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9 tháng 7 2017

a) \(\left(\dfrac{1}{2}\right)^3.\left(\dfrac{1}{4}\right)^2\)

\(=\dfrac{1}{8}.\dfrac{1}{16}\)

\(=\dfrac{1}{128}\)

b) \(16:\left(0,125\right)^3.512\)

\(=16:\dfrac{1}{512}.512\)

\(=16:\left(\dfrac{1}{512}.512\right)\)

\(=16:1\)

\(=16\)

9 tháng 7 2017

a, \(\left(\dfrac{1}{2}\right)^3\). \(\left(\dfrac{1}{4}\right)^2\)

=\(\dfrac{1}{8}\).\(\dfrac{1}{16}\)

=\(\dfrac{1}{128}\)

b, 16 : (0,125)3.512

= 16 : \(\dfrac{1}{512}\).512

= 16 : 1

=16

19 tháng 10 2021

\(1,\\ a,=\left(\dfrac{1}{4}\right)^3\cdot32=\dfrac{1}{64}\cdot32=\dfrac{1}{2}\\ b,=\left(\dfrac{1}{8}\right)^3\cdot512=\dfrac{1}{512}\cdot512=1\\ c,=\dfrac{2^6\cdot2^{10}}{2^{20}}=\dfrac{1}{2^4}=\dfrac{1}{16}\\ d,=\dfrac{3^{44}\cdot3^{17}}{3^{30}\cdot3^{30}}=3\\ 2,\\ a,A=\left|x-\dfrac{3}{4}\right|\ge0\\ A_{min}=0\Leftrightarrow x=\dfrac{3}{4}\\ b,B=1,5+\left|2-x\right|\ge1,5\\ A_{min}=1,5\Leftrightarrow x=2\\ c,A=\left|2x-\dfrac{1}{3}\right|+107\ge107\\ A_{min}=107\Leftrightarrow2x=\dfrac{1}{3}\Leftrightarrow x=\dfrac{1}{6}\)

\(d,M=5\left|1-4x\right|-1\ge-1\\ M_{min}=-1\Leftrightarrow4x=1\Leftrightarrow x=\dfrac{1}{4}\\ 3,\\ a,C=-\left|x-2\right|\le0\\ C_{max}=0\Leftrightarrow x=2\\ b,D=1-\left|2x-3\right|\le1\\ D_{max}=1\Leftrightarrow x=\dfrac{3}{2}\\ c,D=-\left|x+\dfrac{5}{2}\right|\le0\\ D_{max}=0\Leftrightarrow x=-\dfrac{5}{2}\)

14 tháng 8 2017

image /assets/images/2017/08_10/1195-xHOKk8NXdv5EDVJo.jpeg

14 tháng 8 2017

a) \(\left(\dfrac{1}{5}\right)^5.5^5=\left(\dfrac{1}{5}.5\right)^5=1^5=1\)

b) \(\left(0,125\right)^3.512=\left(0,512\right)^3.8^3=\left(0,512.8\right)^3=1^3=1\)

c) \(\left(0,25\right)^4.1024=\left[\left(0,25\right)^2\right]^2.32^2=\left(\dfrac{1}{6}\right)^2.32^2=\left(\dfrac{1}{6}.32\right)^2=2^2=4\)

d) \(\dfrac{120^3}{40^3}=\left(\dfrac{120}{40}\right)^3=3^3=64\)

e) \(\dfrac{390^4}{130^4}=\left(\dfrac{390}{130}\right)^4=3^4=81\)

g) \(\dfrac{3^2}{\left(0,375\right)^2}=\left(\dfrac{3}{0,375}\right)^3=8^3=512\)

15 tháng 12 2019

(0,125)3.512 = 0,1253.83 = (0,125.8)3 = 13 = 1

15 tháng 8 2023

\(0,125^3.512\)

=\(\left(\dfrac{1}{8}\right)^3.8^3\)

\(\dfrac{1}{8^3}.8^3\)

=\(6^3\)

15 tháng 8 2023

  (0,125)3. 512

=  (0,125)3. 83

= (0,125.8)3

= 13

\(\left(\dfrac{1}{1^{ }}\right)^3\)

 

26 tháng 6 2017

0, 1253 . 512 = 0, 1253 . 83 = (0,125 .8 )3 =13 = 1.

13 tháng 9 2017

a/ \(\left(\dfrac{1}{5}\right)^5.5^5=\left(\dfrac{1}{5}.5\right)^5=1^5=1\)

b/ \(\left(0,125\right)^3.512=\left(0,125\right).8^3=\left(0,125.8\right)^3=1^3=1\)

c/ \(\left(0,25\right)^4.1024=\left(0,25^2\right)^2.32^2=\left(\dfrac{1}{6}\right)^2.32^2=\left(\dfrac{1}{6}.32\right)^2=16^2\)

13 tháng 9 2017

\(a,\left(\dfrac{1}{5}\right)^5.5^5=\left(\dfrac{1}{5}.5\right)^5=1^5=1\)

\(b,\left(0,125\right)^3.512=\left(0,125\right)^3.8^3=\left(0,125.8\right)^3=1^3=1\)

\(c,\left(0,25\right)^4.1024=\left(0,25\right)^4.4^4.4=\left(0,25.4\right)^4.4=1^4.4=1.4=4\)

9 tháng 6 2017

a) \(\left(\dfrac{1}{5}\right)^5.5^5=1\)

b) \(\left(0,125\right)^3.512=1\)

c) \(\left(0,25\right)^4.1024=4\)

9 tháng 7 2017

a) (1/5)^5 . 5^5 = (1/5. 5)^5 = 1^5= 1

b) (0,125)^3. 512= (0,125)^3 . 8^3 = (0,125. 8)^3 = 1^3= 1

c) (0,25)^4. 1024= [(0,25)^2]^2. 32^2= (1/6)^2. 32^2=(1/6.32)^2= (32/6)^2 =2^2= 4

6 tháng 8 2017

a) \(\left(\dfrac{1}{5}\right)^5.5^5\)

\(=\dfrac{1}{3125}.3125\)

= 1

b) \(\left(0,125\right)^3.512\)

\(=\dfrac{1}{512}.512\)

= 1

c) \(\left(0,25\right)^4.1024\)

= \(\dfrac{1}{256}.1024\)

= 4

6 tháng 8 2017

50.

a) \(\left(\dfrac{1}{5}\right)^5.5^5\)

\(=\left(5^{-1}\right)^5.5^5=5^{-5}.5^5=5^{-5+5}=5^0=1\)

8 tháng 9 2021

toi ko co the bt day nh vau ko dau