K
Khách
Hãy nhập câu hỏi của bạn vào đây, nếu là tài khoản VIP, bạn sẽ được ưu tiên trả lời.
Các câu hỏi dưới đây có thể giống với câu hỏi trên
26 tháng 7 2019
8697-[37:35+2(13-3)]
=>8697-[32+2.10]
=>8697-[9+20]
=>8697-29=8668
26 tháng 7 2019
8697 - [ 32 + 2. 10 ]
= 8697 - [ 32 + 20 ]
= 8697 - 29
= 8668
Mk nghĩ bn nên động não 1 tí :(
Chúc bn hc tốt <3
TT
23 tháng 11 2017
2.
a,\(50-\left[\left(50-2^3.5\right):2+3\right]\)
\(=50-\left[\left(50-40\right):2+3\right]\)
\(=50-\left(10:2+3\right)\)
\(=50-8\)
\(=42\)
b,\(8697-\left[3^7:3^5+2\left(13-3\right)\right]\)
\(=8697-\left(3^2+2.10\right)\)
\(=8697-\left(9+20\right)\)
\(=8697-29\)
\(=8668\)
c,\(205-\left[1200-\left(4^2-2.3\right)^3\right]:40\)
\(=205-200:40\)
\(=200\)
NN
24 tháng 11 2017
2)
a) \(50-\left[\left(50-2^3.5\right):2+3\right]\)
\(=50-\left[\left(50-8.5\right):2+3\right]\)
\(=50-\left[\left(50-40\right):2+3\right]\)
\(=50-\left(10:2+3\right)\)
\(=50-\left(5+3\right)\)
\(=50-8\)
\(=42\)
b) \(8697-\left[3^7:3^5+2\left(13-3\right)\right]\)
\(=8697-\left(3^7:3^5+2.10\right)\)
\(=8697-\left(3^{7-5}+2.10\right)\)
\(=8697-\left(3^2+2.10\right)\)
\(=8697-\left(9+2.10\right)\)
\(=8697-\left(9+20\right)\)
\(=8697-29\)
\(=8668\)
c) \(205-\left[1200-\left(4^2-2.3\right)^3\right]:40\)
\(=205-\left[1200-\left(16-2.3\right)^3\right]:40\)
\(=205-\left[1200-\left(16-6\right)^3\right]:40\)
\(=205-\left(1200-10^3\right):40\)
\(=205-\left(1200-1000\right):40\)
\(=205-200:40\)
\(=205-5\)
\(=200\)
HD
28 tháng 7 2017
\(a)47-\left[\left(45.2^4-5^2.12\right):14\right]\)
\(=47-\left[\left(45.16-25.12\right):14\right]\)
\(=47-\left[\left(720-300\right):14\right]\)
\(=47-\left[420:14\right]\)
\(=47-30\)
\(=17\)
\(b)50-\left[\left(20-2^3\right):2+34\right]\)
\(=50-\left[\left(20-8\right)\right]:2+34\)
\(=50-\left[12:2+34\right]\)
\(=50-\left[6+34\right]\)
\(=50-40\)
\(=10\)
\(c)10^2-\left[60:\left(5^6:5^4-3,5\right)\right]\)
\(=10^2-\left[60:\left(5^2-3,5\right)\right]\)
\(=10^2-\left[60:\left(25-3,5\right)\right]\)
\(=10^2-\left[60:21,5\right]\)
\(=100-\dfrac{120}{43}\)
\(=\dfrac{4180}{43}\)
\(d)50-\left[\left(50-2^3.5\right):2+3\right]\)
\(=50-\left[\left(50-8.5\right):2+3\right]\)
\(=50-\left[\left(50-40\right):2+3\right]\)
\(=50-\left[10:2+3\right]\)
\(=50-5+3\)
\(=50-8\)
\(=42\)
\(e)10-\left[\left(8^2-48\right).5+\left(2^3.10+8\right)\right]:28\)
\(=10-\left[\left(64-48\right).5+\left(8.10+8\right)\right]:28\)
\(=10-\left[16.5+\left(80+8\right)\right]:28\)
\(=10-\left[80+88\right]:28\)
\(=10-168:28\)
\(=10-6\)
\(=4\)
\(f)8697-\left[3^7:3^5+2.\left(13-3\right)\right]\)
\(=8697-\left[3^2+2.\left(13-3\right)\right]\)
\(=8697-\left[9+2.10\right]\)
\(=8697-9+20\)
\(=8697-29\)
\(=8668\)
\(g)2011+5\left[300-\left(17-7\right)^2\right]\)
\(=2011+5.\left[300-10^2\right]\)
\(=2011+5.\left[300-100\right]\)
\(=2011+5.200\)
\(=2011+1000\)
\(=3011\)
\(h)695-\left[200+\left(11-1\right)^2\right]\)
\(=695-\left[200+10^2\right]\)
\(=695-200+100\)
\(=695-300\)
\(=395\)
\(i)129-5\left[29-\left(6-1\right)^2\right]\)
\(=129-5\left[29-5^2\right]\)
\(=129-5\left[29-25\right]\)
\(=129-5.4\)
\(=129-20\)
\(=109\)
10 tháng 11 2017
a) 47 - [(45.16 - 25.12 ) : 14]
= 47 - [ (720 - 300 ) : 14
= 47 - [ 420 : 14 ]
= 47 - 30
= 17
b) 50 - [ (20 - 8 ) : 2 + 34 ]
= 50 - [ 12 : 2 + 34 ]
= 50 - [ 6 + 34 ]
= 50 - 40
= 10
c) 100 - [ 60 : ( 15625 : 625 - 15 )
= 100 - [ 60 : ( 25 - 15 ) ]
= 100 - [ 60 : 10 ]
= 100 - 6
= 94
4 tháng 7 2018
d)50-[(50-235)/2+3
=50-(10/2+3)
=50-8
=42
minh chi giupban duoc den do thoi ha
2 tháng 3 2018
cơ bản giống nhau nhé
Lời giải cho ý (D) các câu khác tương tự
\(D=13^1+13^3+13^5+...+13^{99}\)
\(13^2.D=13^3+13^5+13^7...+13^{99+2}\)
\(\left(13^2-1\right)D=13^3+13^5+13^7+...+13^{101}-\left(13^1+13^3+13^5+...+13^{99}\right)\)
\(D=\dfrac{13^{101}-13}{13^2-1}\)
KT
2 tháng 3 2018
\(A=2+2^3+2^5+2^7+2^9+...+2^{2009}\)
\(\Leftrightarrow\)\(4A=2^3+2^5+2^7+2^9+2^{11}+...+2^{2011}\)
\(\Leftrightarrow\)\(4A-A=\left(2^3+2^5+2^7+...+2^{2011}\right)-\left(2+2^3+2^5+...+2^{2009}\right)\)
\(\Leftrightarrow\)\(3A=2^{2011}-2\)
\(\Leftrightarrow\)\(A=\frac{2^{2011}-2}{3}\)
2 tháng 3 2018
Ta có :
\(A=2+2^3+2^5+...+2^{2009}\)
\(4A=2^3+2^5+2^7+...+2^{2011}\)
\(4A-A=\left(2^3+2^5+2^7+...+2^{2011}\right)-\left(2+2^3+2^5+...+2^{2009}\right)\)
\(3A=2^{2011}-2\)
\(A=\frac{2^{2011}-2}{3}\)
Vậy \(A=\frac{2^{2011}-2}{3}\)
Câu b) dễ hơn nữa làm tương tư câu a) nhưng B nhân cho 2
Câu c) thì C nhân cho 5
Câu d) thì D nhân cho 169
8697-[37:35+2(13-3)]
= 8697- [ 9 + 2.10 ]
= 8697- ( 9 + 20)
= 8697- 29
= 8668
`8697 - [3^7 : 3^5 + 2.(13-3)]`
`=8697 - [3^7 : 3^5 + 2.10]`
`=8697 - [3^2 + 20]`
`=8697 - [9 +20]`
`=8697 - 29`
`=8668`