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a)=24.156+24.444+24.400
=24(156+444+400)
=24.1000
=24000
b)=64.6+3.27.2.2+17.6
=64.6+54.6+17.6
=6(64+54+17)
=6.135
=810
1=???
2=(4x25)x37=100x37=3700
3=33750
4=28x(64+36)=28x100=2800
5=14386
6=810
7=(43x[42+57+1])-90=4300-90=4210
8=2772
a,4.37.25
=(4.25)+25
=100+25
=125
đó tui giải câu a thu
mấy câu khác dễ ợt
a,43.27 + 93.43+ 57.61 + 59.57
=43.(27+93)+57.(61+59)
=43.120+57.120
=(43+57).120
=100.120
=12000
b,16.41 + 37.34 + 11.41 + 25.37
=41.(16+11)+37.(34+25)
=41.27+37.59
=1107+2183
=3290
c,23.39 + 58.35 + 25.39 +26.58
=(23+25).39+58.(35+26)
=48.39+58.61
=1872+3538
=5410
d,36.6 + 6.37 + 31.73 + 73.23
=(37+36).6 + (31+23).73
=73.6 + 54.73
=73.(6+54)
=73.60
=133
**** nhes
e,64.6 + 81.4 + 17.6
a,43.27 + 93.43+ 57.61 + 59.57
=43.(27+93)+57.(61+59)
=43.120+57.120
=(43+57).120
=100.120
=12000
b,16.41 + 37.34 + 11.41 + 25.37
=41.(16+11)+37.(34+25)
=41.27+37.59
=1107+2183
=3290
c,23.39 + 58.35 + 25.39 +26.58
=(23+25).39+58.(35+26)
=48.39+58.61
=1872+3538
=5410
d,36.6 + 6.37 + 31.73 + 73.23
=(37+36).6 + (31+23).73
=73.6 + 54.73
=73.(6+54)
=73.60
=133
Bài giải
\(\frac{2}{3}+\frac{3}{4}+\frac{4}{5}=\frac{40}{60}+\frac{45}{60}+\frac{48}{60}=\frac{133}{60}\)
\(\frac{8}{5}+\frac{7}{6}+\frac{10}{9}+\frac{1}{2}=\frac{144}{90}+\frac{105}{90}+\frac{100}{90}+\frac{45}{90}=\frac{394}{90}\)
\(\frac{15}{17}-\frac{11}{13}+\frac{3}{26}=\frac{390}{442}+\frac{374}{442}+\frac{51}{442}=\frac{815}{442}\)
\(\frac{9}{12}\text{ x }\frac{4}{3}\text{ : }\frac{8}{5}=\frac{9}{12}\text{ x }\frac{4}{3}\text{ x }\frac{5}{8}=\frac{9\text{ x }4\text{ x }5}{12\text{ x }3\text{ x }8}=\frac{5}{8}\)
\(\frac{4}{5}\text{ x }\frac{15}{8}\text{ : }\frac{5}{7}=\frac{4}{5}\text{ x }\frac{15}{8}\text{ x }\frac{7}{5}=\frac{4\text{ x }15\text{ x }7}{5\text{ x }8\text{ x }5}=\frac{21}{10}\)
\(\frac{2}{3}+\frac{3}{4}+\frac{4}{5}=\frac{40}{60}+\frac{45}{60}+\frac{48}{60}=\frac{133}{60}\)
\(\frac{8}{5}+\frac{7}{6}+\frac{10}{9}+\frac{1}{2}=\frac{144}{90}+\frac{105}{90}+\frac{100}{90}+\frac{45}{90}=\frac{197}{45}\)
\(\frac{15}{17}-\frac{11}{13}+\frac{1}{26}=\frac{390}{442}+\frac{374}{442}+\frac{51}{442}=\frac{815}{442}\)
\(\frac{9}{12}\times\frac{4}{3}:\frac{8}{5}=1:\frac{8}{5}=\frac{5}{8}\)
\(\frac{4}{5}\times\frac{15}{8}:\frac{5}{7}=\frac{3}{2}:\frac{5}{7}=\frac{21}{10}\)
\(\frac{5}{9}\times\frac{12}{7}=\frac{5\times12}{9\times7}=\frac{5\times4\times3}{3\times3\times7}=\frac{20}{21}\)
\(\frac{6}{5}:\frac{8}{3}=\frac{6}{5}\times\frac{8}{3}=\frac{2\times3\times8}{5\times3}=\frac{16}{5}\)
\(\frac{9}{20}\times\frac{5}{12}=\frac{3\times3\times5}{4\times5\times4\times3}=\frac{3}{16}\)
\(\frac{15}{16}:\frac{25}{24}=\frac{15}{16}\times\frac{24}{25}=\frac{3\times5\times4\times2\times3}{4\times2\times2\times5\times5}=\frac{9}{10}\)
\(14\times\frac{5}{21}=\frac{2\times7\times5}{3\times7}=\frac{10}{3}\)
\(10:\frac{5}{3}=10\times\frac{3}{5}=\frac{2\times5\times3}{5}=6\)
\(\frac{5}{3}:10=\frac{5}{3}\times\frac{1}{10}=\frac{5}{3\times2\times5}=\frac{1}{6}\)
= 81x(17-15)/ 81x(17+4)= 81x2/ 81x21= 2/21
xẹc ngang là dấu / nhé
=81x(17-15)/81x(17+4)=81x2/=81x21=2/21