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Ta có ; \(\frac{-7}{25}.\frac{11}{13}+\frac{-7}{25}.\frac{2}{13}-\frac{18}{25}\)
\(=\frac{-7}{25}.\left(\frac{11}{13}+\frac{2}{13}\right)-\frac{18}{25}\)
\(=\frac{-7}{25}.1-\frac{18}{25}\)
\(=\frac{-7}{25}-\frac{18}{25}=\frac{-25}{25}=-1\)
mk ko ghi lại đầu bài nhé
=-7/25.(11/13+2/13)-18/25
=-7/25.1-18/25
=-7/25-18/25
=-25/25
=-1
~ chúc bạn học toots~ k mk nha
= -7/25 x ( 11/13 + 2/13 ) - 18/25
= - 7/25 x 1 - 18/25
= -7/25 - 18/25
= -1
nhớ tích cho mình nha mình cảm ơn rất nhìu^^
\(=\dfrac{-7}{25}\left(\dfrac{11}{13}+\dfrac{2}{13}\right)-\dfrac{18}{25}=-1\)
\(a)-7/25*(11/13+2/13)-18/25=-7/25*1-18/25=-7/25-18/25=-25/25=-1\)
\(=-\dfrac{7}{25}\left(\dfrac{11}{13}+\dfrac{2}{13}\right)-\dfrac{18}{25}=-\dfrac{7}{25}.1-\dfrac{18}{25}=-\dfrac{25}{25}=-1\)
`Answer:`
a. \(-\frac{17}{30}-\frac{11}{-15}+-\frac{7}{12}\)
\(=-\frac{17}{30}+\frac{11}{15}-\frac{7}{12}\)
\(=-\frac{17}{30}+\frac{22}{30}-\frac{7}{12}\)
\(=\frac{1}{6}-\frac{7}{12}\)
\(=-\frac{5}{12}\)
b. \(-\frac{5}{9}+\frac{5}{9}:\left(\frac{5}{3}-\frac{25}{12}\right)\)
\(=-\frac{5}{9}+\frac{5}{9}:\left(-\frac{5}{12}\right)\)
\(=\frac{5}{9}.\left(-1\right)+\frac{5}{9}.\left(-\frac{12}{5}\right)\)
\(=\frac{5}{9}.\left(-1-\frac{12}{5}\right)\)
\(=\frac{5}{9}.\frac{-17}{5}\)
\(=-\frac{17}{9}\)
c. \(-\frac{7}{25}.\frac{11}{13}+-\frac{7}{25}-\frac{2}{13}-\frac{18}{25}\)
\(=\frac{77}{325}-\left(\frac{7}{25}+\frac{18}{25}\right)-\frac{2}{13}\)
\(=\frac{77}{325}-1-\frac{2}{13}\)
\(=-\frac{452}{325}\)
Giải:
\(-\dfrac{7}{25}.\dfrac{11}{13}+\dfrac{-7}{25}.\dfrac{2}{13}+2018\dfrac{7}{25}\)
\(=-\dfrac{7}{25}.\dfrac{11}{13}+\dfrac{-7}{25}.\dfrac{2}{13}+2018+\dfrac{7}{25}\)
\(=-\dfrac{7}{25}.\left(\dfrac{11}{13}+\dfrac{2}{13}\right)+2018+\dfrac{7}{25}\)
\(=-\dfrac{7}{25}.1+2018+\dfrac{7}{25}\)
\(=-\dfrac{7}{25}+2018+\dfrac{7}{25}\)
\(=2018\)
Vậy ...
1) âm năm phần 12
2) âm mười bảy phần 9
3) -1
Đây là đáp án còn làm bài từ làm nhé
a) -7/25 . 11/13 + -7/25 . 2/13 - 18/25=-1
b) 5/7 . 1/3 - 5/7 . 1/4 - 5/7 . 1/12=0
c) 5 + 2/5 . 4+ 2/7 + 5 + 5/7 . 5+ 2/5=18
d) 75% - 3/2 + 0,5 - [ -1/2]^2=-1/2
\(\frac{-7}{25}.\frac{11}{13}+\frac{-7}{25}.\frac{2}{13}-\frac{18}{25}\)
= \(\frac{-7}{25}.\left(\frac{11}{13}+\frac{2}{13}\right)-\frac{18}{25}\)
= \(\frac{-7}{25}-\frac{18}{25}\)
= - 1