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#)Giải :
A, \(\frac{254x399-145}{254+399x253}\)
\(=\frac{253x399+399-145}{254+399x253}\)
\(=\frac{253x399+254}{254+399x253}\)
\(=1\)
B, \(\frac{5932+6001x5931}{5931x6001-69}\)
\(=\frac{5932+6001x5931}{\left(5931+1\right)x6001-69}\)
\(=\frac{5932+6001x5931}{5931x6001+6001-69}\)
\(=\frac{5932+6001x5932}{5932x6001+5932}\)
\(=1\)
#~Will~be~Pens~#
\(\frac{254x399-145}{254+399x253}=\frac{\left(253+1\right)x399-145}{254+399x253}=\frac{253x399+1x399-145}{254+399x253}=\frac{253x399+254}{254+399x253}\)
\(=1\)
3*x + 2*x + x =12*5 + 12*4 + 12
3*x +2*x + x = 12*(5 + 4 +1)
3*x + 2*x + x = 12*10
3*x + 2*x + x = 120
x*(3 +2 + 1) = 120
x*6 = 120
x = 120 : 6
x = 20
\(\frac{3}{4}.\frac{12}{7}+x=\frac{5}{2}\)
\(\frac{3.3}{1.7}+x=\frac{5}{2}\)
\(\frac{9}{7}+x=\frac{5}{2}\)
\(x=\frac{5}{2}-\frac{9}{7}\)
\(x=\frac{35}{14}-\frac{18}{14}\)
\(x=\frac{17}{14}\)
=> x . ( 2 + 3 + 4 + 5 + 6 ) = x . 9 + 9999
=> x . 20 = x . 9 + 9999
=> x . 11 = 9999 ( cùng bớt x + 9 )
=> x = 9999 : 11
=> 909
2x + 3x + 4x + 20x + 6x = 9x + 9999
35x - 9x = 9999
26x = 9999
x = 9999 / 26
Vậy : x = 9999 / 26
`75/20 - x = 3/2 xx 10`
`15/4 - x = 15`
`x = 15/4 - 15`
`x = -45/4`
`(12 xx 15) - X xx 1/4 = 120 xx 1/4`
`180 - X xx 1/4 = 30`
`X xx 1/4 = 180-30`
`X xx 1/4 = 150`
`X = 150 : 1/4`
`X = 600`
\(\dfrac{15}{4}-x=15\)
\(x=\dfrac{15}{4}-15\)
\(x=-\dfrac{45}{4}\)
\(\left(12\times15\right)-\dfrac{1}{4}x=120\times\dfrac{1}{4}\)
\(180-\dfrac{1}{4}x=30\)
\(-\dfrac{1}{4}x=30-180\)
\(-\dfrac{1}{4}x=-150\)
\(-x=-150:\dfrac{1}{4}\)
\(-x=-150\times4\)
\(-x=-600\)
\(x=600\)
1.53x201=10653
2.
a)4 xX-15x4=6x15+X
<=>4x-60=90+x
<=>4x-x=60+90
<=>3x=150
<=>x=50
b(102+28-2x):20-5=1
<=>(130-2x):20=6
<=>130-2x=120
<=>2x=10
<=>x=5
c)1999x-x=1999+1997+1999
<=>1998x=5995
<=>\(x\approx3\)
d)105-5x=150:15
<=>105-5x=10
<=>5x=95
<=>x=19
e)(x+1)+(x+2)+(x+3)+...+(x+6)=78
<=>6x+21=78
<=>6x=57
<=>x=9,5
1) 53x201=53x200+53=10600+53=10653
2a)
4x-15x4=6x15+x
4x-60=90+x
4x-x=90+60
3x=150
x=50
b) x=5
c) x=3
d)x=19
e) x=9,5
a) \(2\times x+3\times x=\frac{5}{2}\)
=> \(\left(2+3\right)\times x=\frac{5}{2}\)
=> \(5\times x=\frac{5}{2}\)
=> \(x=\frac{5}{2}:5=\frac{5}{2}\times\frac{1}{5}=\frac{1}{2}\)
b) \(145+x\times12-432=253\)
=> \(145+x\times12=253+432\)
=> \(145+x\times12=685\)
=> \(x\times12=685-145\)
=> \(x\times12=540\Rightarrow x=45\)
Câu a) 2 x X + 3 x X = 5/2
( 2+3 ) x X = 5/2
5 x X = 5/2
X =5/2 : 5
X = 1/2
Câu b) 145 + X x 12 - 432 = 253
145 + X x 12 = 253 + 432
145 + X x 12 = 685
X x 12 = 685 - 145
X x 12 = 540
X = 540 : 12
X = 45