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Câu 9:
\(3^x=9^{-6}\cdot27^{-6}\cdot81^8\)
\(\Leftrightarrow3^x=\dfrac{1}{9^6\cdot27^6}\cdot81^8=\dfrac{1}{3^{12}\cdot3^{18}}\cdot3^{32}=3^2\)
=>x=2
Câu 18:
\(4^{x+3}-3\cdot4^{x+1}=13\cdot4^{11}\)
\(\Leftrightarrow4^x\cdot64-3\cdot4^x\cdot4=13\cdot4^{11}\)
\(\Leftrightarrow4^x\left(64-3\cdot4\right)=13\cdot4^{11}\)
\(\Leftrightarrow4^x=13\cdot4^{10}\cdot4:52=4^{10}\)
=>x=10
\(\Leftrightarrow3^x\cdot82=3^{50}+3^{54}\)
hay x=50
nguyen truong giang tưởng c là ng` ko xin lk ai ngờ............................................... @@
1. Với mọi x,y ta có :
\(\left\{{}\begin{matrix}\left|x-2013\right|\ge0\\\left|1007-\dfrac{1}{2}y\right|\ge0\end{matrix}\right.\)
Mà \(\left|x-2013\right|+\left|1007-\dfrac{1}{2}y\right|=0\)
\(\Leftrightarrow\left\{{}\begin{matrix}\left|x-2013\right|=0\\\left|1007-\dfrac{1}{2}y\right|=0\end{matrix}\right.\)
\(\Leftrightarrow\left\{{}\begin{matrix}x-2013=0\\1007-\dfrac{1}{2}y=0\end{matrix}\right.\) \(\Leftrightarrow\left\{{}\begin{matrix}x=2013\\y=2014\end{matrix}\right.\)
Vậy ...
2. Đặt :
\(H=9.10^n+18\)
Mà \(27=9.3\)
Ta có ;
\(A=9.10^n+18=9\left(10^n+2\right)\)
\(\Leftrightarrow A⋮9\)\(\left(1\right)\)
Lại có :
\(10^n+2=\left(10.......0\right)+2=100....02\)
\(\Leftrightarrow A⋮3\)\(\left(2\right)\)
Từ \(\left(1\right)+\left(2\right)\Leftrightarrow A⋮27\left(đpcm\right)\)
a) 87-218
=(23)7-218
=221-218
=218.(23-1)
=218. 7
=217.2.7
=217.14 chia het cho 14
81^7-27^9-9^13
=(3^4)^7-(3^3)^9-(3^2)^13
=3^28-3^27-3^26
=(3^26.3^2)-(3^26.3^1)-(3^26.1)
=3^26.(9-3-1)
=3^22.(3^4.5)
=3^22.405 chia het cho 405
=> 81^7-27^9-9^13 chia het cho 405
Mình chỉ giải câu a thôi,mấy câu còn lại dễ.
a)Ta có:\(\dfrac{x}{27}=\dfrac{-3}{x}\)
=>\(x^2=-3\cdot27=-81\)(Nhân chéo)
Mà x2>0 với mọi x nên :
Không có giá trị nào thỏa mãn điều kiện của x
Tìm x biết :
a) \(\dfrac{x}{27}=-\dfrac{3}{x}\) \(\Rightarrow2x=-3.27\Rightarrow2x=-81\Rightarrow x=-40,5\)
b) \(-\dfrac{9}{x}=-\dfrac{x}{\dfrac{4}{49}}\Rightarrow2x=-9.\left(-\dfrac{4}{9}\right)\Rightarrow2x=4\Rightarrow x=2\)
c) \(\left|7x-\dfrac{5}{3}\right|+\dfrac{7}{19}=-\dfrac{8}{15}\) ( mk nghĩ bn chép sai đề bài câu này )
\(\Rightarrow\left|7x-\dfrac{5}{3}\right|=-\dfrac{8}{15}-\dfrac{7}{19}\)
\(\Rightarrow\left|7x-\dfrac{5}{3}\right|=-\dfrac{257}{285}\)
\(\Rightarrow\left[{}\begin{matrix}7x-\dfrac{5}{3}=-\dfrac{257}{285}\\7x-\dfrac{5}{3}=\dfrac{257}{285}\end{matrix}\right.\)
\(\Rightarrow\left[{}\begin{matrix}x=\dfrac{218}{1995}\\x=\dfrac{244.}{665}\end{matrix}\right.\)
d) \(\left|\dfrac{1}{23}x\right|+\dfrac{18}{90}=\dfrac{18}{19}-1\dfrac{2}{5}\)
\(\left|\dfrac{1}{23}x\right|+\dfrac{18}{90}=-\dfrac{43}{95}\)
\(\left|\dfrac{1}{23}x\right|=-\dfrac{43}{95}-\dfrac{18}{90}\)
\(\left|\dfrac{1}{23}x\right|=-\dfrac{62}{95}\)
\(\Rightarrow\left[{}\begin{matrix}\dfrac{1}{23}x=\dfrac{62}{95}\\\dfrac{1}{23}x=-\dfrac{62}{95}\end{matrix}\right.\Rightarrow\left[{}\begin{matrix}x=15\dfrac{1}{95}\\x=-15\dfrac{1}{95}\end{matrix}\right.\)
\(a,3^x=\frac{9^4}{27^3}\)
\(\Leftrightarrow3^x=3^8:3^9\)
\(\Leftrightarrow3^x=3^{-1}\)
\(\Leftrightarrow x=-1\)
\(b,\frac{5^5}{5^x}=5^{18}\)
\(\Leftrightarrow5^x=5^5:5^{18}\)
\(\Leftrightarrow5^x=5^{-13}\)
\(\Leftrightarrow x=-13\)
A;3x=94/(9*3) 3=94=93*33=93*9=94
3X=94=38
X=8
B;55/5x=518=55-x
=>5-x=18
x=5-18
x=-13
\(9:27^x=\dfrac{1}{18}\)
\(\Rightarrow9:\left(3^3\right)^x=\dfrac{1}{18}\)
\(\Rightarrow3^{3x}=9:\dfrac{1}{18}\)
\(\Rightarrow3^{3x}=162\)
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