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A = 78 x 31 + 78 x 24 + 78 x 17 + 22 x 72
A = 78 x ( 31 + 24 + 17 ) + 22 x 72
A = 78 x 72 + 22 x 72
A = 72 x ( 78 + 22 )
A = 72 x 100
A = 7200
C = 53 x 39 + 47 x 39 - 53 x 21 - 47 x 21
C = 39 x ( 53 + 47 ) - 21 x ( 53 - 47 )
C = 39 x 100 - 21 x 6
C = 3900 - 126
C = 3774
a) 67.(-18) + (-33).18
= 67.(-18) + 33.(-18)
= (-18).(67 + 33)
= (-18).100
= (-1800)
b) 34.(-53) - (-66).53 - 68.(-53)
= (-34).53 + 66.53 - (-68).53
= (-34).53 + 66.53 + 68.53
= 53. (-34 + 66 + 68)
= 53.100
= 5300
a) 67.(-18) + (-33).18
= 67.(-18) + 33.(-18)
= (-18).(67 + 33)
= (-18).100
= (-1800)
b) 34.(-53) - (-66).53 - 68.(-53)
= (-34).53 + 66.53 - (-68).53
= (-34).53 + 66.53 + 68.53
= 53. (-34 + 66 + 68)
= 53.100
= 5300
chúc bạn học tốt nhé
dẫu . là dấu nhân nha mn.
mong mn giải giúp mình mình đang cần gấp
a) – 3 < x < 2 => x ∈ {-2;-1;0;1}
b) − 4 21 < x 21 < 2 21 => x ∈ {-3;-2;-1;0;1}
c) 1 ≤ x ≤ 6 => x ∈ {-3;-2;-1;0;1}
d) -7 ≤ x ≤ -3 => x ∈ {-3;-2;-1;0;1}
\(\frac{8}{29}+\frac{4}{21}-53\frac{3}{53}+\frac{17}{21}-\frac{27}{19}\)
\(=\left(\frac{8}{19}-\frac{27}{19}\right)+\left(\frac{4}{21}+\frac{17}{21}\right)-53\frac{3}{53}\)
\(=-1+1-53\frac{3}{53}=0-53\frac{3}{53}=-53\frac{3}{53}\)
\(\frac{17}{21}\cdot\frac{48}{53}+\frac{17}{21}\cdot\frac{4}{53}+\frac{52}{53}\cdot\frac{4}{21}\)
\(=\frac{17}{21}\left(\frac{48}{53}+\frac{4}{53}\right)+\frac{52}{53}\cdot\frac{4}{21}\)
\(=\frac{17}{21}\cdot\frac{52}{53}+\frac{52}{53}\cdot\frac{4}{21}\)
\(=\frac{52}{53}\left(\frac{17}{21}+\frac{4}{21}\right)\)
\(=\frac{52}{53}\cdot1\)
\(\frac{17}{21}.\frac{48}{53}+\frac{17}{21}.\frac{4}{53}+\frac{52}{53}.\frac{4}{21}\)
= \(\frac{17}{21}.\left(\frac{48}{53}+\frac{4}{53}\right)+\frac{52}{53}.\frac{4}{21}\)
= \(\frac{17}{21}.\frac{52}{53}+\frac{52}{53}.\frac{4}{21}\)
=\(\frac{52}{53}.\left(\frac{17}{21}+\frac{4}{21}\right)\)
= \(\frac{52}{53}\)
\(a,\left(-113\right)+55+113-155=\left(-113+133\right)+\left(55-155\right)=0+\left(-100\right)=-100\\ b,-25.17+17.\left(-75\right)=17\left[\left(-25\right)+\left(-75\right)\right]=17.\left(-100\right)=-1700\)
\(c,6^8:6^6-3\left[\left(-53\right)-\left(-21-53\right)\right]+2022^0\\ =6^2-3\left(-53+21+53\right)+1\\ =36-3.21+1\\ =36-63+1\\ =-26\)
a(-113) + 55 + 113 - 155
=>(-113)+ 113+(55 - 155)
=>-100
b -25.17+17.(-75)
=>17(-25-75)
=>17. (-100)
=>-1700
c 68 : 66-3 [( -53) - ( -21 -53 )] + 20220
=>62- 3[ -53 +21 +53 )]+1
=>36−3.21+1
=>36−63+1
=>−26