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\(a,\left(\frac{3}{15}\right)^{15}:\left(\frac{9}{25}\right)^5=\left(\frac{1}{5}\right)^{15}:\frac{9^5}{25^5}=\frac{1}{5^{15}}.\frac{5^{10}}{9^5}=\frac{1}{5^5.9^5}=\frac{1}{45^5}\)
\(b,5-\left(\frac{-5}{11}\right)^0+\left(\frac{1}{3}\right)^2:3=5-1+\frac{1}{3^2}.\frac{1}{3}=4+\frac{1}{3^3}=\frac{109}{27}\)
\(c,2^3+3\left(\frac{1}{2}\right)^0+\left[\left(-2\right)^2.12\right].8=8+3.1+4.12.8=395\)
a, \(\frac{-1}{39}+\frac{-1}{52}=\frac{-61}{468}\)
b, \(-\frac{9}{6}+-\frac{12}{16}=-\frac{9}{4}\)
\(c,-\frac{2}{5}--\frac{3}{11}=-\frac{7}{55}\)\
\(-\frac{34}{37}\cdot\frac{74}{-58}=\frac{34}{29}\)
h cho minh nha
a= -7/156
b=1/12
c=-7/55
d=17/21
e=10/7
cho minh nhé
\(\frac{-1}{39}+\frac{-1}{52}=\frac{-7}{156}\)
\(\frac{-6}{9}+\frac{12}{16}=\frac{-2}{3}+\frac{3}{4}=\frac{1}{12}\)
\(\frac{-2}{5}-\frac{-3}{11}-\frac{34}{37}-\frac{74}{-85}=\frac{-1215}{6919}\)
\(\frac{-5}{9}:\frac{-7}{18}=\frac{-5}{9}.\frac{-18}{7}=\frac{10}{7}\)
a) \(\left(\frac{2}{3}\right)^x=\left(\frac{4}{9}\right)^{50}\)
\(\Rightarrow\left(\frac{2}{3}\right)^x=\left(\frac{2^2}{3^2}\right)^{50}\)
\(\Rightarrow\left(\frac{2}{3}\right)^x=\left(\frac{2}{3}\right)^{100}\)
\(\Rightarrow x=100\)
Vậy x = 100
b) \(\left(\frac{2}{3}-x\right)^2=\frac{1}{36}\)
\(\Rightarrow\left(\frac{2}{3}-x\right)^2=\left(\frac{1}{6}\right)^2\)
\(\Rightarrow\frac{2}{3}-x=\frac{1}{6}\)
\(\Rightarrow x=\frac{2}{3}-\frac{1}{6}\)
\(\Rightarrow x=\frac{1}{2}\)
Vậy \(x=\frac{1}{2}\)
2)
Ta có:
\(74^{m+1}+74^m=74^m.74^1+74^m=74^m.\left(74+1\right)=74^m.75⋮25\)
( vì \(75⋮25\) )
\(\Rightarrowđpcm\)
-1/39 + -1/52 = -7/156
-6/9 + -12/16 = -17/12
-2/5 - - 3/11 [ (-) + ( -) = +] = -2/5 + 3/11 = -7/55
-34/37 - 74/ -85 = -152/3145
-5/9 : -7/18 = 10/7