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a)
\(3:\left(\dfrac{9}{4}\right)=\dfrac{3}{4}:\left(6.x\right)\\ \Rightarrow3.6.x=\dfrac{3}{4}.\dfrac{9}{4}\\ x=\dfrac{3}{4}.\dfrac{9}{4}.\dfrac{1}{3}.\dfrac{1}{6}\\ x=\dfrac{3}{4.4.2}\\ x=\dfrac{3}{32}\)
b)
\(4,5:0,3=\left(5.0,09\right):\left(0,01.x\right)\\ 0,01.x.4,5=5.0,09.0,3\\ x=5.\dfrac{9}{100}.\dfrac{3}{10}.100.\dfrac{10}{45}\\ x=3\)
d)
\(\left(\dfrac{1}{9}.x\right)=\dfrac{7}{4}:\dfrac{2}{25}\\ \left(\dfrac{1}{9}.x\right)=\dfrac{7}{4}.\dfrac{25}{2}\\ x:\dfrac{7}{4}=\dfrac{25}{2}:\dfrac{1}{9}\\ x=\dfrac{25}{2}.9.\dfrac{7}{4}\\ x=\dfrac{1575}{8}\\ x=196\dfrac{7}{8}\)
e)
\(\dfrac{-2}{x}=\dfrac{-x}{\dfrac{8}{25}}\\ -x.x=-2.\dfrac{8}{25}\\ -x^2=-\dfrac{16}{25}=-\dfrac{4^2}{5^2}\\ -x^2=-\left(\dfrac{4}{5}\right)^2\\ \Rightarrow x=\dfrac{4}{5}\)
Chúc bạn học tốt
\(\left(\frac{3}{5}\right)^x=\left(\frac{9}{25}\right)^3\)
\(\left(\frac{9}{25}\right)^3=\left(\left(\frac{3}{5}\right)^2\right)^3=\left(\frac{3}{5}\right)^6\)
vậy x=6
\(\left(\frac{3}{5}\right)^x=\left(\frac{9}{25}\right)^3\)
\(\Rightarrow\left(\frac{3}{5}\right)^x=\left[\left(\frac{3}{5}\right)^2\right]^3\)
\(\Rightarrow\left(\frac{3}{5}\right)^x=\left(\frac{3}{5}\right)^6\)
\(\Leftrightarrow x=6\)
`@` `\text {Ans}`
`\downarrow`
\(\left(\dfrac{3}{5}\right)^{2x-1}=\left(\dfrac{9}{25}\right)^3\)
`=>`\(\left(\dfrac{3}{5}\right)^{2x-1}=\left(\dfrac{3^2}{5^2}\right)^3\)
`=>`\(\left(\dfrac{3}{5}\right)^{2x-1}=\left(\dfrac{3}{5}\right)^6\)
`=> 2x - 1 = 6`
`=> 2x=6+1`
`=> 2x=7`
`=> x = 7/2`
`=> x = 3,5`
Vậy, `x = 3,5`
`@` `\text {Kaizuu lv uuu}`
b) (5/2-3x)=25/9
3x = 5/2-25/9
3x =-5/18
x =-5/18:3
x=-5/54
\(e.\left(x-1\right)^5=-32\)
\(\left(x-1\right)^5=\left(-2\right)^5\)
\(x-1=-2\)
\(x\) \(=-2+1\)
\(x\) \(=-1\)
Vậy \(x=-1\)
Ta có: \(2x^3+5=21\)
\(2x^3=16\)
\(x^3=8\)
\(\Rightarrow x=2\)(1)
Áp dụng tính chất dãy tỉ số bằng nhau ta được
\(\frac{x+16}{9}=\frac{y-25}{16}=\frac{z+9}{25}=\frac{x+16+y-25}{9+16}=\frac{z+9-x-16}{25-9}=\frac{x+y-9}{25}=\frac{z-x-7}{16}\)
Mà \(x=2\)
\(\Rightarrow\frac{y+2-9}{25}=\frac{z-2-7}{16}=\frac{y-7}{25}=\frac{z-9}{16}=\frac{2+16}{9}=2\)(cái này từ dãy tỉ số trên thay x vào bạn nhé!)
\(\hept{\begin{cases}y-7=2\cdot25=50\\z-9=2\cdot16=32\end{cases}}\)(nhân chéo bạn nhé!)
\(\Leftrightarrow\hept{\begin{cases}y=50+7=57\\z=32+9=41\end{cases}}\)(2)
Thay (1) và (2) vào A, ta được:
\(A=2+57+41+2017\)
\(A=2117\)
Vậy A=2117
\(5^{x-3}=25^9\)
\(\Rightarrow5^{x-3}=\left(5^2\right)^9\)
\(\Rightarrow5^{x-3}=5^{18}\)
\(\Rightarrow x-3=18\)
\(\Rightarrow x=18+3\)
\(\Rightarrow x=21\)
Vậy: x=21