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0,81x8,4+2,6x0,81
= 0,81x(8,4+2,6)
=0,81x11
=8,91
16,5x47,8+47,8x3,5
=47,8x(16,5+3,5)
=47,8x20
=956
nho h cho mk nhe
a, 0,81 x 8,4 + 2,6 x 0,81
= 0,81 x ( 8,4 + 2,6 )
= 0,81 x 11
= 8,91
b, 16,5 x 47,8 + 47,8 x 3,5
= 47,8 x ( 16,5 + 3,5 )
= 47,8 x 20
= 956
![](https://rs.olm.vn/images/avt/0.png?1311)
x(3-x)=0
Th1: x=0
Th2: 3-x=0 => x=3
Vậy x=0 và x=3
(x+2)(4x-8)=0
Th1: x+2= 0 => x=-2
Th2: 4x-8 =0 => 4x =8
x= 2
Vậy x= +- 2 (cộng trừ 2 nhé)
(x+1)+(x+2)+(x+3)+....+(x+199)=5750
199x +(1+2+3+...199) =5750
199x+ {(199+1)* [(199-1)+1] : 2} =5750
199x + 19900= 5750
199x = -14150
x= -14150/199
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1) 5(x - 2) + 27 = 4x - 8
=> 5x - 10 + 27 = 4x - 8
=> 5x + 17 = 4x - 8
=> 5x - 4x = -8 - 17
=> x = -25
2) 3(x + 1) + 2(x + 2) = -13
=> 3x + 3 + 2x + 4 = -13
=> 5x + 7 = -13
=> 5x = -13 - 7
=> 5x = -20
=> x = -20 : 5
=> x = -4
3) (2x + 4)(5 - x) = 0
=> \(\orbr{\begin{cases}2x+4=0\\5-x=0\end{cases}}\)
=> \(\orbr{\begin{cases}2x=-4\\x=5\end{cases}}\)
=> \(\orbr{\begin{cases}x=-2\\x=5\end{cases}}\)
Vậy ...
4) x2 - 3x = 0
=> x(x - 3) = 0
=> \(\orbr{\begin{cases}x=0\\x-3=0\end{cases}}\)
=> \(\orbr{\begin{cases}x=0\\x=3\end{cases}}\)
Vậy ...
5) x2 - 3x + 2 = 0
=> x(x - 3) = -2
=> x(x - 3) = 1 . (1 - 3)
=> x = 1
![](https://rs.olm.vn/images/avt/0.png?1311)
![](https://rs.olm.vn/images/avt/0.png?1311)
9,3 x 6,7 + 9,3 x 3,3 = 9,3 x ( 6,7 + 3,3 )
= 9,3 x 10
= 93
7,8 x 0,35 + 0,35 x 2,2 = 0,35 x ( 7,8 + 2,2 )
= 0,35 x 10
= 3,5
Đáp án là:
a) 9,3 x 6,7 + 9,3 x 3,3
= 9,3 x (6,7+3,3)
= 9,3 x 10
= 93.
b) 7,8 x 0,35 + 0,35 x 2,2
= 0,35 x (7,8+2,2)
= 0,35 x 10
= 35
![](https://rs.olm.vn/images/avt/0.png?1311)
\(25\cdot\left\{8\cdot\left[12-4+8\left(16\div80\right)\right]\right\}\)
\(=25\cdot\left\{8\cdot\left[12-4+8\cdot0,2\right]\right\}\)
\(=25\cdot\left\{8\cdot8+1,6\right\}\)
\(=25\cdot\left(64+1,6\right)\)
\(=25\cdot65,6=1640\)
b)\(2016\cdot0+1\left(207+\frac{0}{4579}\right)=0+1\cdot207=207\)
c)\(15\cdot\left\{2100\div\left[251-\left(16+84\cdot2\right)\right]\right\}\)
\(=15\cdot\left\{2100\div\left[251-\left(16+168\right)\right]\right\}\)
\(=15\cdot\left\{2100\div\left[251-184\right]\right\}\)
\(=15\cdot\left(2100\div67\right)\)
\(=15\cdot\frac{2100}{67}=\frac{31500}{67}\)
![](https://rs.olm.vn/images/avt/0.png?1311)
0, 9 x 95 + 1, 8 x 2 + 0, 9
= 0,9 x 95 + 0,9 x 2 x 2 + 0,9
= 0,9 x 95 + 0,9 x 4 + 0,9
= 0,94 x ( 95 + 4 + 1 )
= 0,94 x 100
= 94
Nhớ k cho mk nha ^_^
=0.9 x 95 +0.9 x 2 x 2 + 0.9 x 1
=0.9 x (95+4+1)
=0.9 x 100
=90
![](https://rs.olm.vn/images/avt/0.png?1311)
a) \(15-5\left|x+4\right|=-12-3\)
\(\Leftrightarrow5\left|x+4\right|=30\)
\(\Leftrightarrow\left|x+4\right|=6\)
\(\Leftrightarrow\orbr{\begin{cases}x+4=6\\x+4=-6\end{cases}}\Leftrightarrow\orbr{\begin{cases}x=2\\x=-10\end{cases}}\)
b) \(\left(4x-8\right)\left(7-x\right)=0\Leftrightarrow\orbr{\begin{cases}4x-8=0\\7-x=0\end{cases}}\Leftrightarrow\orbr{\begin{cases}x=2\\x=7\end{cases}}\)
c) \(\left(x^2-36\right)\left(x^2+5\right)=0\Rightarrow\left(x-6\right)\left(x+6\right)=0\)
\(\Leftrightarrow\orbr{\begin{cases}x-6=0\\x+6=0\end{cases}}\Leftrightarrow\orbr{\begin{cases}x=6\\x=-6\end{cases}}\)
d) \(-3\left(x+7\right)-11=2\left(x+5\right)\)
\(\Leftrightarrow-3x-32=2x+10\)
\(\Leftrightarrow5x=-42\Rightarrow x=-\frac{42}{5}\)
8 x ( x - 2 ) = 0
x - 2 = 0 : 8
x - 2 = 0
x = 0 + 2
x = 2