\(5-\left|x+1\right|=29\)

\(\left|x+1\right|=5-29\)

\(\left|x+1\right|=-24\Leftrightarrow x\in\left\{\varnothing\right\}\)

5 tháng 6 2018

Bài 1:

a) \(\frac{16}{15}.\frac{\left(-5\right)}{14}.\frac{54}{24}.\frac{56}{21}\)

\(=\frac{4.2.2}{5.3}.\frac{\left(-5\right)}{2.7}.\frac{3.3}{4}.\frac{8}{3}\)

\(=\frac{4.2.2.\left(-5\right).3.3.8}{5.3.2.7.4.3}\)

\(=\frac{-16}{7}\)

b) \(\frac{7}{3}.\frac{\left(-5\right)}{2}.\frac{15}{21}.\frac{4}{\left(-5\right)}\)

\(=\frac{7}{3}.\frac{\left(-5\right)}{2}.\frac{5}{7}.\frac{2.2}{\left(-5\right)}\)

\(=\frac{7.\left(-5\right).5.2.2}{3.2.7.\left(-5\right)}\)

\(=\frac{10}{3}\)

5 tháng 6 2018

Bài 2:

a) \(\frac{21}{24}.\frac{11}{9}.\frac{5}{7}=\frac{7}{8}.\frac{11}{9}.\frac{5}{7}=\frac{11.5}{8.9}=\frac{55}{72}\)

b) \(\frac{5}{23}.\frac{17}{26}+\frac{5}{23}.\frac{9}{26}\)

\(=\frac{5}{23}.\left(\frac{17}{26}+\frac{9}{26}\right)=\frac{5}{23}.1=\frac{5}{23}\)

c) \(\left(\frac{3}{29}-\frac{1}{5}\right).\frac{29}{3}=\frac{3}{29}.\frac{29}{3}-\frac{1}{5}.\frac{29}{3}\)

\(=1-1\frac{14}{15}=\frac{14}{15}\)

Bài 3:

a) x/5 = 2/5

=> x =2

b) -4/x = 20/14 = 10/7

=> -4/x = 10/7

=> x.10 = (-4).7

x.10 = - 28

x= -28 :10

x= -2,8

c) 4/7 = 12/x = 12/ 21

=> 12/x = 12/21

=> x = 21

d) 3/7 = x / 21 = 9/21

=> x/21 = 9/21

=> x= 9

21 tháng 4 2017

a, \(\dfrac{62}{7}.x=\dfrac{29}{90}.\dfrac{3}{56}\)

\(\dfrac{62}{7}.x=\dfrac{29}{1680}\)

\(x=\dfrac{29}{1680}:\dfrac{62}{7}\)

\(x=\dfrac{29}{14880}\)

b, \(\dfrac{1}{5}:x=\dfrac{1}{5}-\dfrac{1}{7}\)

\(\dfrac{1}{5}:x=\dfrac{2}{35}\)

\(x=\dfrac{1}{5}:\dfrac{2}{35}\)

\(x=\dfrac{7}{2}\)

c, \(\left(x+\dfrac{1}{4}-\dfrac{1}{3}\right):\left(2+\dfrac{1}{6}-\dfrac{1}{4}\right)=\dfrac{7}{46}\)

\(\left(x+\dfrac{1}{4}-\dfrac{1}{3}\right):\left(\dfrac{13}{6}-\dfrac{1}{4}\right)=\dfrac{7}{46}\)

\(\left(x+\dfrac{1}{4}-\dfrac{1}{3}\right):\dfrac{23}{12}=\dfrac{7}{46}\)

\(\left(x+\dfrac{-1}{12}\right):\dfrac{23}{12}=\dfrac{7}{46}\)

\(\left(x+\dfrac{-1}{12}\right)=\dfrac{7}{46}.\dfrac{23}{12}\)

\(x+\dfrac{-1}{12}=\dfrac{7}{24}\)

\(x=\dfrac{7}{24}-\dfrac{-1}{12}\)

\(x=\dfrac{3}{8}\)