Question

[Nguyen Huy Hoang]

 9^{x +2} + 9^x_ 9². 82 = 0 

Answer 1

[thyuggggfytu678]

\(9^x\).\(9^2\)+\(9^x\)-\(9^2\).82=0

\(9^x\).[\(9^2\)+1]-\(9^2\).82=0

\(9^x\).82-\(9^2\).82=0

82.[\(9^x\)-\(9^2\)]=0

\(9^x\)-\(9^2\)=82

\(9^x\)=1

x=1

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