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a) 5x = 125
5x = 53
=> x = 3
b) x3 = 64
x3 = 43
=> x = 4
c) ( x - 1 ) 2 = 25
( x - 1 ) 2 = 52
=> x - 1 = 5
=> x = 5 + 1
=> x = 6
d) 5x + 5x+2 = 130
5x . 1 + 5x . 52 = 130
5x . ( 1 + 52 ) = 130
5x . 26 = 130
5x = 130 : 26
5x = 5
=> x = 1
a: \(4^5\cdot8^7=2^{10}\cdot2^{21}=2^{31}\)
b: \(125^5\cdot25^3=5^{15}\cdot5^6=5^{21}\)
\(5^x=25\div125\)
\(\Leftrightarrow5^x=\frac{1}{5}\)
\(\Leftrightarrow5^x=5^{-1}\)
Vậy x = -1
\(5^a=25:125\)
\(\Rightarrow5^a=\frac{1}{5}\)
\(\Rightarrow5^a=5^{-1}\)
\(\Rightarrow a=-1\)
23.27.24=23+7+4=214
23.24:25=23+4-5=27
(-3)+(-125)+(-25)
=-128+(-25)
=-153
25+(-38)=25-38=-13
126+159=285
120+(-135)+200
=120-135+200
=-15+200
=185
2^3x2^7=2^10x2^4=2^14=16384
2^3x2^4=2^7:2^5=2^2=4
1300-(150.2+(900+90):9)=1300-(150.2+990:9)=1300-(300+11)=1300-311=989
(-3) + (-125)+(-25)= -(3+125+25)= -153
25 + (-38)= -(38-25)= - 13
(126)+159=285
(120)+(-135)+200= -(135-120) + 200= (-15) + 200= +(200-15)=185
\(4^8.2^{20}=2^{16}.2^{20}=2^{36}\)
\(9^{12}.27^5.81^4=3^{24}.3^{15}.3^{16}=3^{55}\)
mk chỉnh đề
\(64^3.4^5.16^2=4^9.4^5.4^4=4^{18}\)
\(25^{20}.125^4=5^{40}.5^{12}=5^{52}\)
\(x^7.x^4.x^3=x^{14}\)
5x.25=125
5x.52=53
5x=53:52
=>x=1
\(5^x.25=125\)
\(5^x.5^2=5^3\)
\(5^{x+2}=5^3\)
\(x+2=3\)
\(x=3-2\)
\(x=1\)