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B = \(\dfrac{3}{17}\)x \(\dfrac{2}{9}\) - \(\dfrac{2}{9}\) x \(\dfrac{3}{34}\)
B = \(\dfrac{2}{9}\) x \(\left(\dfrac{3}{17}-\dfrac{3}{34}\right)\)
B = \(\dfrac{2}{9}\) x \(\dfrac{3}{34}\)
B = \(\dfrac{1}{51}\)
=> \(\dfrac{1}{B}\) = 51
\(\frac{7}{9}\cdot\frac{3}{5}=\frac{7\cdot3}{9\cdot5}=\frac{7\cdot1}{3\cdot5}=\frac{7}{15}\)
\(\frac{9}{22}\cdot55=\frac{9}{22}\cdot\frac{55}{1}=\frac{9\cdot55}{22\cdot1}=\frac{9\cdot5}{2\cdot1}=\frac{45}{2}\)
\(\frac{11}{17}:\frac{33}{34}=\frac{11}{17}\cdot\frac{34}{33}=\frac{11\cdot34}{17\cdot33}=\frac{1\cdot2}{1\cdot3}=\frac{2}{3}\)
\(\frac{13}{2}\times\frac{27}{5}\times2\times\frac{34}{9}\times2\times\frac{2}{17}\)
\(=\frac{13\times27\times2\times34\times2\times2}{2\times5\times9\times17}\)
\(=\frac{95472}{1530}\)
\(=\frac{312}{5}=62,4\)
\(\left(\frac{9}{15}+\frac{8}{11}\right)+\frac{6}{15}=\left(\frac{9}{15}+\frac{6}{15}\right)+\frac{8}{11}\)
\(=1+\frac{8}{11}=\frac{19}{11}\)
\(\left(\frac{26}{17}+\frac{15}{34}\right)+\left(\frac{8}{17}+\frac{19}{34}\right)=\left(\frac{26}{17}+\frac{8}{17}\right)+\left(\frac{15}{34}+\frac{19}{34}\right)\)
\(=2+1=3\)
\(\left(\frac{9}{15}+\frac{8}{11}\right)+\frac{6}{15}\)
\(=\left(\frac{9}{15}+\frac{6}{15}\right)+\frac{8}{11}\)
\(=1+\frac{8}{11}\)
\(=\frac{19}{11}\)
\(\left(\frac{26}{17}+\frac{15}{34}\right)+\left(\frac{8}{17}+\frac{19}{34}\right)\)
\(=\frac{26}{17}+\frac{15}{34}+\frac{8}{17}+\frac{19}{34}\)
\(=\left(\frac{26}{17}+\frac{8}{17}\right)+\left(\frac{15}{34}+\frac{19}{34}\right)\)
\(=2+1\)
\(=3\)
\(\dfrac{7}{9}\cdot\dfrac{3}{35}=\dfrac{7}{3\cdot3}\cdot\dfrac{3}{7\cdot5}=\dfrac{1}{15}\)
\(\dfrac{9}{22}\cdot55=\dfrac{9}{11\cdot2}\cdot11\cdot5=\dfrac{45}{2}\)
\(\dfrac{11}{17}:\dfrac{33}{34}=\dfrac{11}{17}\cdot\dfrac{34}{33}=\dfrac{11\cdot17\cdot2}{17\cdot11\cdot3}=\dfrac{2}{3}\)
\(\frac{25}{24}.\frac{27}{25}.\frac{34}{9}.\frac{36}{17}\)
\(=\frac{25.9.3.17.2.4.9}{4.6.25.9.17}\)
\(=9\)
. là dấu nhân nha bn