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tính phân số
a)\(\frac{8}{5}+\frac{7}{6}+\frac{5}{9}-2\)
b)\(3-\frac{5}{6}-\frac{4}{9}+\frac{32}{24}\)

\(\frac{8}{5}+\frac{7}{6}+\frac{5}{9}-2\)
\(=\frac{83}{30}+\frac{-13}{9}=1\frac{29}{90}\)
\(3-\frac{5}{6}-\frac{4}{9}+\frac{32}{24}\)
\(=\frac{13}{6}-\frac{16}{9}\)
\(=\frac{7}{18}\)
Đây là chj tính nhẩm, còn em muốn giải chi tiết thì quy đồng lên để giải nha.
\(a,\frac{8}{5}+\frac{7}{6}+\frac{5}{9}-2\)
\(=\frac{83}{30}+\frac{5}{9}-2\)
\(=\frac{299}{90}-2\)
\(=\frac{119}{90}\)
\(b,3-\frac{5}{6}-\frac{4}{9}+\frac{32}{24}\)
\(=\frac{13}{6}-\frac{4}{9}+\frac{32}{24}\)
\(=\frac{31}{18}+\frac{32}{24}\)
\(=\frac{55}{18}\)
tính phân số
a)\(\frac{8}{5}+\frac{7}{6}+\frac{5}{9}-2\)
b)\(3-\frac{5}{6}-\frac{4}{9}+\frac{32}{24}\)

\(\left(a\right)=\frac{119}{90}\)
\(\left(b\right)=55,18\)
Mình lười tính, k nha

a) \(\frac{5}{6}< \frac{6}{7}\)
b) \(\frac{5}{8}=\frac{50}{80}\)
c) \(\frac{3}{4}>\frac{5}{7}\)
d) \(\frac{9}{7}< \frac{8}{5}\)

\(\frac{6}{8}+\frac{4}{8}=\frac{6+4}{8}=\frac{10}{8}=\frac{5}{4}\)
\(\frac{5}{7}-\frac{1}{7}=\frac{5-1}{7}=\frac{4}{7}\)
\(\frac{9}{6}+\frac{4}{8}=\frac{9\times3}{6\times3}+\frac{4\times2}{8\times2}=\frac{27}{19}+\frac{8}{19}=\frac{35}{19}\)
\(\frac{5}{7}-\frac{4}{6}=\frac{5\times6}{7\times6}-\frac{4\times7}{6\times7}=\frac{30}{42}-\frac{28}{42}=\frac{2}{42}=\frac{1}{21}\)
\(\frac{6}{8}+\frac{4}{8}=\frac{6+4}{8}=\frac{10}{8}=\frac{5}{4}\)

\(\frac{5}{6}\)\(+\frac{41}{6}+\left(\frac{225}{20}-\frac{37}{4}\right):\frac{25}{3}=\frac{23}{3}+2:\frac{25}{3}=\frac{23}{3}+\frac{6}{25}=\frac{593}{75}\)
\(\frac{5}{6}+6\frac{5}{6}.\left(11\frac{5}{20}-9\frac{1}{4}\right):8\frac{1}{3}\)
\(=\frac{5}{6}+\frac{41}{6}.\left(\frac{45}{4}-\frac{37}{4}\right):\frac{25}{3}\)
\(=\frac{5}{6}+\frac{41}{6}.2.\frac{3}{25}\)
\(=\frac{5}{6}+\frac{41}{25}\)
\(=\frac{371}{150}\)
\(\dfrac56+\dfrac98\)
\(=\dfrac{20}{24}+\dfrac{27}{24}\)
\(=\dfrac{20+27}{24}\)
\(=\dfrac{47}{24}=1\dfrac{23}{24}\)
\(\frac56+\frac98\)
= \(\frac{40+72}{48}\)
= \(\frac{40}{48}+\frac{72}{48}\)
= \(\frac{112}{48}\)
= \(\frac73\)