Hãy nhập câu hỏi của bạn vào đây, nếu là tài khoản VIP, bạn sẽ được ưu tiên trả lời.
\(72^{45}-72^{44}=72^{44}.\left(72-1\right)=72^{44}.71\)
\(72^{44}-72^{43}=72^{43}.\left(72-1\right)=72^{43}.71\)
Vì \(72^{44}>72^{43}\Rightarrow72^{45}-72^{44}>72^{44}-72^{43}\)
Câu 3:
\(2S=2+2^2+2^3+...+2^{10}\)
nên \(S=2^{10}-1\)
\(5\cdot2^8=256\cdot5=1280>1023=2^{10}-1\)
Do đó: \(S< 5\cdot2^8\)
1, x-72:36=18
x-2=18
=> x=20
2, \(\dfrac{x}{3}-\dfrac{1}{4}=\dfrac{-5}{6}\)
\(\dfrac{x}{3}=\dfrac{-7}{12}\)
12x= -21
->x= \(\dfrac{-21}{12}\)
1: 9 - 25 - (7 - x) - (25 + 7)
đề thiếu
2: -6 . x = 18
x=18:(-6)
x=-3
3: [(6 . x - 72) : 2- 84]. 28= 5628
(6.x-72):2-84=5628:28
(6.x-72):2-84=201
(6.x-72):2=201+84
(6.x-72):2=285
6.x-72=285.2
6.x-72=570
6.x=570+72
6.x=642
x=642:6
x=107
2130 - ( x + 130 ) + 72 = - 64
2202 - ( x + 130 ) = - 64
x + 130 = 2202 + 64
x + 130 = 2266
x = 2266 + 130
x = 2396
\(|x|-5=-1\)
\(|x|=-1+5\)
\(|x|=4\)
\(\Rightarrow\orbr{\begin{cases}x=4\\x=-4\end{cases}}\)
\(|x+2|-12=-1\)
\(|x+2|=-1+12\)
\(|x+2|=11\)
\(\Rightarrow\orbr{\begin{cases}x+2=11\\x+2=-11\end{cases}}\)
\(\Rightarrow\orbr{\begin{cases}x=11-2\\-x=-11-2\end{cases}}\)
\(\Rightarrow\orbr{\begin{cases}x=9\\x=-13\end{cases}}\)
135 - ( 9 - x ) = 35
135 - 9 + x = 35
126 + x = 35
x = 35 - 126
x = - 91
15 - ( -x + 18 ) = - 24
15 + x - 18 = - 24
- 3 + x = -24
x = - 24 + 3
x = - 21
1e) Để \(\frac{2x-1}{x-3}\) nguyên thì \(2x-1⋮x-3\)
\(\Leftrightarrow2x-6+5⋮x-3\)
\(\Leftrightarrow2\left(x-3\right)+5⋮x-3\)
Do \(2\left(x-3\right)⋮x-3\) \(\Rightarrow5⋮x-3\)
\(\Rightarrow x-3\in\left\{-5;-1;1;5\right\}\)
\(\Leftrightarrow x\in\left\{-2;2;4;8\right\}\)
Vậy:...................
\(x\cdot18:4=72\cdot0,25\)
\(x\cdot18:4=18\)
\(x\cdot4,5=18\)
\(x=18:4,5\)
\(x=4\)
\(x\times18:4=72\times0,25\)
\(\Rightarrow x\times18:4=18\)
\(\Rightarrow x\times4,5=18\)
\(\Rightarrow x=4\)