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LH
12 tháng 2 2020
(-5/11:13/8-5/11:13/5)+-1/33
= (-5/11.8/13-5/11.5/13)+-1/33
= -5/11.(8/13+5/13)+-1/33
=-5/11.1+-1/33
=-5/11+-1/33
=-16/33
mk lm đại ko bt đúng hay ko
test lại dùm mk nha
12 tháng 1 2023
\(=\dfrac{-5}{11}\left(\dfrac{13}{8}+\dfrac{13}{5}\right)+\dfrac{-1}{33}\)
\(=\dfrac{-5}{11}\cdot\dfrac{13\cdot13}{40}+\dfrac{-1}{33}\)
\(=\dfrac{-1}{8}\cdot\dfrac{169}{11}+\dfrac{-1}{33}=\dfrac{-169}{88}-\dfrac{1}{33}=\dfrac{-515}{264}\)
13 tháng 2 2020
Trả lời:
\(\left(\frac{-5}{11}\text{÷}\frac{13}{8}-\frac{5}{11}\text{÷}\frac{13}{5}\right)+\frac{-1}{33}\)
\(=\left(\frac{-5}{11}.\frac{8}{13}+\frac{-5}{11}.\frac{5}{13}\right)+\frac{-1}{33}\)
\(=\frac{-5}{11}.\left(\frac{8}{13}+\frac{5}{13}\right)+\frac{-1}{33}\)
\(=\frac{-5}{11}+\frac{-1}{33}\)
\(=\frac{-15-1}{33}\)
\(=\frac{-16}{33}\)
#Huyền Anh
10 tháng 11 2018
a) \(\dfrac{-3}{5}.51\dfrac{11}{13}+\dfrac{3}{5}.21\dfrac{11}{13}\)
\(=\dfrac{-3}{5}.\left(51\dfrac{11}{13}-21\dfrac{11}{13}\right)\)
\(=\dfrac{-3}{5}.30\)
\(=-18.\)
b) \(\left|\dfrac{-3}{4}\right|.\left|-\dfrac{2}{3}\right|=\dfrac{3}{4}.\dfrac{2}{3}=\dfrac{1}{2}\).
c) \(\dfrac{-3}{5}+5\dfrac{1}{13}-\dfrac{2}{3}+1\dfrac{3}{5}-\dfrac{11}{33}\)
\(=\left(1\dfrac{3}{5}-\dfrac{3}{5}\right)+5\dfrac{1}{13}-\left(\dfrac{2}{3}+\dfrac{11}{33}\right)\)
\(=1+\dfrac{66}{13}-1\)
\(=\dfrac{66}{13}.\)
d) \(\dfrac{3}{4}.\sqrt{16}-10.\sqrt{0,81}\)
\(=\dfrac{3}{4}.4-10.\dfrac{9}{10}\)
\(=3.9\)
\(=27.\)
e) \(\left(\dfrac{3}{4}\right)^3:\left(\dfrac{-3}{8}\right)^3=\dfrac{3^3}{4^3}.\dfrac{\left(-8\right)^3}{3^3}=\left(\dfrac{-8}{4}\right)^3=\left(-2\right)^3=-8\)
f) \(\dfrac{6^4.15^3}{8.9^3.10^3}=\dfrac{2^4.3^4.3^3.5^3}{2^3.3^6.2^3.5^3}=\dfrac{2.3^7}{2^3.3^6}=\dfrac{3}{2^2}=\dfrac{3}{4}.\)
A
7 tháng 11 2018
( -1,25) . 14,7. ( -8 )
= \(\frac{-5}{4}\). \(\frac{147}{10}\)\(.\frac{\left(-8\right)}{1}\)
= \(\frac{\left(-5\right).147.\left(-8\right)}{4.10.1}.\)
= \(\frac{\left[\left(-5\right).\left(-8\right)\right].147}{\left(4.10\right).1}\)
= \(\left[\frac{-5}{4}.\frac{-8}{10}\right].147\)
=147
6 tháng 9 2017
\(A=\left(-\frac{5}{11}\right).\frac{7}{15}+\frac{11}{-5}.\frac{30}{33}\)
\(A=-\frac{7}{33}+-2\)
\(A=-\frac{73}{33}\)
[ A] = -2
AH
Akai Haruma
Giáo viên
19 tháng 2 2019
Lời giải:
Ta có:
\(A=\frac{\frac{3}{4}-\frac{3}{11}+\frac{3}{13}}{\frac{5}{4}-\frac{5}{11}+\frac{5}{13}}+\frac{\frac{1}{2}-\frac{1}{3}+\frac{1}{4}}{\frac{5}{4}-\frac{5}{6}+\frac{5}{8}}\) \(=\frac{3\left(\frac{1}{4}-\frac{1}{11}+\frac{1}{13}\right)}{5\left(\frac{1}{4}-\frac{1}{11}+\frac{1}{13}\right)}+\frac{\frac{1}{2}-\frac{1}{3}+\frac{1}{4}}{\frac{5}{2}\left(\frac{1}{2}-\frac{1}{3}+\frac{1}{4}\right)}\)
\(=\frac{3}{5}+\frac{1}{\frac{5}{2}}=\frac{3}{5}+\frac{2}{5}=\frac{5}{5}=1\)
19 tháng 12 2017
\(A=\dfrac{\dfrac{3}{7}-\dfrac{3}{11}+\dfrac{3}{13}}{\dfrac{5}{7}-\dfrac{5}{11}+\dfrac{5}{13}}+\dfrac{\dfrac{1}{2}-\dfrac{1}{3}+\dfrac{1}{4}}{\dfrac{5}{4}+\dfrac{5}{8}-\dfrac{5}{6}}=\dfrac{\dfrac{3}{7}-\dfrac{3}{11}+\dfrac{3}{13}}{\dfrac{5}{7}-\dfrac{5}{11}+\dfrac{5}{13}}+\dfrac{\dfrac{2}{4}+\dfrac{2}{8}-\dfrac{2}{6}}{\dfrac{5}{4}+\dfrac{5}{8}-\dfrac{5}{6}}=\dfrac{3\left(\dfrac{1}{7}-\dfrac{1}{11}+\dfrac{1}{13}\right)}{5\left(\dfrac{1}{7}-\dfrac{1}{11}+\dfrac{1}{13}\right)}+\dfrac{2\left(\dfrac{1}{4}+\dfrac{1}{8}-\dfrac{1}{6}\right)}{5\left(\dfrac{1}{4}+\dfrac{1}{8}-\dfrac{1}{7}\right)}=\dfrac{3}{5}+\dfrac{2}{5}=1\)