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\(a,\left(13+150+47\right)-\left(13+47\right)\)
\(=13+150+47-13-47\)
\(=\left[13+\left(-13\right)\right]+\left[47+\left(-47\right)\right]+150\)
\(=0+0+150\)
\(=150\)
\(b,\left(-237\right)-\left[\left(-237+155\right)-55\right]\)
\(=\left(-237\right)+237+155-55\)
\(=0+100\)
\(=100\)
\(c,57.\left(62-43\right)-62.\left(57-43\right)\)
\(=57.62-57.43-62.57+62.43\)
\(=-57.43+62.43\)
\(=43.\left(-57+62\right)\)
\(=43.5\)
\(=215\)
a , ( 13 + 150 + 47 ) - ( 13 + 47 )
= 12 + 150 + 47 - 13 - 47
= [ 12 + ( - 13 ) ] + [ 47 + ( - 47 ) ] + 150
= - 1 + 0 + 150
= 149
b , ( - 237 ) - [ ( - 237 + 155 ) - 55 ]
= - 237 - [ - 237 + 155 - 55 ]
= - 237 + 237 - 155 + 55
= [ ( - 237 ) + 237 ] + [ ( - 155 ) + 55 ]
= 0 + ( - 100 )
= - 100
c , 57 . ( 62 - 43 ) - 62 . ( 57 - 43 )
= 57 . 62 - 57 . 43 - 62 . 57 - 62 . 43
= [ 57 . 62 - 62 . 57 ] . [ 62 . 43 - 62 . 43 ]
= 0 . 0
= 0
a)
9 8 − 4 7 + − 1 8 + 11 7 = 9 8 + − 1 8 + − 4 7 + 11 7 = 1 + 1 = 2
b)
− 5 7 ⋅ 3 11 + − 5 7 ⋅ 8 11 + 5 7 = − 5 7 3 11 + 8 11 − 1 = − 5 7 .0 = 0
Lời giải:
$x-\frac{31}{15}.\frac{26}{47}=\frac{-57}{15}.\frac{31}{47}-\frac{31}{15}:\frac{-141}{31}$
$x=\frac{-57}{47}.\frac{31}{15}-\frac{31}{15}.\frac{-31}{141}+\frac{31}{15}.\frac{26}{47}$
$x=\frac{31}{15}(\frac{-57}{47}-\frac{-31}{141}+\frac{26}{47})$
$x=\frac{31}{15}.\frac{-62}{141}=\frac{-1922}{2115}$
(1374x57+687x86):(26x13+14x74)
=78318+59082:338+1036
=137400:1374
=100
57.47 - 57.74 + 47.74 - 47.57
= (57.47 - 47.57) + (-57 . 74 + 47 . 74)
= 74. (-57 + 47)
= 74 . (-10) = -740
=(57.47-57.74)+(47.74-47.57)
=57.47-57.74+47.74-47.57
=(57.47-47.57)-(57.74-74.47)
=0-74(57-47)
=0-74.10
=0-740
=-740