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\(a, 2023 - 25^2 : 5^3 + 27\)
\(=\left(2023+27\right)-\left(5^2\right)^2:5^3\)
\(=2050-5^4:5^3\)
\(=2050-5\)
\(=2045\)
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\(b,60:\left[7\cdot\left(11^2-20\cdot6\right)+5\right]\)
\(=60:\left[7\cdot\left(121-120\right)+5\right]\)
\(=60:\left(7\cdot1+5\right)\)
\(=60:\left(7+5\right)\)
\(=60:12\)
\(=5\)
#Toru
a) \(2023-25^2:5^3+27\)
\(=2023-5^4:5^3+27\)
\(=2023-5+27\)
\(=2018+27\)
\(=2045\)
b) \(60:\left[7.\left(11^2-20.6\right)+5\right]\)
\(=60:\left[7.\left(121-120\right)+5\right]\)
\(=60:\left[7.1+5\right]\)
\(=60:\left[7+5\right]\)
\(=60:12\)
\(=5\)
\(#WendyDang\)
791:789+5.52-124
=791:789+5.25-124
=791-89+125-124
=72+125-124
=49+125-124
=174-124
=50
4.15+28:7-620:618
=60+4-620-18
=64-62
=64-36
=28
(32+23):7
=(9+8):7
=17:7
=17/7
1125:1123-35:(110+23)-60
=1125:1123-35:(1+8)-60
=1125:1123-35:9-60
=1125:1123-35:33-60
=1125-23-35-3-60
=112-32-60
=121-9-60
=112-60
=52
a) (38 - 60) + (20 - 38)
= 38 - 60 + 20 - 38
= (38 - 38) + (-60 + 20)
= 0 - 40
= -40
b) 75 - (20 + 75)
= 75 - 20 - 75
= (75 - 75) - 20
= 0 - 20
= -20
c) 32 + (60 - 32)
= 32 + 60 - 32
= (32 - 32) + 60
= 0 + 60
= 60
d) (81 - 36) - (81 - 36)
= 81 - 36 - 81 + 36
= (81 - 81) + (-36 + 36)
= 0 + 0
= 0
e) (2 + 4 + 6 + 8) - (1 + 3 + 5 + 7)
= 2 + 4 + 6 + 8 - 1 - 3 - 5 - 7
= (2 - 1) + (4 - 3) + (6 - 5) + (8 - 7)
= 1 + 1 + 1 + 1
= 4
f) (1 + 3 + 5 + 7 + ... + 99) - (2 + 4 + 6 + 8 + ... + 100)
= 1 + 3 + 5 + 7 + ... + 99 - 2 - 4 - 6 - 8 - ... - 100
= (1 - 2) + (3 - 4) + (5 - 6) + (7 - 8) + ... + (99 - 100)
= -1 - 1 - 1 - 1 - ... - 1 (50 chữ số 1)
= -50
Câu Q có Ước chung lớn nhất là 1680
<=> Q = 378/1680 - 308/1680 - 260/1680 - 225/1680
Q= (378-308-260-255)/1680
Q= -445/1680
Q=-89/336
a: 7/30=28/120
13/60=26/120
-9/40=-27/120
b: -3/5=-18/30
-5/6=-25/30
3=90/30
c: -4/7=-36/63
8/9=56/63
-10/21=-30/63
d: -3/20=-9/60
-11/-30=11/30=22/60
7/15=28/60
a: 14/5-7/5=7/5
b: 7/8-1/3+5/4
=21/24-8/24+30/24
=43/24
c; =7/6+5/6+2/15+13/15
=2+1
=3
d: =4*5/3*11=20/33
e: =2/9*1/6*1/4=2/9*1/24=1/108
2:
a: \(=\dfrac{3}{9}\cdot\dfrac{4}{4}\cdot\dfrac{5}{5}\cdot\dfrac{6}{6}\cdot\dfrac{7}{7}=\dfrac{1}{3}\)
b: \(=\dfrac{1}{6}\left(\dfrac{22}{3}-\dfrac{2}{3}\right)=\dfrac{10}{3}\cdot\dfrac{1}{6}=\dfrac{10}{18}=\dfrac{5}{9}\)
c; \(=\dfrac{1}{3}\left(9-\dfrac{2}{5}-\dfrac{3}{5}\right)=\dfrac{8}{3}\)
60 : [ 7 . ( 112 - 20 . 6 ) + 5 ]
= 60 : [ 7 . 1 + 5 ]
= 60 : 12
= 5
60 : [ 7.(112 – 20 . 6 ) + 5]
= 60 : [ 7 . ( 121 - 120 ) + 5 ]
= 60 : ( 7 . 1 + 5 )
= 60 : ( 7 + 5 )
= 60 : 12
= 5