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\(50\%+\dfrac{7}{12}-\dfrac{1}{2}\)
\(=\dfrac{1}{2}+\dfrac{7}{12}-\dfrac{1}{2}\)
\(=\left(\dfrac{1}{2}-\dfrac{1}{2}\right)+\dfrac{7}{12}\)
\(=\dfrac{7}{12}\)
_______________
\(2022\cdot67+2022\cdot43-2022\cdot10\)
\(=2022\cdot\left(67+43-10\right)\)
\(=2022\cdot100\)
\(=202200\)
_____________________
\(10,3+6,9+8,7+13,1\)
\(=\left(13,1+6,9\right)+\left(10,3+8,7\right)\)
\(=20+19\)
\(=39\)
___________________
\(17,58\times43+57\times17,58\)
\(=17,58\times\left(43+57\right)\)
\(=17,58\times100\)
\(=1758\)
tớ ghi sai nên cập nhật lại câu hỏi, phần 3 các bạn trả lời sớm mà bị sai thì bỏ qua cho tớ nhé
\(Ư\left(5\right)=\left\{1;-1;5;-5\right\}\)
\(Ư\left(9\right)=\left\{1;-1;3;-3;9;-9\right\}\)
\(Ư\left(8\right)=\left\{1;-1;2;-2;4;-4;8;-8\right\}\)
\(Ư\left(-13\right)=\left\{1;-1;13;-13\right\}\)
\(Ư\left(1\right)=\left\{1;-1\right\}\)
\(Ư\left(-8\right)=\left\{1;-1;2;-2;4;-4;8;-8\right\}\)
\(Ư\left(5\right)=\left\{-5;-1;1;5\right\}\)
\(Ư\left(9\right)=\left\{-9;-3;-1;1;3;9\right\}\)
\(Ư\left(12\right)=\left\{-12;-6;-4;-3;-2;-1;1;2;3;4;6;12\right\}\)
\(Ư\left(13\right)=\left\{-13;-1;1;13\right\}\)
\(Ư\left(1\right)=\left\{-1;1\right\}\)
\(Ư\left(-8\right)=\left\{-8;-4;-2;-1;1;2;4;8\right\}\)
a. \(\left(5876321-999999-3876000-322\right):x=5\)
\(\Rightarrow1000000:x=5\)
\(\Rightarrow5x=1000000\)
\(\Rightarrow x=\dfrac{1000000}{5}=200000\)
Vậy \(x=200000\)
b. \(\left(7593-1997\right)x+\dfrac{1,1}{x}-5696x=\dfrac{1,1}{x}\)
\(\Rightarrow5596x-5696x=\dfrac{1,1}{x}-\dfrac{1,1}{x}=0\)
\(\Rightarrow-100x=0\)
\(\Rightarrow x=0\)
Vậy \(x=0\)
\(a\) \(1000000:x=5\)
\(x=200000\)
\(b\) \(5596.x+1,1:x-5696.x=1,1:x\)
\(x=1\)
a) ( 5 876 321 - 999 999 - 3 876 000 - 322 ) : x = 5
=> 1 000 000 : x = 5
=> x = 1 000 000 : 5 = 200 000
Vậy ...
b) ( 7 593 - 1 997 ) . x +1,1/x - 5696x = 1,1/x
=> 7593x + 1,1/x - 5696x - 1,1/x = 0
=> ( 7593x - 5696x ) + (1,1/x-1,1/x) = 0
=> 1897x + 0 = 0
=> 1897x = 0
=> x = 0 : 1897 = 0
Vậy x = 0
\(x:\left(1,1x-9\right).\frac{1}{5}=40\%\)
\(x:\left(1,1x-9\right)=2\)
\(x=2.\left(1,1x-9\right)\)
\(x=2,2x-18\)
\(-1,2x=-18\)
\(x=15\)
ĐK : \(7x\ge0\Leftrightarrow x\ge0\)
Với \(x\ge0\)thì \(x+1,1>0;x+2,2>0;x+3,3>0;x+4,4>0;x+5,5>0\)
=> |x + 1,1| = x + 1,1
|x + 2,2| = x + 2,2
|x + 3,3| = x + 3,3
|x + 4,4| = x + 4,4
|x + 5,5| = x + 5,5
Khi đó |x + 1,1| + |x + 2,2| + |x + 3,3| + |x + 4,4| + |x + 5,5| = 7x
<=> x + 1,1 + x + 2,2 + x + 3,3 + x + 4,4 + x + 5,5 = 7x
<=> 5x + 16,5 = 7x
<=> 2x = 16,5
<=> x = 8,25
Vậy x = 8,25
`5,17 : ( -1,3) + 1,43. 1,1 + 39. 0,143 + 7,83 : (-1,3)`
`=5,17 .(-10)/(13) + 7,83 .(-10)/13 +0,143.11 + 39. 0,143 `
`= (-10)/13 .( 5,17+7,83) + 0,143.(11+39)`
`= -10 + 7,15`
`=-2,85`
5,17:(−1,3)+1,43.1,1+39.0,143+7,83:(−1,3)=(5,17+7,83):(−1,3)+1,43.1,1+1,43.3,9=(5,17+7,83):(−1,3)+1,43(1,1+3,9)=13:(−1,3)+1,43.5=−10+7,15=−2,85
`@` `\text {Ans}`
`\downarrow`
`79,52 \div x - 1,1 = 13,1`
`\Rightarrow 79,52 \div x = 13,1 + 1,1`
`\Rightarrow 79,52 \div x =14,2`
`\Rightarrow x = 79,52 \div 14,2`
`\Rightarrow x = 5,6`
Vậy, `x =5,6`
5.6 nhe bn