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a)
\(8^4.16^5.32=2^{12}.2^{20}.2^5=2^{37}\)
b)
\(27^4.81^{10}=3^{12}.3^{40}=3^{52}\)
a) \(\frac{18^4.3^2.8^3}{27^3.16^2}=\frac{\left(2.3^2\right)^4.3^2.\left(2^3\right)^3}{\left(3^3\right)^3.\left(2^4\right)^2}=\frac{2^4.2^9.3^8.3^2}{3^9.2^8}=\frac{2^{13}.3^{10}}{3^9.2^8}=3.2^5=96\)
b) \(\frac{35^5.9^3.8^5}{81^4.32^5}=\frac{35^5.\left(3^2\right)^3.\left(2^3\right)^5}{\left(3^4\right)^4.\left(2^5\right)^5}=\frac{35^5.3^6.2^{15}}{3^{16}.2^{25}}=\frac{35^5}{3^{10}.2^{10}}=\frac{35^5}{6^{10}}\)
c) \(\frac{48^5.18^2}{81^2.34^4}=\frac{\left(2^4.3\right)^5.\left(2.3^2\right)^2}{\left(3^4\right)^2.\left(2.17\right)^4}=\frac{2^{20}.3^5.2^2.3^4}{3^8.2^4.17^4}=\frac{2^{22}.3^9}{3^8.2^4.17^4}=\frac{2^{18}.3}{17^4}\)
d) \(\frac{54^7.27^3.16^2}{243^2.64^3}=\frac{\left(2.3^3\right)^7.\left(3^3\right)^3.\left(2^4\right)^2}{\left(3^5\right)^2.\left(2^6\right)^3}=\frac{2^7.3^{21}.3^9.2^8}{3^{10}.2^{18}}=\frac{2^{15}.3^{30}}{3^{10}.2^{18}}=\frac{3^{20}}{2^3}\)
84 x 165 x 32
= (23)4 x (24)5 x 25
= 212 x 220 x 25
= 237
X x X4 x X7 x ... x X100
= X1 + 4 + 7 + ... + 100
Câu b mk chỉ gợi ý thôi nhé! Phần còn lại bn tự tính nhé!
\(2^{37}\)
\(\left[\left(100-1\right):3+1\right].\)\(\left(100+1\right):2=1717\)
a) 42 . 121 - 42 . 22 + 42
= 42 . 121 - 42 . 22 + 42 . 1
= 42 . ( 121 - 22 + 1 )
= 42 . 100
= 16 . 100
= 1600
b) 600 - 400 : [ 118 . 2 - ( 50 . 3 - 9 . 16 )2 ]
= 600 - 400 : [ 118 . 2 - ( 150 - 144 )2 ]
= 600 - 400 : ( 118 . 2 - 62 )
= 600 - 400 : ( 236 - 36 )
= 600 - 400 : 200
= 600 - 2
= 598
c) |- 15 + 10|+|( - 48 ) + ( - 22 )|+ ( - 100 )
= |- 5|+|- 70|+ ( - 100 )
= 5 + 70 + ( - 100 )
= 75 + ( - 100 )
= - 25
d) 52 - ( - 8 ) -|- 17|
= 25 - ( - 8 ) - 17
= 25 + 8 - 17
= 33 - 17
= 16
Tick cho mình nhé!!!
Chúc bạn học tốt!!!
Ta có :
- A = (25)8 x 410
- A = 240 x ( 22)10
- A = 240 x 220
- A = 240+20
- A = 260
Lại có
- B = 20 x 410 x 812 x 16
- B = 20 x (22)10 x ( 23)12 x 24
- B = 20 x 220 x 236 x 24
- B = 20+20+36+4
- B = 260
Vì A = 260 và B = 260 nên A = B
Vậy A = B
a) \(27=3^3\Rightarrow3^n=3^3\Leftrightarrow n=3\)
b) \(625=5^4\Rightarrow5^n=5^4\Leftrightarrow n=4\)
c) \(144=12^2\Rightarrow12^n=12^2\Leftrightarrow n=2\)
d) \(128=8.16=2^3.16\Leftrightarrow2^n.16=2^3.16\Leftrightarrow n=3\)
a, \(\frac{25^{11}.4^{33}}{8^{15}.10^{22}}=\frac{\left(5^2\right)^{11}.\left(2^2\right)^{33}}{\left(2^3\right)^{15}.\left(2.5\right)^{22}}=\frac{5^{22}.2^{66}}{2^{45}.2^{22}.5^{22}}=\frac{5^{22}.2^{66}}{2^{67}.5^{22}}=\frac{1}{2}\)
b,\(\frac{8^4.5^8.9^3}{125^3.4^7.27}=\frac{\left(2^3\right)^4.5^8.\left(3^2\right)^3}{\left(5^3\right)^3.\left(2^2\right)^7.3^3}=\frac{2^{12}.5^8.3^6}{5^9.2^{14}.3^3}=\frac{3^3}{5.2^2}=\frac{27}{20}\)
Bạn làm nốt nhé cũng tương tự thôi !!!!!!!!!
\(A=18^{15}-\frac{8^5.9^{14}.5}{4^8}.27^{10}-4^7.3^{31}=\left(2.3^2\right)^{15}-\frac{\left(2^3\right)^5.\left(3^2\right)^{14}.5}{\left(2^2\right)^8}.\left(3^3\right)^{10}-\left(2^2\right)^7.3^{31}\)
\(=2^{15}.3^{30}-\frac{2^{15}.3^{28}.5}{2^{16}}.3^{30}-2^{14}.3^{31}\)
\(=2^{15}.3^{30}-\frac{3^{58}.5}{2}-2^{14}.3^{31}\)
\(=2^{14}.3^{30}\left(2-3\right)-\frac{3^{58}.5}{2}=-1.2^{14}.3^{30}-\frac{3^{58}.5}{2}=-1.2^{15}.3^{30}-3^{58}.5\)
\(=3^{30}\left(-1.2^{15}-3^{28}.5\right)\)