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\(4x^3+15=47\)
\(4x^3=47-15\)
\(4x^3=32\)
\(x^3=32:4\)
\(x^3=8\)
\(x^3=2^3\)
\(\Rightarrow x=2\)
\(4.2^x-3=125\)
\(4.2^x=125+3\)
\(4.2^x=128\)
\(2^x=128:4\)
\(2^x=32\)
\(2^x=2^5\)
\(\Rightarrow x=5\)
\(4x^3+15=47\)
\(4x^3=47-15\)
\(4x^3=32\)
\(x^3=32:4\)
\(x^3=8\)
\(x^3=2^3\)
\(\Rightarrow x=2\)
\(4.2^x-3=125\)
\(4.2^x=125+3\)
\(4.2^x=128\)
\(2^x=128:4\)
\(2^x=32\)
\(2^x=2^5\)
\(\Rightarrow x=5\)
a, \(4x^2+15=47\\ =>4x^2=47-15=32\\ =>x^2=32:4=8\\ =>x\ne N\)
b, \(4.2^x-3=125\\ =>4.2^x=125+3=128\\ =>2^x=128:4=32\\ Mà:2^5=32\\ =>x=5\)
a) 4\(x^2\)+ 15 = 47
=> 4\(x^2\) = 47 - 15
=> 4\(x^2\)= 32
=> \(x^2\)= 32 : 4
=> \(x^2\)= 8
=> \(x\) \(\ne\) N
b) 4. \(2^x\) - 3 = 125
=> 4.2\(^x\)= 125 + 3
=> 4. \(2^x\)= 128
=> \(2^x\)= 128 : 4
=> \(2^x\)= 32
Mà \(2^5\) = 32 nên \(x\) = 5
a) 47.(-147) - 47.(-47)
= 47.(-147 + 47)
= 47 . (-100)
= -4700
b) 24.(15 - 4) + 4.(24 - 15)
= 24.15 - 25.4 + 4.25 - 4.15
= (24 - 4).15 - (25.4 - 4.25)
= 20 . 15
= 300
1: \(=\dfrac{15}{37}\cdot\dfrac{38}{41}-\dfrac{15}{37}\cdot\dfrac{74}{45}-\dfrac{38}{41}\cdot\dfrac{15}{37}-\dfrac{38}{41}\cdot\dfrac{82}{76}\)
\(=\dfrac{-2}{3}-1=-\dfrac{5}{3}\)
2: \(=\dfrac{47}{53}\cdot\dfrac{17}{3}-\dfrac{47}{53}\cdot\dfrac{53}{47}+\dfrac{17}{3}\cdot\dfrac{6}{17}-\dfrac{17}{3}\cdot\dfrac{47}{53}\)
\(=-1+2=1\)
\(4x^3+15=47\)
\(4x^3=47-15\)
\(4x^3=32\)
\(x^3=32\div4\)
\(x^3=8\)
\(x^3=2^3\)
\(\Rightarrow x=2\)
4x3 + 15 =47
4 x 3 = 47 - 15
4 x 3 =32
x 3 =32 : 4
x 3 = 8
x 3 = 2 3
=> x = 2