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2x+1-2x=32
2x.2-2x=32
2x(2-1)=32
2x.1=32
2x=25
=> x=5
Vậy x=5
525.5x-1=525
5x-1=525:525
5x-1=1
5x-1=50
=> x-1=0
x=1
Vậy x=1.
2x+1-2x = 32
<=>2x.2 - 2x = 32
<=> 2x.(2-1) = 32
<=> 2x =32
<=> 2x = 25
<=> x = 5
Vậy x = 5
525.5x-1=525
<=> 5x-1 = 1
<=> 5x-1 = 50
<=> x - 1 = 0
<=> x = 1
Vậy x = 1
a, 2x - 20 = 35 : 32
=> 2x - 1 = 33
=> 2x - 1 = 27
=> 2x = 28
=> x = 14
b, 525.5x + 1 = 525
=> 525+x+1 = 525
=> 25 + x + 1 = 25
=> 26 + x = 25
=> x = -1
a. 2x - 20 = 35 : 32
2x - 1 = 33
2x = 27 + 1
2x = 28
x = 28 : 2
x = 14.
Ta có : 525.5x+1=525
=> 5x+1=525:525
=> 5x+1=1
=> 5x=\(\frac{1}{5}\)\(=\frac{1}{5^1}\)
=> 5x=5-1
=> x=-1
2346 : (25 + x) = 23
=> 25 + x = 2346 : 23 = 102
=> x = 102 - 25 = 77
Vậy x = 77
2(x-3) + 5(x+4) = 49
=> 2x - 6 + 5x + 20 = 49
=> 7x + (20 - 6) = 49
=> 7x + 14 = 49
=> 7x = 49 - 14 = 35
=> x = 35 : 7 = 5
Vậy x = 5
(2x-10)3 . 251007 = \(5^2.5^{2015}\)
\(\left(2x-10\right)^3.5^{2014}=5^{2014}.5^3\)
\(\left(2x-10\right)^3=5^3\)
2x - 10 = 5
=> 2x = 5 + 10 = 15
=> x = 15 2 = 7,5
Vậy x = 7,5
1. a. 2346:(25+x)=23
=> 25+x=2346:23
=> 25+x=102
=> x=102-25
=> x=77
b. 2(x-3)+5(x+4)=49
=> 2x-6+5x+20=49
=> 7x+14=49
=> 7x=49-14
=> 7x=35
=> x=35:7
=> x=5
c. (2x-10)3.251007=52.52015
=> (2x-10)3.(52)1007=52017
=> (2x-10)3.52014=52017
=> (2x-10)3=52017:52014
=> (2x-10)3=53
=> 2x-10=5
=> 2x=5+10
=> 2x=15
=> x=15:2
=> x=7,5
525 x 5x-1 = 525
5x-1 = 525 : 525
5x+1 = 1
Vì bất kì luỹ thừa nào mũ 0 đều bằng 1
Nên => x = 1 (vì 1-1 = 0 mà 50 = 1 => x=1)
\(5^{25}\times5^{x+1}=5^{25}\)
\(5^{x+1}=5^{25}\div5^{25}\)
\(5^{x+1}=1\)
\(5^x\times5=5^0\)
\(5^x=5^0\div5\)
\(\Rightarrow5^x\in\varnothing\)
\(\Rightarrow x\in\varnothing\)
Vậy \(x\in\varnothing\)
Tìm x , biết:
a, ( 2x + 1)2 = 93
b, ( 2x + 1)3 = 1252
c, 252< 5x+3 < 254
d, x15= x
e, ( x - 5)4 = ( x-5)6
A) \(\left(2x+1\right)^2=9^3\)
\(\Rightarrow\left(2x+1\right)^2=9^2\times9\)
\(\Rightarrow2x+1=81\)
\(\Rightarrow2x=81-1\)
\(\Rightarrow2x=80\)
\(\Leftrightarrow x=40\)
B) \(\left(2x+1\right)^3=125^2\)
\(\Rightarrow\left(2x+1\right)^3=5^3\)
\(\Rightarrow2x+1=5\)
\(\Rightarrow2x=5-1\)
\(\Leftrightarrow x=2\)
C) \(25^2< 5^{x+3}< 25^4\)
\(\Leftrightarrow5^4< 5^{x+3}< 5^6\)
\(\Leftrightarrow4< x+3< 6\)
\(\Rightarrow x+3=5\)
\(\Rightarrow x=2\)
D) \(x^{15}=x\)
Nếu \(x>1\)thì \(x^{15}>x\)
Vậy \(x=1\)
E) \(\left(x-5\right)^4=\left(x-5\right)^6\)
\(\Rightarrow\left(x-5\right)^4-\left(x-5\right)^6=0\)
\(\Rightarrow\left(x-5\right)\times\left(1^4-1^6\right)=0\)
\(\Rightarrow x-5=0\)
\(\Leftrightarrow x=5\)
KÍCH MK NHA BẠN
a) 2(x-1)^2=800 5^x+1.5^5=5^9
(x-1)^2=800:2 5^x.5.5^5=5^9
(x-1)^2=400 5^x.5^6=5^9
(x-1)^2=20^2 5^x=5^9:5^6
(x-1)=20 5^x=5^3
x=20+1 => x=3
x=21
c) 25^2 : 5(x-1)=25 d)4^x . 7 +8^2=176
625:5(x-1)=25 4^x . 7+64=176
5(x-1)=625:25 4^x . 7=176:64
5(x-1)=25 4^x . 7=112
x-1=25:5 4^x =112:7
x-1=5 4^x=16
x=5+1 mà 16=4^2
x=6 =>4^x=4^2
=>x=2
bài e) mình ko biết !! ^.^
125(28+72)-25(3^2.4+64)
=125.100-25(9.4+64)
=125.100-25.(36+64)
=125.100-25.100
=12500-2500
=10000
Đề bài : Tìm x?
525.5x-1=525
5x-1=525:525
5x-1=1
5x-1=50
=> x-1=0
x=0+1
x=1
Vậy x=1
Lần sau bạn nhớ ghi đầy đủ đề bài Toán nhé!
525.5x-1=525
5x-1=525:525
5x-1=1
5x-1=50
x-1=0
x=0+1
x=1
Vậy x=1