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a) \(\dfrac{2^6\cdot5^5}{10^5}\)
\(=\dfrac{2^6\cdot5^5}{2^5\cdot5^5}\)
\(=2\)
b) \(\dfrac{3^6\cdot5^7}{15^6}\)
\(=\dfrac{3^6\cdot5^7}{3^6\cdot5^6}\)
\(=5\)
TL
\(\frac{3}{4}+\frac{2}{3}=\frac{17}{12}\)
\(\frac{4}{5}+\frac{1}{2}-\frac{7}{10}=\frac{3}{5}\)
\(\frac{7}{6}\).\(\frac{1}{3}+\frac{7}{6}\).\(\frac{1}{2}\)-\(\frac{7}{6}\) . \(\frac{5}{8}\)=\(\frac{7}{6}.\)(\(\frac{1}{3}+\frac{1}{2}-\frac{5}{8}\))=\(\frac{7}{6}.\)\(\frac{5}{24}\)=\(\frac{35}{144}\)
HT
Lời giải:
$\frac{1}{3}+\frac{3}{6}.\frac{5}{9}+\frac{6}{7}+8+\frac{6}{9}+\frac{3}{4}:\frac{2}{3}$
$=\frac{1}{3}+\frac{5}{18}+\frac{6}{7}+8+\frac{2}{3}+\frac{9}{8}$
$=(\frac{1}{3}+\frac{2}{3})+8+(\frac{5}{18}+\frac{6}{7}+\frac{9}{8})$
$=9+\frac{1134}{504}=9+2+\frac{131}{504}=11\frac{131}{504}$
Câu 1 xem kỉ đề
\(B,\frac{49^6.5-7^{11}}{\left(-7\right)^{10}.5-2.49^5}=\frac{7^{12}.5-7^{11}}{7^{10}.5-2.7^{10}}=\frac{7^{11}.\left(7.5-1\right)}{7^{10}.\left(5-2\right)}=\frac{7.34}{3}=\frac{238}{3}\)
a) A=212.35-\(\frac{2^{12}.3^6}{2^{12}}\)+93+84.35
=212.35-36+36+212.35
=213.35
b)B=496.5-5.\(\frac{7^{11}}{\left(-7\right)^{10}}-2.49^5\)
=496.5-7.5-2.495
=712.5-7.5-2.710
\(\dfrac{2^6.18+2^7}{2^6.5^2-2^6.3}=\dfrac{2^6\left(18+2\right)}{2^6.\left(5^2-3\right)}=\dfrac{20}{5^2-3}=\dfrac{20}{25-3}=\dfrac{20}{22}=\dfrac{10}{11}\)
\(=\dfrac{2^6.18+2^6.2}{2^6.25-2^6.3}=\dfrac{2^6\left(18+2\right)}{2^6\left(25-3\right)}=\dfrac{18+2}{25-3}=\dfrac{20}{22}=\dfrac{10}{11}\)
85=(23)5=215=2.214
3.47=3.(22)14=3.214
vì 2<3 nên 2.214<3.214
hay 85<3.47
335=32.333=9.(33)11=9.2711
523=51.522=5.(52)11=5.2511
vì 9>5 và 27>25 nên 9.2711>5.2511
hay 335>523
xem lại câu này
216=23.213=8.213
vì 7<8 nên 7.213<8.213
hay 7.213<216
a/\(\frac{3939-101}{3.2929+505}=\frac{39.101-101}{8787+505}=\frac{101.\left(39-1\right)}{87.101+5.101}=\frac{101.38}{101.\left(87+5\right)}=\frac{38}{92}\)
\(=\frac{38}{92}\)
b/\(\frac{6.4+6.7}{6.5+12}=\frac{4+1.7}{1.5+2}=\frac{4+7}{5+2}=\frac{11}{7}\)
`@` `\text {Ans}`
`\downarrow`
`a.`
`A=(1/2-7/13-1/3)+(-6/13+1/2+1 1/3)`
`= 1/2 - 7/13 - 1/3 - 6/13 + 1/2 + 1 1/3`
`= (1/2 + 1/2) + (-7/13 - 6/13) + (-1/3 + 1 1/3) `
`= 1 - 1 + 1`
`= 1`
`b.`
`B=0,75+2/5+(1/9-1 1/2+5/4)`
`= 3/4 + 2/5 + 1/9 - 3/2 + 5/4`
`= (3/4+5/4)+ 1/9 + 2/5 - 3/2`
`= 2 + 1/9 - 11/10`
`= 19/9 - 11/10`
`= 91/90`
`c.`
`(-5/9).3/11+(-13/18).3/11`
`= 3/11*[(-5/9) + (-13/18)]`
`= 3/11*(-23/18)`
`= -23/66`
`d.`
`(-2/3).3/11+(-16/9).3/11`
`= 3/11* [(-2/3) + (-16/9)]`
`= 3/11*(-22/9)`
`= -2/3`
`e.`
`(-1/4).(-2/13)-7/24.(-2/13)`
`= (-2/13)*(-1/4-7/24)`
`= (-2/13)*(-13/24)`
`= 1/12`
`f.`
`(-1/27).3/7+(5/9).(-3/7)`
`= 3/7*(-1/27 - 5/9)`
`= 3/7*(-16/27)`
`= -16/63`
`g.`
`(-1/5+3/7):2/11+(-4/5+4/7):2/11`
`=[(-1/5+3/7)+(-4/5+4/7)] \div 2/11`
`= (-1/5+3/7 - 4/5 + 4/7) \div 2/11`
`= [(-1/5-4/5)+(3/7+4/7)] \div 2/11`
`= (-1+1) \div 2/11`
`= 0 \div 2/11 = 0`