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a: =54x(-100)=-5400
b: \(=18+\left(-200\right):4-8\cdot\left(-32\right)-1\)
=17-50+256
=-33+256
=223
a: =54x(-100)=-5400
b: \(=18+\left(-200\right):4-8\cdot\left(-32\right)-1\)
=17-50+256
=-33+256
=223
1. a) 4.415.8.25.125
= (4.25). (8.125).415
= 100.1000.415
= 100000.415
= 41500000
b) 2.31.12+4.42.6+8.27.3
= (2.31.12)+(4.42.6)+(8.27.3)
= (2.12).31+(4.6).42+(8.3).27
= 24.31+24.42+24.27
= 24 (31+42+27)
= 24.100
= 2400
\(X^2-5X=0\)
\(\Leftrightarrow X^2=5X=0\)
\(\Leftrightarrow5X=0\Rightarrow X=0\left(TM\right)\)
\(X^2=0\Rightarrow X=0\)
VẬY X=0
x^2-5x=0
=x.x-5.x=0
=x(x-5)=0
=>x=0 hoặc x-5=0
=>x=0 hoặc x=5
vậy x=0 hoặc x=5
a/6x + 4x = 2010
10x = 2010
x = 2010 : 10
x = 201
c/5x - 3x - x = 20
( 5 - 3 - 1 )x = 20
-->x = 20
d/8x - 4x = 1208
( 8 - 4 )x = 1208
2x =1208
x =1208 : 2
x = 604
e/ 2^x + 4.2^x = 5
2 ^ x ( 4 + 1 ) = 5
2 ^ x . 5 = 5
2^x = 5 : 5
2^x =1
-->x = 0
f/ ( x + 2 ) ^ 5 = 2 ^10
( x + 2 ) ^ 5 =( 2 ^ 2 )^5
( x + 2 ) ^ 5 =4 ^ 5
--> x + 2 = 4
x = 4 - 2
x = 2
b. 1404 : [118 - (4x + 6)] = 27
118 - (4x + 6) = 52
4x + 6 = 66
4x = 60
x = 15
d) \(5x^2-3x=0\)
\(\Leftrightarrow x\left(5x-3\right)=0\)
\(\Leftrightarrow\orbr{\begin{cases}x=0\\5x-3=0\end{cases}}\)
\(\Leftrightarrow\orbr{\begin{cases}x=0\\x=\frac{3}{5}\end{cases}}\)
e) \(3\left(x-1\right)+4\left(x-1\right)^2=0\)
\(\Leftrightarrow\left(x-1\right)\left[3-4.\left(x-1\right)\right]=0\)
\(\Leftrightarrow\orbr{\begin{cases}x-1=0\\3-4\left(x-1\right)=0\end{cases}}\)
\(\Leftrightarrow\orbr{\begin{cases}x=1\\4\left(x-1\right)=3\end{cases}}\)
\(\Leftrightarrow\orbr{\begin{cases}x=1\\x-1=\frac{3}{4}\Rightarrow x=\frac{7}{4}\end{cases}}\)
f) \(2\left(x-2\right)^2=\left(x-2\right)\)
\(\Leftrightarrow\orbr{\begin{cases}x-2=0\\2\left(x-2\right)-1=0\end{cases}}\)
\(\Leftrightarrow\orbr{\begin{cases}x=2\\x-2=\frac{1}{2}\Rightarrow x=\frac{5}{2}\end{cases}}\)
g) \(\left(x-2020\right)^4=\left(x-2020\right)^2\)
\(\Leftrightarrow\orbr{\begin{cases}\left(x-2020\right)^2=0\\\left(x-2020\right)^2-1=0\end{cases}}\)
\(\Leftrightarrow\orbr{\begin{cases}x=2020\\x=2019,x=2021\end{cases}}\)
\(8x^2-5x=0\)
=> x(8x-5)=0
=> \(\left[{}\begin{matrix}x=0\\8x-5=0\end{matrix}\right.\)
=> x = 5 và x = 5/8
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