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8x3333/2424x54
=8x 3333:303/2424:303 x54 (Vì 3333/2424 chưa rút gọn)
=8x11/8x54
=11x54=594
\(\frac{121212}{141414}\times\frac{1313}{1212}\times\frac{2424}{2424}\)
\(=\frac{6}{7}\times\frac{13}{12}\times1\)
\(=\frac{13}{14}\)
~ Hok tốt ~
\(2018\times\left(\frac{1}{2}+\frac{1212}{2424}\right)=2018\times\left(\frac{1}{2}+\frac{12}{24}\right).\)
\(=2018\times\left(\frac{1}{2}+\frac{1}{2}\right)\)
\(=2018\times1=2018\)
Trả lời:
\(2018\times\left(\frac{1212}{1212}\div\frac{2424}{2424}\right)\)
\(=2018\times\left(1\div1\right)\)
\(=2018\times1\)
\(=2018\)
a) x+ \(\frac{4}{5}\)= \(\frac{4}{5}\)+ ( \(\frac{3}{7}\)+ \(\frac{3}{5}\))
x + \(\frac{4}{5}\)= \(\frac{4}{5}\)+ \(\frac{36}{35}\)
=> x = \(\frac{36}{35}\)
Vậy : x = \(\frac{36}{35}\)
b) \(\frac{4}{9}\)+\(\frac{8}{9}\)+ \(\frac{12}{9}\)+ ... + \(\frac{56}{9}\)
= \(\frac{4+8+12+...+56}{9}\)
Ta có : 4+8+12 + ... +56
Số các số hạng của dẫy số trên là : ( 56 -4) + 4 +1 = 14 ( số hạng )
=> Tổng trên = ( 4+56) x 14 : 2 = 420
=> \(\frac{4}{9}\)+ \(\frac{8}{9}\)+ ... + \(\frac{56}{9}\)= \(\frac{420}{9}\)= \(\frac{140}{3}\)
a)x=3/7+3/5=3x(1/7+1/5)=36/35
b)=(4+8+...+56)/9=(56+4)x14/9=280/3
999 x 222 - 3333 + 213 = 999 x 222 - 3333 + 9261 = 221778 - 3333 + 9261 = 218445 + 9261 = 209184
999x222-3333+213=111x(9+2) -(3333-961)
=111X11-2372
=1221-2372
=-1151
a)5/12+25/3x1/4=5/12+25/12=5/2
b)8X3333X54/2424=1439856/2424=594
C)12/5-2/5X25/6=12/5-5/3=11/15
\(\frac{12}{20}\)= \(\frac{6}{10}\)= \(\frac{3}{5}\)
\(\frac{3}{4}\)= \(\frac{9}{12}\)= \(\frac{12}{16}\)= \(\frac{15}{20}\)
\(\frac{75}{45}\)= \(\frac{15}{9}\)= \(\frac{5}{3}\)
\(\frac{3}{4}\)= \(\frac{18}{24}\)= \(\frac{12}{16}\)
12/20 = 6/10 = 3/5
3/4 = 9/12 = 12/16 = 15/20
75/45 = 15/9 = 5/3
3/4 = 18/24 = 12/16
Tk mk nha
\(a.\frac{1}{2\cdot3}+\frac{1}{3\cdot4}+\frac{1}{4\cdot5}=\frac{1}{2}-\frac{1}{3}+\frac{1}{3}-\frac{1}{4}+\frac{1}{4}-\frac{1}{5}\)
\(=\frac{1}{2}-\frac{1}{5}\)
\(=\frac{3}{10}\)
\(b.\frac{2}{2\cdot3}+\frac{2}{3\cdot4}+\frac{2}{4\cdot5}\)
\(=2\left(\frac{1}{2\cdot3}+\frac{1}{3\cdot4}+\frac{1}{4\cdot5}\right)\)
\(=2\cdot\left(\frac{1}{2}-\frac{1}{3}+\frac{1}{3}-\frac{1}{4}+\frac{1}{4}-\frac{1}{5}\right)\)
\(=2\cdot\left(\frac{1}{2}-\frac{1}{5}\right)\)
\(=2\cdot\frac{3}{10}=\frac{3}{5}\)
\(c.\frac{1}{2\cdot3}+\frac{2}{3\cdot5}+\frac{3}{5\cdot8}\)
\(=\frac{1}{6}+\frac{2}{15}+\frac{3}{40}\)
\(=\frac{3}{8}\)
k nha 500 AE
a, \(\frac{1}{2\times3}+\frac{1}{3\times4}+\frac{1}{4\times5}\)
\(=\frac{3-2}{2\times3}+\frac{4-3}{3\times4}+\frac{5-4}{4\times5}\)
\(=\frac{1}{2}-\frac{1}{3}+\frac{1}{3}-\frac{1}{4}+\frac{1}{4}-\frac{1}{5}\)
\(=\frac{1}{2}-\frac{1}{5}\)
\(=\frac{3}{10}\)
b, \(\frac{2}{2\times3}+\frac{2}{3\times4}+\frac{2}{4\times5}\)
\(=\frac{3-2}{2\times3}+\frac{4-3}{3\times4}+\frac{5-4}{4\times5}\)
\(=\left(\frac{1}{2}-\frac{1}{3}+\frac{1}{3}-\frac{1}{4}+\frac{1}{4}-\frac{1}{5}\right)\times\frac{2}{1}\)
\(=\left(\frac{1}{2}-\frac{1}{5}\right)\times\frac{2}{1}\)
\(=\frac{3}{10}\times\frac{2}{1}\)
\(=\frac{3}{5}\)
c, \(\frac{1}{2\times3}+\frac{2}{3\times5}+\frac{3}{5\times8}\)
\(=\frac{3-2}{2\times3}+\frac{5-3}{3\times5}+\frac{8-5}{5\times8}\)
\(=\frac{1}{2}-\frac{1}{3}+\frac{1}{3}-\frac{1}{5}+\frac{1}{5}-\frac{1}{8}\)
\(=\frac{1}{2}-\frac{1}{8}\)
\(=\frac{3}{8}\)
\(8\times\frac{3333}{2424}\times54\)
\(=8\times\frac{11}{8}\times54\)
\(=11\times54\)
\(=594\)
8x3333/2424x54
=11x54
=594
Đáp số: 594