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A=36 x 350 + 1,2 x 20 x 3 + 9 x 4 x 4,5
= 12600 + 72 + 162
= 12834
y+yx2+yx3+yx4-566=2015
yx[1+2+3+4]-566=2015
yx10-566=2015
yx10=2015+566
yx10=2581
y=2591:10
y=259,1
a. \(\frac{565}{565}=1\); \(\frac{565565}{565565}=1\)
=> \(\frac{565}{565}=\frac{565565}{565565}\)
\(\frac{565}{565}=1\)
\(\frac{565565}{565565}=1\)
\(=>\frac{565}{565}=\frac{565565}{565565}\)
\(a̸\)
\(\frac{3}{5}-\frac{1}{2}.x=\frac{1}{4}\)
\(\frac{1}{2}.x=\frac{3}{5}-\frac{1}{4}\)
\(\frac{1}{2}.x=\frac{7}{20}\)
\(\Rightarrow\frac{7}{10}\)
\(b̸\)
\(11,3+2\left[x-\frac{1}{3}\right]=\frac{25}{6}\)
\(2\left[x-\frac{1}{3}\right]=\frac{25}{6}-11,3\)
\(2\left[x-\frac{1}{3}\right]=\frac{-107}{15}\)
\(x-\frac{1}{3}=\frac{-107}{15}:2\)
\(x-\frac{1}{3}=\frac{-107}{30}\)
\(x=\frac{-107}{30}+\frac{1}{3}\)
\(x=\frac{-97}{30}\)
\(a)\frac{3}{5}-\frac{1}{2}x=\frac{1}{4}\)
\(\implies\frac{1}{2}x=\frac{3}{5}-\frac{1}{4}\)
\(\implies\frac{1}{2}x=\frac{7}{20}\)
\(\implies x=\frac{7}{20}:\frac{1}{2}\)
\(\implies x=\frac{7}{10}\)
Vậy...
\(b) 11,3+2(x-\frac{1}{3})=\frac{25}{6}\)
\(\implies \frac{113}{10}+2x-2.\frac{1}{3}=\frac{25}{6}\)
\(\implies \frac{113}{10}+2x-\frac{2}{3}=\frac{25}{6}\)
\(\implies \frac{113}{10}+2x=\frac{25}{6}+\frac{2}{3}\)
\(\implies \frac{113}{10}+2x=\frac{29}{6}\)
\(\implies 2x=\frac{29}{6}-\frac{113}{10}\)
\(\implies 2x=\frac{-97}{15}\)
\(\implies x=\frac{-97}{30}\)
Vậy..
\(c)5x-435+2x+140+3x=565\)
\(\implies (5x+2x+3x)+(-435+140)=565\)
\(\implies 10x+(-295)=565\)
\(\implies 10x=565-(-295)\)
\(\implies 10x=860\)
\(\implies x=86\)
Vậy...
~ hok tốt a~
5 + 566(5.3-7.2)
= 5 + 566.(15-14)
= 5 + 566.1
= 5 + 566
= 571
k cho mình nha!
\(565+x=566\)
\(x=566-565\)
\(x=1\)
\(k.nha\)
\(565+x=566\)
\(x=566-565\)
\(x=1\)
hok tốt