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a) 44 + (16 - x) = 50
=> 16-x = 6
=> x = 10
b) 585 - (7x + 60) = 455
=> 7x+60=130
=> 7x = 70
=> x = 7
c) 22x : 22 = 10.24 - 6.24
=> 22x : 22 =64
=> 22x = 256
mà : 256 = 28
=> 22x = 28
=> 2x = 8
=> x = 4

Đặt \(A=4+2^2+2^3+2^4+...+2^{60}\)
\(A=2^2+2^2+2^3+...+2^{60}\)
\(2A=2^3+2^3+2^4+...+2^{61}\)
\(2A-A=\left(2^3+2^3+2^4+...+2^{61}\right)-\left(2^2+2^2+2^3+...+2^{60}\right)\)
\(A=2^3+2^{61}-2^2-2^2\)
\(A=2^3+2^{61}-2^2\left(1+1\right)\)
\(A=2^3+2^{61}-2^2.2\)
\(A=2^3+2^{61}-2^3\)
\(A=2^{61}\)
Vậy \(A=2^{61}\)
Chúc bạn học tốt ~

44 + ( 16 - x ) = 50
=> 16 - x = 50 - 44
=>16 - x = 6
=> x = 16 - 6
=> x = 10
tíc mình nha

a)\(568-\left\{5.\text{[}143-\left(4-1\right)^2\text{]}+10\right\}:10\)
\(=568-\left\{5.\left[143-3^2\right]+10\right\}:10\)
\(=568-\left\{5.134+10\right\}\text{ }\)
\(=568-\left(670+10\right)\)
\(=568-680\)
\(=-112\)
b)\(10^2-\left[60:\left(5^6:5^4-3\times5\right)\right]\)
\(=100-\left[60-\left(6^2-15\right)\right]\)
\(=100-\left(60-\left(36-15\right)\right)\)
\(=100-60-36+15\)
\(=19\)
\(a)\)\(568-\left\{5\left[143-\left(4-1\right)^2\right]+10\right\}\div10\)
\(=\)\(568-\left\{5\left[143-3^2\right]+10\right\}\div10\)
\(=\)\(568-\left\{5\left[143-9\right]+10\right\}\div10\)
\(=\)\(568-\left\{5.134+10\right\}\div10\)
\(=\)\(568-\left\{670+10\right\}\div10\)
\(=\)\(568-680\div10\)
\(=\)\(568-68\)
\(=\)\(500\)
\(b)\)\(10^2-\left[60\div\left(5^6\div5^4-3\times5\right)\right]\)
\(=\)\(10^2-\left[60\div\left(5^2-15\right)\right]\)
\(=\)\(10^2-\left[60\div\left(25-15\right)\right]\)
\(=\)\(10^2-\left[60\div10\right]\)
\(=\)\(100-6\)
\(=\)\(94\)

2 mũ 6 x bằng 6
2 mũ 5 trừ 2 bằng 30 x = 5
x bằng 12
x bằng 4
x= 4
\(2^x=64\Leftrightarrow2^x=2^6\Leftrightarrow x=6\)
\(2^x-2=30\Leftrightarrow2^x=32\Leftrightarrow2^x=2^5\Leftrightarrow x=5\)
\(18:\left(x-6\right)=3\Leftrightarrow x-6=6\Leftrightarrow x=6+6=12\)
\(3^x-1=80\Leftrightarrow3^x=81\Leftrightarrow3^x=3^4\Leftrightarrow x=4\)
\(240:\left(2x-4\right)=60\Leftrightarrow2x-4=4\Leftrightarrow2x=8\Leftrightarrow x=4\)
\(143-5^{3-x}=3^3\times2^0\Leftrightarrow143-5^{3-x}=27\times1\)
\(\Leftrightarrow143-5^{3-x}=27\Leftrightarrow5^{3-x}=143-27=116\)
mà \(5^{3-x}\ne116\Leftrightarrow x\in\varnothing\)
Vậy: \(x\in\varnothing\)
Nhớ k cho mình nhé! Thank you!!!
60-(x+2)2=-4
(x + 2)2 = 60 - (-4)
(x + 2)2 = 64
(x + 2)2= 82
=> x + 2 = 8
x = 8 -2
x = 6