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\(\dfrac{-5}{7}-\dfrac{9}{22}+\dfrac{5}{17}-\dfrac{13}{22}\\ =-\dfrac{5}{7}+\dfrac{5}{17}+\left(-\dfrac{9}{22}-\dfrac{13}{22}\right)\\ =-\dfrac{5}{7}+\dfrac{5}{17}-\dfrac{22}{22}\\ =-\dfrac{5}{7}+\dfrac{5}{17}-1\\ =\dfrac{-5\times17+5\times7-119}{119}\\ =\dfrac{-85+35-119}{119}=\dfrac{-169}{119}\)
a) - 2 < x < 3 = > x ∈ {0;1;2}
b) 25 32 < x < 4 => x ∈ {1;2;3}
c) – 5 < x < - 2 = > x = ∅
\(\frac{22}{25}.\left(\frac{5}{11}-\frac{8}{9}\right)-\frac{8}{9}\left(\frac{27}{4}-\frac{22}{25}\right)\)
\(\frac{22}{25}.\left(\frac{5}{11}-\frac{8}{9}\right)-\frac{8}{9}.\left(\frac{27}{4}-\frac{22}{25}\right)=\frac{22}{25}.\frac{5}{11}-\frac{22}{25}.\frac{8}{9}-\frac{8}{9}.\frac{27}{4}+\frac{8}{9}.\frac{22}{25}=\frac{2}{5}-\frac{6}{1}=\frac{-28}{5}\)
a: \(=\dfrac{3}{5}:\dfrac{7}{5}=\dfrac{3}{5}\cdot\dfrac{5}{7}=\dfrac{3}{7}\)
b: \(=\dfrac{9}{17}\left(\dfrac{8}{5}-\dfrac{3}{5}\right)+\dfrac{8}{17}\)
=9/17+8/17=1
c: =>x-3/10=7/15*1/5=7/75
=>x=7/75+3/10=59/150
a) \(\left(x+\frac{5}{3}\right)\cdot\frac{9}{13}=\frac{2}{3}\)
\(x+\frac{5}{3}=\frac{2}{3}:\frac{9}{13}\)
\(x+\frac{5}{13}=\frac{26}{27}\)
\(x=\frac{5}{13}-\frac{26}{27}\)
\(x=\frac{-203}{351}\)
b) \(43770:x=560-434\)
\(43770:x=126\)
\(x=43770:126\)
\(x=\frac{7295}{21}\)
c) \(x:3\frac{1}{3}=2\frac{2}{5}+\frac{7}{10}\)
\(x:\frac{10}{3}=\frac{12}{5}+\frac{7}{10}\)
\(x:\frac{10}{3}=\frac{31}{10}\)
\(x=\frac{31}{10}\cdot\frac{10}{3}\)
\(x=\frac{31}{3}\)
a) =(-4).(-25).125.(-8).(-11)
= 100.(-1000).(-11)
= (-100000).(-11)
= 1100000
b) =(-823)+823 . 812-812.823
=(-823)+(823.812-812.823)
= (-823) +0
=-823
k giùm mình nha!
Hok tốt!
