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a) \(x^{20}=x\)
\(\Rightarrow\orbr{\begin{cases}x=0\\x=1\end{cases}}\)
b) \(x^6:x^3=125\)
\(\Leftrightarrow x^{6-3}=125\)
\(\Leftrightarrow x^3=125\)
\(\Leftrightarrow x^3=5^3\)
\(\Leftrightarrow x=5\)
c) \(4x^3+12=120\)
\(\Leftrightarrow4x^3=120-12\)
\(\Leftrightarrow4x^3=108\)
\(\Leftrightarrow x^3=27\)
\(\Leftrightarrow x^3=3^3\)
\(\Leftrightarrow x=3\)
d) \(x^{10}=x^1\)
\(\Leftrightarrow x^{10}=x\)
\(\Rightarrow\orbr{\begin{cases}x=1\\x=0\end{cases}}\)
e) \(\left(2x-15\right)^5=\left(2x-15\right)^3\)
\(\Leftrightarrow\left(2x-15\right)^5-\left(2x-15\right)^3=0\)
\(\Leftrightarrow\left(2x-15\right)^3\left[\left(2x-15\right)^2-1\right]=0\)
\(\Rightarrow\orbr{\begin{cases}\left(2x-15\right)^3=0\\\left(2x-15\right)^2-1=0\end{cases}}\)
\(\Rightarrow\orbr{\begin{cases}2x-15=0\\\orbr{\begin{cases}2x-15=1\\2x-15=-1\end{cases}}\end{cases}}\Rightarrow\orbr{\begin{cases}x=\frac{15}{2}\\\orbr{\begin{cases}x=8\\x=-7\end{cases}}\end{cases}}\)\(\Rightarrow2x-15=0\)hoặc \(2x-15=1\) hoặc \(2x-15=-1\)
\(\Rightarrow x=\frac{15}{2}\)hoặc \(x=8\)hoặc \(x=7\)
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a) \(x\cdot x^2\cdot x^3\cdot x^4=1024\)
\(x^{1+2+3+4}=1024\)
\(x^{10}=1024\)
\(x^{10}=2^{10}\)
\(\Rightarrow x=2\)
b) \(\left(x+5\right)\cdot2^3-2^2\cdot5=2^2\cdot3\cdot5\)
\(2^2\cdot\left[2\left(x+5\right)-5\right]=2^2\cdot15\)
\(2^2\cdot\left[2x+10-5\right]=2^2\cdot15\)
\(2^2\cdot\left[2x+5\right]=2^2\cdot15\)
\(\Rightarrow2x+5=15\)
\(\Rightarrow2x=15+5=20\)
\(\Rightarrow x=\frac{20}{2}=10\)
a)\(x.x^2.x^3.x^4=1024\Rightarrow x^{1+2+3+4}=2^{10}\Rightarrow x^{10}=2^{10}\Rightarrow x=2\)
b)\(\left(x+5\right).2^3-2^2.5=2^2.3.5\Rightarrow\left(x+5\right).2^3=2^2.3.5+2^2.5\)
\(\Rightarrow\left(x+5\right).2^3=2^2.5.\left(3+1\right)=2^2.5.2^2=2^4.5\)
\(\Rightarrow x+5=\frac{2^4.5}{2^3}=10\Rightarrow x=5\)
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100=25 .4 =5^2.4
5^2019:( 5^2013-5^2.4.5^2010)=5^2019: ( 5^2013-5^2012.4)=5^2019: (5^2012.(5-4))
=5^2019:5^2012=5^7(=78125)
Học tốt
5x = 52019 : (52013 -100*52010)
<=> 5x = 52019 : (52010 .(53-100))
<=> 5x = 52019 : (52010 . 25)
<=> 5x = 52019 : 52012
<=> 5x = 57
<=> x = 7
Vậy x = 7
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theo công thức: D=(1+2+3+...+100)2
D=[(1+100)*100/2]2
D=[101*50]2
D=50502=25502500
công thức dạng chung n3=(n-2).n.(n+2) - 4n bạn thay vào òi làm nhé:
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1/2^2+1/3^2+1/4^2+...+1/100^2
+) 1/2^2=1/2.2< 1/1.2
+) 1/3^2 = 1/3.3 < 1/2.3
+) 1/4^2 =1/4.4 < 1/3.4
+) ...
+) 1/100^2 = 1/100.100 < 1/99.100
=> 1/2^2+1/3^2+1/4^2+...+1/100^2 < 1/1.2+ 1/2.3+1/3.4+..+1/99.100 = 1/1-1/2+1/2-1/3+1/3-1/4+...+1/99-1/100 = 1-1/100 < 1
=> 1/2^2+1/3^2+1/4^2+...+1/100^2 < 1
(Hoi kho nhìn mot chút , xin loi nhe! Nhung bai giai nhu tren la dung 100% roi day!!!! Tick cho minh nhe Vy!!!!!!!!!!!!)
53 : x=25
x=53 : 25
x=125:25
x=5
53 : 2 + 100=125 ( tính được, nhưng ko rõ cách viết )
x=2