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a, \(\Leftrightarrow2x^2=72\)
\(\Leftrightarrow x^2=36\)
\(\Leftrightarrow x=\pm6\)
Vậy ...
\(b,\Leftrightarrow\dfrac{3}{5}x-0,75=2\dfrac{4}{5}.\dfrac{3}{7}=\dfrac{6}{5}\)
\(\Leftrightarrow\dfrac{3}{5}x=\dfrac{6}{5}+0,75=\dfrac{39}{20}\)
\(\Leftrightarrow x=\dfrac{39}{20}:\dfrac{3}{5}=\dfrac{13}{4}\)
Vậy ...
\(c,\Leftrightarrow2x=1\dfrac{5}{6}.\dfrac{6}{11}-\dfrac{3}{10}=\dfrac{7}{10}\)
\(\Leftrightarrow x=\dfrac{7}{10}:2=\dfrac{7}{20}\)
Vậy ...
\(d,\Leftrightarrow\dfrac{1}{x-7\dfrac{1}{3}}=1.5:2\dfrac{1}{4}=\dfrac{2}{3}\)
\(\Leftrightarrow x-7\dfrac{1}{3}=\dfrac{3}{2}\)
\(\Leftrightarrow x=\dfrac{3}{2}+7\dfrac{1}{3}=\dfrac{53}{6}\)
Vậy ...
a) 2x2 - 72 = 0
\(\Rightarrow\) 2x2 = 72
\(\Rightarrow\) x2 = 36 = 62 = (- 6)2
\(\Rightarrow\) x = 6 hoặc x = - 6
Vậy x = 6 hoặc x = - 6
b) (\(\dfrac{3}{5}\)x - 0,75) : \(\dfrac{3}{7}\) = \(2\dfrac{4}{5}\)
\(\Rightarrow\) (\(\dfrac{3}{5}\)x - 0,75) : \(\dfrac{3}{7}\) = \(\dfrac{14}{5}\)
\(\Rightarrow\) \(\dfrac{3}{5}\)x - \(\dfrac{3}{4}\) = \(\dfrac{6}{5}\)
\(\Rightarrow\) \(\dfrac{3}{5}\)x = \(\dfrac{39}{20}\)
\(\Rightarrow\) x = \(\dfrac{13}{4}\)
Vậy x = \(\dfrac{13}{4}\)
5x . (4x - 60) - (4x - 60) . 50 = 0
⇒ (4x - 60).(5x - 50) = 0
⇒ \(\left[{}\begin{matrix}4x-60=0\\5x-50=0\end{matrix}\right.\)
⇒ \(\left[{}\begin{matrix}4x=60\\5x=50\end{matrix}\right.\)
⇒ \(\left\{{}\begin{matrix}x=15\\x=10\end{matrix}\right.\)
Vậy x \(\in\) {15; 10}
(4x - 60 ) . (50- 5 ) =0
(4x-60).45=0
4x-60=0.45
4x-60=0
4x=0+60
4x=60
x=60:4
x=15
nhấn đúng cho mình nha
\(a,12\left(x-1\right)=0\\ x-1=0\\ x=1\\ b,45+5\left(x-3\right)=70\\ 5\left(x-3\right)=25\\ x-3=5\\ x=8\\ c,3.x-18:2=12\\ 3.x-9=12\\ 3.x=21\\ x=7\)
b, |5x-3| >= 7
=> 5x-3 < = -7 hoặc 5x-3 >= 7
=> x < = -4/5 hoặc x >= 2
Vậy ..........
Tk mk nha
5x + 3x + 6x = 280
14x = 280
x = 280 : 14
x = 20
Vậy x = 20
( 2x - 18 ) - 125 = 325
( 2x - 18 ) = 325 + 125
2x - 18 = 450
2x = 450 + 18
2x = 468
x = 234
Vậy x = 234
\(5x+3x+6x=280\)
\(\Rightarrow x\left(5+3+6\right)=280\)
\(\Rightarrow x.14=280\)
\(\Rightarrow x=20\)
b, \(\left(2x-18\right)-125=325\)
\(\Rightarrow2x-18=450\)
\(\Rightarrow2x=468\)
\(\Rightarrow x=234\)
a)
\(\left(1-\dfrac{1}{5}\right)x\left(1-\dfrac{2}{5}\right)x...x\left(1-\dfrac{9}{5}\right)\\ =\left(1-\dfrac{1}{5}\right)x...x\left(1-\dfrac{5}{5}\right)x...x\left(1-\dfrac{9}{5}\right)\\ =\left(1-\dfrac{1}{5}\right)x...x0x...x\left(1-\dfrac{9}{5}\right)=0\)
x là nhân nhé :))
b)
\(\dfrac{1}{2}x\dfrac{2}{3}x...x\dfrac{9}{10}\\ =\dfrac{1x2x...x9}{2x3x...x10}=\dfrac{2x3x...x9}{2x3x...x9x10}=\dfrac{1}{10}\)
a.11x-7x+x=325
<=> 5x= 325
<=> x=65
b.5x+(-15)-3x=25
<=> 5x-3x= 25+15
<=> 2x=40
<=>x=20
\(\left(x-3\right).\left(2.x^2+3\right)=0\)
\(< =>\left[{}\begin{matrix}x-3=0\\2.x^2+3=0\end{matrix}\right.< =>\left[{}\begin{matrix}x=0+3\\2.x^2=0-3\end{matrix}\right.\)
\(< =>\left[{}\begin{matrix}x=3\\2.x^2=-3\end{matrix}\right.< =>\left[{}\begin{matrix}x=3\\x^2=-\dfrac{3}{2}\end{matrix}\right.< =>\left[{}\begin{matrix}x=3\\x\in\varnothing\end{matrix}\right.\)<=>x=3
Vậy x=3
à cái này dễ ghê hôm nào ca thấy
nói miệng nha bn . cho 2 cái bằng không rồi tìm x bình thườg nha...kg cần k mik âu
~ hok tôt ~
=> 5x - 325= 0 hoặc 2x2 - 50 = 0
từ đây thì dễ bạn tự giải
hok tốt