Hãy nhập câu hỏi của bạn vào đây, nếu là tài khoản VIP, bạn sẽ được ưu tiên trả lời.
a) \(S4=\frac{3}{50}+\frac{3}{150}+\frac{3}{300}+...+\frac{3}{9500}\)
\(S4=\frac{3}{5.10}+\frac{3}{10.15}+\frac{3}{15.20}+...+\frac{3}{95.100}\)
\(S4=\frac{3}{5}\left(\frac{1}{5}-\frac{1}{10}+\frac{1}{10}-\frac{1}{15}+\frac{1}{15}-\frac{1}{20}+...+\frac{1}{95}-\frac{1}{100}\right)\)
\(S4=\frac{3}{5}\left(\frac{1}{5}-\frac{1}{100}\right)\)
\(S4=\frac{3}{5}.\frac{19}{100}\)
\(S4=\frac{57}{500}\Rightarrow S=\frac{57}{500}:4=\frac{57}{2000}\)
b) \(S5=\frac{55}{11.16}+\frac{55}{16.21}+...+\frac{55}{36.41}\)
\(S5=\frac{55}{5}.\left(\frac{1}{11}-\frac{1}{16}+\frac{1}{16}-\frac{1}{21}+...+\frac{1}{36}-\frac{1}{41}\right)\)
\(S5=11.\left(\frac{1}{11}-\frac{1}{41}\right)\)
\(S5=11.\frac{30}{451}\)
\(S5=\frac{30}{41}\Rightarrow S=\frac{30}{41}:5=\frac{6}{41}\)
\(\frac{29}{68}\times\frac{31}{55}+\frac{31}{68}\times\frac{26}{55}=\frac{31}{68}\times\frac{29}{55}+\frac{31}{68}\times\frac{26}{55}\)
\(=\frac{31}{68}\times\left(\frac{29}{55}+\frac{26}{55}\right)\)
\(=\frac{31}{68}\)
\(\frac{5}{11.16}+\frac{5}{16.21}+..+\frac{5}{36.41}\)
\(=\frac{1}{11}-\frac{1}{16}+\frac{1}{16}-\frac{1}{21}+..+\frac{1}{36}-\frac{1}{41}\)
\(=\frac{1}{11}-\frac{1}{41}\)
= bn tự timnhs nha......................................
@@@@@@@@@@@@@@@@@@@@@@@@@@@@@
\(\frac{5}{11.16}+\frac{5}{16.21}+...+\frac{5}{36.41}\)
\(=\frac{1}{11}-\frac{1}{16}+\frac{1}{16}-\frac{1}{21}+...+\frac{1}{36}-\frac{1}{41}\)
\(=\frac{1}{11}-\frac{1}{41}\)
\(=\frac{30}{451}\)
_Chúc bạn học tốt_
Bài 2:
a. $=62-81-12+59-9=(62-12)+(59-9)-81$
$=50+50-81=100-81=19$
b. $=39+13-26-62-39=(39-39)+13-(26+62)$
$=0+13-88=-(88-13)=-75$
c. $=(32-42)+(36-34)+(40-38)=10+2+2=14$
d. $=92-55+8-45=(92+8)-(55+45)=100-100=0$
Bài 1:
a. $=(387-87)-224=300-224=76$
b. $=-(75+35)+379=-110+379=379-110=269$
c. $=(11+15)-(13+17)=25-30=-5$
d. $=(31-21)-(27-24)=10-3=7$
Thì vì 3111<3211 mà3211=(25)11 thi bằng 25×11 =255
Câu kia cũng thế
Khi 255va256 đã có chung cơ số thì ta so sánh số mũ so mũ nào lớn hơn thì lũy thừa đó lớn hơn
255<256hay3211<1614
ta thấy 3111<3211<1614<1714
suy ra 3111<1714
a: =(21-11)+(22-12)+(23-13)+(24-14)
=10+10+10+10
=40
b: =(34-14)+(35-15)+(36-16)+(37-17)
=20+20+20+20
=80
\(\dfrac{55}{11}\cdot6+\dfrac{55}{16}\cdot21+\dfrac{55}{21}\cdot26+\dfrac{55}{26}\cdot31+\dfrac{55}{31}\cdot36+\dfrac{55}{36}\cdot41=30+\dfrac{1155}{16}+\dfrac{1430}{21}+\dfrac{1705}{26}+\dfrac{1980}{31}+\dfrac{2255}{36}=\dfrac{12186720}{406224}+\dfrac{29324295}{406224}+\dfrac{27661920}{406224}+\dfrac{26638920}{406224}+\dfrac{25945920}{406224}+\dfrac{25445420}{406224}=\dfrac{147203195}{406224}\)