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B8 = 6/15.18 + 6/18.21 + 6/21.24 + ... + 6/87.90
B8 = 2.(3/15.18 + 3/18.21 + 3/21.24 + ... + 3/87 .90)
B8 = 2.(1/15 - 1/18 + 1/18 -1/21 + 1/21 - 1/24 + ... + 1/87 - 1/90)
B8 = 2.(1/15 - 1/90)
B8 = 2.(6/90 - 1/90)
B8 = 2. 1/18
B8 = 1/9
B = 1/9 : 8
B = 1/72
bạn sai ở đoạn cuối
A=\(\frac{3\cdot3}{15\cdot18}+\frac{3\cdot3}{18\cdot21}+...+\frac{3\cdot3}{96\cdot99}=3\cdot\left(\frac{3}{15\cdot18}+\frac{3}{18\cdot21}+...+\frac{3}{96\cdot99}\right)=3\cdot\left(\frac{1}{15}-\frac{1}{18}+\frac{1}{18}-\frac{1}{21}+...+\frac{1}{96}-\frac{1}{99}\right)=3\cdot\left(\frac{1}{15}-\frac{1}{99}\right)=3\cdot\frac{28}{495}=\frac{28}{165}\)
\(A=\frac{6}{5.8}+\frac{6}{8.11}+....+\frac{6}{87.90}\)
\(A=2.\left(\frac{3}{5.8}+\frac{3}{8.11}+....+\frac{3}{87\cdot90}\right)\)
\(A=2.\left(\frac{1}{5}-\frac{1}{8}+\frac{1}{8}-\frac{1}{11}+....+\frac{1}{87}-\frac{1}{90}\right)\)
\(A=2.\left(\frac{1}{5}-\frac{1}{90}\right)\)
\(A=2.\frac{1}{6}=\frac{1}{3}\)
D=6/15.18+6/18.21+...+6/89.92
D=6(1/15.18+1/18.21+...+1/89.92)
a) 3D=6(1/15-1/18+1/18-1/21+...+1/89-1/92)
3D=6(1/15-1/92)
3D=6.(77/1380)
3D=77/230
D=77/690
b) F=1/25.27+1/27.29+...+1/73.75
2F=2/25.27+2/27.29+..+2/73.75
2F=1/25-1/27+1/27-1/29+...+1/73-1/75
2F=1/25-1/75
2F=2/75
F=1/75
Gọi biểu thức trên là A, ta có:
\(A=\frac{1}{2\cdot15}+\frac{1}{15\cdot3}+\frac{1}{3\cdot21}+\frac{1}{21\cdot4}+...+\frac{1}{87\cdot90}\)
\(13A=\frac{13}{2\cdot15}+\frac{13}{15\cdot3}+\frac{13}{3\cdot21}+\frac{13}{21\cdot4}+...+\frac{13}{87\cdot90}\)
\(13A=\frac{1}{2}-\frac{1}{15}+\frac{1}{15}-\frac{1}{3}+\frac{1}{3}-\frac{1}{21}+\frac{1}{21}-\frac{1}{4}+...+\frac{1}{87}-\frac{1}{90}\)
\(13A=\frac{1}{2}-\frac{1}{90}\)
\(13A=\frac{22}{45}\)
\(A=\frac{22}{45\text{x}13}=\frac{22}{585}\)
( 25^6 + 15^6 - 10^6 ) : 5^6 - ( 5^6 + 3^6 ) = -64
Nguyễn Thị Tuyết Sương ah , mk bt kq r thứ mik cần là lời giải cơ
\(\frac{6}{15}+\frac{6}{35}+\frac{6}{63}+\frac{6}{143}\)
=\(\frac{304}{429}\)
k mình cho tròn 240 nhé
Đặt \(A=\frac{6}{15.18}+\frac{6}{18.21}+\frac{6}{21.24}+...+\frac{6}{87.90}\)
\(A=2.\left(\frac{3}{15.18}+\frac{3}{18.21}+\frac{3}{21.24}+...+\frac{3}{87.90}\right)\)
\(A=2.\left(\frac{1}{15}-\frac{1}{18}+\frac{1}{18}-\frac{1}{21}+\frac{1}{21}-\frac{1}{24}+...+\frac{1}{87}-\frac{1}{90}\right)\)
\(A=2.\left(\frac{1}{15}-\frac{1}{90}\right)\)
\(A=2.\frac{1}{18}=\frac{1}{9}\)
Vậy...
\(A=2.\left(\frac{3}{15.18}+\frac{3}{18.21}+\frac{3}{21.24}+...+\frac{3}{87.90}\right)\)
\(A=2.\left(\frac{1}{15}-\frac{1}{18}+.......+\frac{1}{87}-\frac{1}{90}\right)\)
\(A=2.\left(\frac{1}{15}-\frac{1}{90}\right)\)