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NH
18 tháng 4 2018
\(A=\frac{\left(23\frac{11}{15}-26\frac{13}{20}\right)}{12^2+5^2}\cdot\frac{1-\frac{1}{30}-\frac{1}{42}-\frac{1}{56}}{3^2.13.2-13.5}-\frac{19}{37}\)
\(A=\frac{\left(23+\frac{11}{15}-26+\frac{13}{20}\right)}{144+25}\cdot\frac{1-\frac{1}{5.6}-\frac{1}{6.7}-\frac{1}{7.8}}{9.13.2-13.5}-\frac{19}{37}\)
\(A=\frac{\left(23+26+\frac{11}{15}-\frac{13}{20}\right)}{169}\cdot\frac{1-\left(\frac{1}{5}-\frac{1}{6}\right)-\left(\frac{1}{6}-\frac{1}{7}\right)-\left(\frac{1}{7}-\frac{1}{8}\right)}{13.\left(9.2-5\right)}-\frac{19}{37}\)
\(A=\frac{49+\frac{44}{60}-\frac{39}{60}}{169}\cdot\frac{1-\frac{1}{5}+\frac{1}{6}-\frac{1}{6}+\frac{1}{7}-\frac{1}{7}+\frac{1}{8}}{13.13}-\frac{19}{37}\)
\(A=\frac{49+\frac{1}{20}}{169}\cdot\frac{1-\frac{1}{5}+\frac{1}{8}}{169}-\frac{19}{37}\)
\(A=\frac{49\frac{1}{20}}{169}\cdot\frac{\frac{4}{5}+\frac{5}{40}}{169}-\frac{19}{37}\)
\(A=\frac{981}{169}\cdot\frac{\frac{32}{40}+\frac{5}{40}}{169}-\frac{19}{37}\)
\(A=\frac{981}{169}\cdot\frac{\frac{37}{40}}{169}-\frac{19}{37}\)
\(A=\frac{981.\frac{37}{40}}{169^2}-\frac{19}{37}\)
\(A=\frac{\frac{36297}{40}}{28561}-\frac{19}{37}\)
\(A=\frac{907,425}{28561}-\frac{19}{37}\)
\(A=\frac{33574,725}{1056757}-\frac{542659}{1056757}\)
\(A=\frac{-509084,275}{1056757}=-0,04604282...\)
Mik chỉ làm đc thế này thôi, ôn thi học kì II tốt nha bạn!
KB
3 tháng 4 2016
\(\frac{1}{8}.15\frac{2}{5}+1\frac{4}{5}.\frac{1}{8}-17\frac{1}{5}.\frac{1}{8}\)
=\(\frac{77}{40}+\frac{9}{40}-\frac{86}{40}\)
=\(\frac{0}{40}=0\)
3 tháng 4 2016
\(\frac{1}{8}.15\frac{2}{5}+1\frac{4}{5}.\frac{1}{8}-17\frac{1}{5}.\frac{1}{8}\)
\(\frac{1}{8}.\left(15\frac{2}{5}+1\frac{4}{5}-17\frac{1}{5}\right)\)
\(\frac{1}{8}.\left(\left(15+1-17\right)+\left(\frac{2}{5}+\frac{4}{5}-\frac{1}{5}\right)\right)\)
\(\frac{1}{8}.\left(\left(-1\right)+1\right)\)
\(\frac{1}{8}.0\)
\(0\)
TT
2
3 tháng 4 2016
\(\frac{5}{6}-x=\frac{-7}{12}+\frac{2}{3}\)
\(\frac{5}{6}-x=\frac{-7}{12}+\frac{8}{12}\)
\(\frac{5}{6}-x=\frac{1}{12}\)
\(x=\frac{5}{6}-\frac{1}{12}\)
\(x=\frac{10}{12}-\frac{1}{12}\)
\(x=\frac{9}{12}\) \(=\frac{3}{4}\)
3 tháng 4 2016
<=> 5/6 - x = 1/12
<=> -x = 1/12 - 5/6
<=> -x = -3/4
=> x = 3/4
Vậy x = 3/4
23 tháng 7 2023
`@` `\text {Ans}`
`\downarrow`
`a)`
\(\left(\dfrac{7}{8}-\dfrac{3}{4}\right)\cdot1\dfrac{1}{3}-\dfrac{2}{3}\cdot0,5\)
`=`\(\dfrac{1}{8}\cdot\dfrac{4}{3}-\dfrac{1}{3}\)
`=`\(\dfrac{1}{6}-\dfrac{1}{3}=-\dfrac{1}{6}\)
`b)`
\(\left(2+\dfrac{5}{6}\right)\div1\dfrac{1}{5}+\left(-\dfrac{7}{12}\right)\)
`=`\(\dfrac{17}{6}\div1\dfrac{1}{5}-\dfrac{7}{12}\)
`=`\(\dfrac{85}{36}-\dfrac{7}{12}=\dfrac{16}{9}\)
`c)`
\(75\%-1\dfrac{1}{2}+0,5\div\dfrac{5}{12}\)
`=`\(-\dfrac{3}{4}+\dfrac{6}{5}=\dfrac{9}{20}\)
VN
Võ Ngọc Phương
VIP
23 tháng 7 2023
a) \(\left(\dfrac{7}{8}-\dfrac{3}{4}\right).1\dfrac{1}{3}-\dfrac{2}{3}.0,5\)
\(=\left(\dfrac{7}{8}-\dfrac{6}{8}\right).\dfrac{4}{3}-\dfrac{2}{3}.\dfrac{1}{2}\)
\(=\dfrac{1}{8}.\dfrac{4}{3}-\dfrac{2}{3}.\dfrac{1}{2}\)
\(=\dfrac{1}{6}-\dfrac{1}{3}\)
\(=\dfrac{-1}{6}\)
b) \(\left(2+\dfrac{5}{6}\right):1\dfrac{1}{5}+\dfrac{-7}{12}\)
\(=\left(\dfrac{12}{6}+\dfrac{5}{6}\right):\dfrac{6}{5}+\dfrac{-7}{12}\)
\(=\dfrac{17}{6}.\dfrac{5}{6}+\dfrac{-7}{12}\)
\(=\dfrac{85}{36}+\dfrac{-7}{12}\)
\(=\dfrac{16}{9}\)
c) \(75\%-1\dfrac{1}{2}+0,5:\dfrac{5}{12}\)
\(=\dfrac{3}{4}-\dfrac{3}{2}+\dfrac{1}{2}.\dfrac{12}{5}\)
\(=\dfrac{3}{4}-\dfrac{6}{4}+\dfrac{6}{5}\)
\(=\dfrac{-3}{4}+\dfrac{6}{5}\)
\(=\dfrac{9}{20}\)
20 tháng 2 2020
a) =-5/7 +7/8-2/7+1/8- -1/12+ -13/12
=(-5/7-2/7)+(7/8+1/8)-(-1/12--13/12)
=-7/7+8/8 - 12/12
= -1+1+1
=1
b)= ( -3/8+11/8)-(12/11+ -1/11)+(-3/5- 2/5)
= 1- 1 + (-1)
=-1
TT
7
KB
2 tháng 4 2016
\(\left(\frac{-1}{5}+\frac{3}{12}\right)+\frac{-3}{4}\)
\(=\left(\frac{-1}{5}+\frac{1}{4}\right)+\frac{-3}{4}\)
\(=\frac{-1}{5}+\frac{1}{4}+\frac{-3}{4}\)
\(=\frac{-1}{5}+\frac{-1}{2}\)
\(=\frac{-2}{10}+\frac{-5}{10}\)
\(=\frac{-7}{10}\)
LT
3
27 tháng 4 2019
\(=\frac{75}{100}-\frac{3}{2}+\frac{1}{2}:\frac{5}{12}-\left(-\frac{1}{3}\right)^2\)
\(=\frac{3}{4}-\frac{3}{2}+\frac{6}{5}-\frac{1}{9}\)
\(=\frac{-3}{4}+\frac{6}{5}-\frac{1}{9}\)
\(=\frac{9}{20}-\frac{1}{9}\)
\(=\frac{61}{180}\)
27 tháng 4 2019
\(\frac{75}{100}-1\frac{1}{2}+0,5:\frac{5}{12}-\left(-\frac{1}{2}\right)^3\)
= \(\frac{3}{4}-\frac{3}{2}+\frac{1}{2}:\frac{5}{12}-\frac{-1}{8}\)
= \(\frac{3}{4}-\frac{6}{4}+\frac{1}{2}\cdot\frac{12}{5}-\frac{-1}{8}\)
= \(-\frac{3}{4}+\frac{6}{5}-\frac{-1}{8}=\frac{-30}{40}+\frac{48}{40}+\frac{-6}{40}=\frac{12}{40}=\frac{3}{10}\)
CHÚC BN HK TỐT #
LT
3
VT
27 tháng 4 2019
\(=-\frac{3}{4}+\frac{6}{5}-\left(\frac{-1}{8}\right)\))
=\(-\frac{3}{4}+\frac{6}{5}+\frac{1}{8}\)
=\(\frac{9}{20}+\frac{1}{8}\)
=\(\frac{23}{40}\)
Vậy..........
27 tháng 4 2019
\(\frac{75}{100}-1\frac{1}{2}+0,5:\frac{5}{12}-\left(-\frac{1}{2}\right)^3\)
= \(\frac{3}{4}-\frac{3}{2}+\frac{6}{5}+\frac{1}{8}\)
= \(\frac{30}{40}-\frac{60}{40}+\frac{48}{40}+\frac{5}{40}\)
= \(\frac{23}{40}\)
\(75\%-1\frac{1}{2}+0,5:\frac{5}{12}\)
\(=\frac{3}{4}-\frac{3}{2}+\frac{1}{2}.\frac{12}{5}\)
\(=\frac{3}{4}-\frac{3}{2}+\frac{6}{5}\)
\(=\frac{15}{20}-\frac{30}{20}+\frac{24}{20}\)
\(=\frac{9}{20}\)
bt rùi nhưng ko chắc lắm