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1+1+1+1+1=...?
2+2+2+2+2=...?
3+3+3+3+3=...?
4+4+4+4+4=4x5=20
5+5+5+5+5=5x5=25
6+6+6+6+6=6x5=30
7+7+7+7+7=7x5=35
8+8+8+8+8=8x5=40
9+9+9+9+9=9x5=45
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a/ (x+3) . (X+2)=0
=>\(\hept{\begin{cases}x+3=0\\x+2=0\end{cases}\Rightarrow\hept{\begin{cases}x=-3\\x=-2\end{cases}}}\)
vậy x\(\in\left\{-3,-2\right\}\)
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a) \(\frac{2}{9}+\frac{1}{5}+\frac{7}{9}+\frac{4}{5}=\left(\frac{2}{9}+\frac{7}{9}\right)+\left(\frac{1}{5}+\frac{4}{5}\right)= 1+1=2 \)
b) \(\frac{19}{37}+\left(1+\frac{19}{37}\right)=\left(\frac{19}{37}-\frac{19}{37}\right)+1=0+1=1\)
c) \(\frac{9}{8}-\left(\frac{17}{7}-\frac{3}{7}\right)+\frac{7}{8}=\frac{9}{8}+\frac{7}{8}-\left(\frac{17}{7}-\frac{3}{7}\right)=2-2=0\)
d) \(\frac{3}{5}\times\frac{8}{27}\times\frac{5}{3}=\frac{3}{5}\times\frac{5}{3}\times\frac{8}{27}=1\times\frac{8}{27}=\frac{8}{27}\)
e) \(\frac{7}{19}\times\frac{1}{3}+\frac{7}{19}\times\frac{2}{3}=\frac{7}{19}\times\left(\frac{1}{3}+\frac{2}{3}\right)=\frac{7}{19}\times1=\frac{7}{19}\)
f) \(\frac{12}{5}\times4-4\times\frac{7}{5}=4\times\left(\frac{12}{5}-\frac{7}{5}\right)=4\times1=4\)
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(3+7)+(4+6) +( 5+5)+(6+4)+(7+3)+(8+2)+(9+1)+(2+8)+(4+6)+(6+4)+(7+3)+(8+2)+(9+1)+(8+9)= 147
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1 + 2 + 3 + 5 + 6 + 7 - 7 - 6 - 5 - 3 - 2 - 1
= ( 1 - 1 ) + ( 2 - 2 ) + ( 3 - 3 ) + ( 5 - 5 ) + ( 6 - 6 ) + ( 7 - 7 )
= 0
nha
1 k mk nha!
5 + 3 - 7 = 1
Ai , mình tích lại cho !