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\(6x^2-7x-20\)
\(=6x^2+8x-15x-20\)
\(=2x\cdot\left(3x+4\right)-5\left(3x+4\right)\)
\(=\left(3x+4\right)\left(2x-5\right)\)
\(x^4+6x^3+7x^2-6x+1\)
\(=x^4+6x^3+9x^2-2x^2-6x+1\)
\(=\left(x^2\right)^2+2.x^2.3x+\left(3x\right)^2-2\left(x^2+3x\right)+1\)
\(=\left(x^2+3x\right)^2-2\left(x^2+3x\right).1+1^2\)
\(=\left(x^2+3x-1\right)^2\)
Chúc bạn học tốt.
\(x^4+6x^3+7x^2-6x+1\)
\(=x^4+6x^3+9x^2-2x^2-6x+1\)
\(=x^2\left(x+3\right)^2-2\left(x^2+3x\right)+1\)
\(=\left(x^2+3x\right)^2-2\left(x^2+3x\right)+1=\left(x^2+3x-1\right)^2\)
\(a,4x^2-y^2-1-4x\)
\(\Rightarrow\left(4x^2+4x+1\right)-y^2\)
\(=\left(2x+1\right)^2-y^2=\left(2x+1-y\right)\left(2x+1+y\right)\)
\(b,6x^2-7x-20=6x^2-15x+8x-20\)
\(=\left(6x^2-15x\right)+\left(8x-20\right)\)
\(=3x\left(2x-5\right)+4\left(2x-5\right)\)
\(=\left(3x+4\right)\left(2x-5\right)\)
x4+6x3+7x2-6x+1
=(x4-2x2+1)+(6x3-6x)+9x2
=(x2-1)2+6x(x2-1)+9x2
=(x2-1).(x2-1+6x)+9x2
=(x2+3x-1)2
x4+6x3+7x2-6x+1
=(x4-2x2+1)+(6x3-6x)+9x2
=(x2-1)2+6x(x2-1)+9x2
=(x2-1). (x2-1+6x)+9x2
=(x2+3x-1)2
x^4+6x^3+7x^2–6x+1
=x^4+(6x^3–2x^2)+(9x^2–6x+1)
= x^4+2x^2(3x–1)+(3x–1)^2
=(x^2+3x–1)^2
\(7x-6x^2-2=\left(3x-6x^2\right)+\left(4x-2\right)=3x\left(1-2x\right)-2\left(1-2x\right)=\left(1-2x\right)\left(3x-2\right)\)
\(6x^2-7x+2=6x^2-3x-4x+2=3x\left(2x-1\right)-2\left(2x-1\right)=\left(3x-2\right)\left(2x-1\right)\)
Đúng cho mình nhe
7x - 6x2 - 2
= - ( 6x2 - 7x + 2)
= - ( 6x2 - 3x - 4x + 2 )
= - [ 3x ( 2x - 1 ) - 2 ( 2x - 1 ) ]
= - ( 2x - 1 ) ( 3x - 2 )
~ Học tốt ~
6x2-7x-20
= 6x2-15x+8x-20
= 3x(2x-5) + 4(2x-5)
= ( 2x-5 )(3x+4)
<=> x= 5/2 hoặc x= -4/3
Vậy .........