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a, cách 1 : 7/11 : 3/5 + 4/11 : 3/5 b, cách 1 : [ 6,24 + 1,26 ] : 0,75
=[ 7/11 + 4/11 ] : 3/5 = 7,5 : 0,75
= 1 : 3/5 = 10
= 5/3 cách 2 : [ 6,24 + 1,26 ] : 0,75
cách 2 :7/11 : 3/5 + 4/11 : 3/5 = 6,24 : 0,75 + 1,26 : 0,75
=35/33 + 20/33 = 8,32 + 1,68
=55/33 = 10
=5/3
\(\frac{7}{11}:\frac{3}{5}+\frac{4}{11}:\frac{3}{5}\)
= ( \(\frac{7}{11}+\frac{4}{11}\)) : \(\frac{3}{5}\)
= 1 : \(\frac{3}{5}\)
= \(\frac{5}{3}\)
\(\frac{23}{12}\)
\(\frac{314}{105}\)
\(\frac{59}{60}\)
\(\frac{199}{90}\)
\(\frac{1}{18}\)
\(\frac{13}{36}\)
\(\frac{4}{221}\)
\(\frac{4}{85}\)
\(\left(\times-\frac{1}{5}\right):\left(\frac{1}{2}+\frac{1}{6}+\cdot\cdot\cdot+\frac{1}{110}\right)=\frac{1}{5}\)
\(\Rightarrow\left(\times-\frac{1}{5}\right):\left(\frac{1}{1\times2}+\cdot\cdot\cdot+\frac{1}{10\times11}\right)=\frac{1}{5}\)
\(\Rightarrow\left(\times-\frac{1}{5}\right):\left(1-\frac{1}{2}+\cdot\cdot\cdot+\frac{1}{10}-\frac{1}{11}\right)=\frac{1}{5}\)
\(\Rightarrow\left(\times-\frac{1}{5}\right):\left(1-\frac{1}{11}\right)=\frac{1}{5}\)
\(\Rightarrow\left(\times-\frac{1}{5}\right):\frac{10}{11}=\frac{1}{5}\)
\(\Rightarrow\left(\times-\frac{1}{5}\right)=\frac{1}{5}\times\frac{10}{11}\)
\(\Rightarrow\times-\frac{1}{5}=\frac{2}{11}\)
\(\Rightarrow\times=\frac{2}{11}+\frac{1}{5}\)
\(\Rightarrow\times=\frac{21}{55}\)
\(\left(x-\frac{1}{5}\right):\left(\frac{1}{2}+\frac{1}{6}+\frac{1}{12}+...+\frac{1}{110}\right)=\frac{1}{5}\)
\(\Rightarrow\left(x-\frac{1}{5}\right):\left(\frac{1}{1\times2}+\frac{1}{2\times3}+\frac{1}{3\times4}+...+\frac{1}{10\times11}\right)=\frac{1}{5}\)
\(\Rightarrow\left(x-\frac{1}{5}\right):\left(1-\frac{1}{2}+\frac{1}{2}-\frac{1}{3}+\frac{1}{3}-\frac{1}{4}+...+\frac{1}{10}-\frac{1}{11}\right)=\frac{1}{5}\)
\(\Rightarrow\left(x-\frac{1}{5}\right):\left(1-\frac{1}{11}\right)=\frac{1}{5}\)
\(\Rightarrow\left(x-\frac{1}{5}\right):\frac{10}{11}=\frac{1}{5}\)
\(\Rightarrow x-\frac{1}{5}=\frac{1}{5}\times\frac{10}{11}\)
\(\Rightarrow x-\frac{1}{5}=\frac{2}{11}\)
\(\Rightarrow x=\frac{2}{11}+\frac{1}{5}\)
\(\Rightarrow x=\frac{21}{55}\)
Vậy \(x=\frac{21}{55}\)
5\12+5\6-0,75
= 5/4 - 0,75
= 0,5
\(\dfrac{5}{12}+\dfrac{5}{6}-0,75\\ =\dfrac{5}{12}+\dfrac{10}{12}-\dfrac{3}{4}\\ =\dfrac{15}{12}-\dfrac{9}{12}=\dfrac{6}{12}=\dfrac{1}{2}\)