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72 . 56 - 12 . 44 + 72 . 44 - 12 . 5
=72 x (56 + 44) + 12 x (44 + 56)
= 72 x 100 + 12 x 100
= 7200 + 1200
= 8400
[44- (56-x) ] . 12 = 384
<=> (44-56+x) . 12 = 384
<=> (-12 + x) . 12 = 384
<=> 12x - 144 = 384
<=> 12x = 384 + 144
<=> 12x = 528
<=> x = 528 : 12
<=> x = 44
Vậy x = 44
\(=\frac{1}{3.4}+\frac{1}{4.5}+\frac{1}{\cdot5.6}+\frac{1}{6.7}+\frac{1}{7.8}+\frac{1}{8.9}\)
=\(\left(\frac{1}{3}-\frac{1}{4}\right)+\left(\frac{1}{4}-\frac{1}{5}\right)+\left(\frac{1}{5}-\frac{1}{6}\right)+\left(\frac{1}{6}-\frac{1}{7}\right)+\left(\frac{1}{7}-\frac{1}{8}\right)+\left(\frac{1}{8}-\frac{1}{9}\right)\)
=1/3-1/9=2/9
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li-ke cho mk nha bn Vũ lệ Quyên
\(\frac{1}{12}+\frac{1}{20}+\frac{1}{30}+\frac{1}{42}+\frac{1}{56}+\frac{1}{72}=\frac{1}{3\times4}+\frac{1}{4\times5}+\frac{1}{5\times6}+\frac{1}{6\times7}+\frac{1}{7\times8}+\frac{1}{8\times9}\)
\(=\frac{1}{3}-\frac{1}{4}+\frac{1}{4}-\frac{1}{5}+\frac{1}{5}-\frac{1}{6}+\frac{1}{6}-\frac{1}{7}+\frac{1}{7}-\frac{1}{8}+\frac{1}{8}-\frac{1}{9}\)
\(=\frac{1}{3}-\frac{1}{9}=\frac{3}{9}-\frac{1}{9}=\frac{2}{9}\)
1/2+...................+71/72
=(1-1/2)+......................+(1-1/72)
=1+1+.....+1-1/2-...................-1/72
=8-(1/2+...................+1/72)
=8-(2-1/1*2+3-2/2*3+.............+9-8/8*9)
=8-(1-1/2+1/2-1/3+1/3-..............+1/8-1/9)
=8-(1-1/9)
=8-8/9
=64/9
a) \(\frac{5}{6}+\frac{11}{12}+\frac{19}{20}+...+\frac{89}{90}\)
\(=1-\frac{1}{6}+1-\frac{1}{12}+...+1-\frac{1}{90}\)
\(=\left(1+1+1+...+1\right)-\left(\frac{1}{6}+\frac{1}{12}+...+\frac{1}{90}\right)\)
\(=\left(1+1+1+...+1\right)-\left(\frac{1}{2\cdot3}+\frac{1}{3\cdot4}+...+\frac{1}{9\cdot10}\right)\)
Từ 2 đến 9 có : ( 9 - 2 ) / 1 + 1 = 8 ( số hạng ) => có 8 số 1
\(\Rightarrow8-\left(\frac{1}{2}-\frac{1}{3}+\frac{1}{3}-\frac{1}{4}+...+\frac{1}{9}-\frac{1}{10}\right)\)
\(=8-\left(\frac{1}{2}-\frac{1}{10}\right)\)
\(=8-\frac{2}{5}=\frac{38}{5}\)
b) \(\frac{1}{2}+\frac{5}{6}+\frac{11}{12}+...+\frac{109}{110}\)
\(=1-\frac{1}{2}+1-\frac{1}{6}+...+1-\frac{1}{110}\)
\(=\left(1+1+1+...+1\right)-\left(\frac{1}{2}+\frac{1}{6}+...+\frac{1}{110}\right)\)
\(=\left(1+1+...+1\right)-\left(\frac{1}{1\cdot2}+\frac{1}{2\cdot3}+...+\frac{1}{10\cdot11}\right)\)
Từ 1 đến 10 có : ( 10 - 1 ) / 1 + 1 = 10 ( số hạng ) => có 10 số 1
\(\Rightarrow10-\left(1-\frac{1}{2}+\frac{1}{2}-\frac{1}{3}+...+\frac{1}{10}-\frac{1}{11}\right)\)
\(=10-\left(1-\frac{1}{11}\right)\)
\(=10-\frac{10}{11}=\frac{100}{11}\)
1/12 + 1/20 1/30 + 1/42 + 1/56 + 1/72 + 1/90
= 1/3.4 + 1/4.5 + 1/5.6 + 1/6.7 + 1/7.8 + 1/8.9 + 1/9.10
= 1/3 - 1/4 + 1/4 - 1/5 + 1/5 - 1/6 + 1/6 - 1/7 + 1/7 - 1/7 + 1/8 - 1/9 + 1/9 - 1/10
= 1/3 - 1/10
= 7/30
\(\frac{1}{12}+\frac{1}{20}+\frac{1}{30}+\frac{1}{42}+\frac{1}{56}+\frac{1}{72}\)
\(=\frac{1}{3.4}+\frac{1}{4.5}+\frac{1}{5.6}+\frac{1}{6.7}+\frac{1}{7.8}+\frac{1}{8.9}\)
\(=\frac{1}{3}-\frac{1}{4}+\frac{1}{4}-\frac{1}{5}+\frac{1}{5}-\frac{1}{6}+\frac{1}{6}-\frac{1}{7}+\frac{1}{7}-\frac{1}{8}+\frac{1}{8}-\frac{1}{9}\)
\(=\frac{1}{3}-\frac{1}{9}\)
\(=\frac{3}{9}-\frac{1}{9}\)
\(=\frac{2}{9}\)
= 1/3 x 4 + 1 / 4 x 5 + 1 / 5x6 + 1 / 6 x 7 + 1 / 7 x 8 + 1 / 8 x 9
= 1/3 - 1 / 4 + 1 /4 - 1/5 + 1/5 - 1/6 + ................... + 1/8 - 1/9
= 1/3 - 1/9
= 2/9
1/2+1/6+...+1/72=1/1x2+1/2x3+...+1/8x9=1/1-1/2+1/2-1/3+...+1/8-1/9=1-1/9=8/9
72 * (56 + 44) + 12 * (44 + 56)
= 72 * 100 + 12* 100
= 7200 + 1200
= 8400
72.56 - 12.44 + 72.44 - 12.56 = 72.(56 + 44) - 12.(44 + 56) = 72.100 - 12.100 = 100.(72 - 12) = 100.60 = 6000