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Câu 1
=> ( 2x-15)^3 - (2x -15)^5=0
(2x-15)^3 * ( -(2x-15)^2+1) =0
xét 2 TH : + (2x-15)^3=0
+ 1-(2x-15)^2 =0
=> ĐPCM
\(125-\left(-75\right)+32-\left(48+32\right)\)
\(=125-\left(-75\right)+32-80\)
\(=125+75+32-80\)
\(=200+32-80\)
\(=232-80\)
\(=152\)
\(-63+415-37-115\)
\(=352-57-115\)
\(=315-115\)
\(=200\)
\(13.\left(-2\right)^2+37.4+4.\left(-150\right)\)
\(=13.2^2+37.4+4.-150\)
\(=13.4+37.4+4.-150\)
\(=4.\left(13+37+-150\right)\)
\(=4.-100\)
\(=-400\)
\(-15.x+4=79\)
\(\Leftrightarrow-15.x=79-4\)
\(\Leftrightarrow-15.x=75\)
\(\Leftrightarrow x=75:-15\)
\(\Leftrightarrow x=-5\)
Vậy \(x=-5\)
\(15-\left(2+x\right)=23\)
\(\Leftrightarrow2+x=15-23\)
\(\Leftrightarrow2+x=-8\)
\(\Leftrightarrow x=-8-2\)
\(\Leftrightarrow x=-10\)
Vậy \(x=-10\)
\(\left(x+2\right)\left(x^2-1\right)=0\)
\(\Leftrightarrow\left(x+2\right)\left(x^2-1^2\right)=0\)
\(\Leftrightarrow\left(x+2\right)\left(x+1\right)\left(x-1\right)=0\)
\(\Leftrightarrow\left(x+1\right)\left(x-1\right)=0\)
\(\Leftrightarrow x=\pm1\)
Vậy \(x\in\left\{\pm1\right\}\)
\(56:\left|x-4\right|=7\)
\(\Leftrightarrow\left|x-4\right|=56:7\)
\(\Leftrightarrow\left|x-4\right|=8\)
\(\Leftrightarrow\orbr{\begin{cases}x-4=8\\x-4=-8\end{cases}\Leftrightarrow\orbr{\begin{cases}x=8+4\\x=-8+4\end{cases}\Leftrightarrow}\orbr{\begin{cases}x=12\\x=-4\end{cases}}}\)
Vậy \(x\in\left\{12;-4\right\}\)
-63+415-37-115
=(-63-37)+(415-115)
=-100+300
=200
nhớ k cho mình nha
học tốt
\(-63+415-37-115\)
\(=352-57-115\)
\(=315-115\)
\(=200\)
\(13.\left(-2\right)^2+37.4+4.\left(-15\right)\)
\(=13.2^2+37.4+4.-150\)
\(=13.4+37.4+4.-150\)
\(=4.\left(13+37+-150\right)\)
\(=4.-100\)
\(=-400\)
\(a.=\left(50-50\right)+\left(2+15\right)-17\)
\(=0+17-17\)
\(=0\)
/ x - 47 / - 115 = 0
x - 47 = 0 + 115
x - 47 = 115
x = 115 + 47
x = 162
215 + ( 146 - x ) = 401
146 - x = 401 - 215
146 - x = 186
x = 186 - 146
x = 40
4 . 2x - 3 = 125
4 . 2x = 125 + 3
4 . 2x = 128
2x = 128 : 4
2x = 32
2x = 25
x = 5 + 0
x = 5
Hok Tốt !!
a/ |x-47| - 115 = 0
|x-47| = 0+115 = 115
=> x-47=115 hay x-47=(-115)
x=115+47=162 hay x=(-115)+47= (- 68)
Vậy x = 162 hay x = -68
b/315 + (164-x) = 401
164-x = 401 - 315 = 86
x= 164-86 = 78
Vậy x=78
c/(3x-6).3=34
3x-6=34 : 3 =33 = 27
3x = 27 + 6 = 33
x= 33 : 3 =11
vậy x=11
d/4.2x - 3 = 125
4.2x = 125 +3 =128
2x= 128 : 4 = 32 = 25
=> x=5
Vậy x=5
Bài 2:
a: 4x+320=480
=>4x=160
hay x=40
b: 150-x:7=120
=>x:7=30
hay x=210
a: =>13^x*3=7-4*13=7-52=-45
=>13^x=-15(loại)
b: Sửa đề: \(4^{x+1}\cdot11-4^{x+2}\cdot2=24:2^2\)
=>\(4^x\cdot4\cdot11-4^x\cdot16\cdot2=6\)
=>4^x=6/(4*11-16*2)=6/(44-32)=6/12=1/2
=>\(x\in\varnothing\)
\(4^x-23=115\)
\(\Rightarrow4^x=115+13\)
\(\Rightarrow4^x=128\)
\(\Rightarrow\left(2^2\right)^x=2^7\)
\(\Rightarrow2^{2x}=2^7\)
\(\Rightarrow2x=7\)
\(\Rightarrow x=\dfrac{7}{2}\)