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\(\frac{3^4.2^3-3^4.4}{3^5.3^2-3^5.5}=\frac{3^4.\left(2^3-4\right)}{3^5.\left(3^2-5\right)}=\frac{8-4}{3.\left(9-5\right)}=\frac{4}{3.4}=\frac{1}{3}\)
\(\frac{3^4\cdot2^3-3^4\cdot4}{3^5.3^2-3^5\cdot5}=\frac{3^4\left(8-4\right)}{3^5\left(9-5\right)}=\frac{4}{3\cdot4}=\frac{1}{3}\)
Bài làm:
\(A=\frac{3^4.2^3-3^4.4}{3^5.3^2-3^5.5}\)
\(A=\frac{2^2.3^4\left(2-1\right)}{3^5\left(3^2-5\right)}\)
\(A=\frac{4.1}{3.4}=\frac{1}{3}\)
làm ơn giúp mình ,bạn nào làm nhanh đúng mình chọn cho nhanh nha mọi người
\(\dfrac{a}{b}=\dfrac{3^4\cdot2^2\cdot\left(2-1\right)}{3^5\cdot\left(3^2-5\right)}=\dfrac{2^2}{3}\cdot\dfrac{1}{4}=\dfrac{1}{3}\)
\(\dfrac{c}{d}=\dfrac{5^3\left(7-2\right)}{5^3\left(7-4\right)}=\dfrac{5}{3}\)
Do đó: a/b<c/d
\(\dfrac{-2}{5}\cdot\dfrac{5}{6}+\dfrac{-2}{5}\cdot\dfrac{1}{6}-2\dfrac{3}{5}\)
\(=\dfrac{-2}{5}\left(\dfrac{5}{6}+\dfrac{1}{6}\right)-\dfrac{13}{5}\)
\(=\dfrac{-2}{5}\cdot1-\dfrac{13}{5}\)
\(=\dfrac{-2}{5}-\dfrac{13}{5}\)
\(=-3\)
#Sahara |
\(=\dfrac{-12}{14}-\dfrac{2}{14}+\dfrac{3}{10}=-1+\dfrac{3}{10}=-\dfrac{7}{10}\)
Ta có: \(\dfrac{-6}{7}+\dfrac{9}{4}\cdot\dfrac{2}{15}-\dfrac{2}{14}\)
\(=\dfrac{-6}{7}-\dfrac{1}{7}+\dfrac{18}{60}\)
\(=-1+\dfrac{3}{10}\)
\(=\dfrac{-10+3}{10}=\dfrac{-7}{10}\)
=(-6/7 - 2/14) + 9/4 * 2/15
=(-6/7 - 1/7) + 3/2 * 1/5
=-1 + 3/10
=-7/10
5.5+6+4.2
=25+6+8
=31+8
=39
5.5+6+4.2
=25+6+8
=31+8
=39