Hãy nhập câu hỏi của bạn vào đây, nếu là tài khoản VIP, bạn sẽ được ưu tiên trả lời.
a] 4/12 ; 5/12 ; 11/2 ; 1/4
b] 1 ; 9/12; 12/5 ; 11/3
c] 8/21; 6/11;8/7
d] 2/3 ;2/7 15/2
a]1/3 5/12 11/2 1/4
b]1 3/4 12/5 33/9
c]8/21 6/11 8/7
d]2/3 2/7 15/2
1+2+3+4+5+6+7+8+9+1+2+3+4+5+6+7+8+9+1+2+3+4+5+6+7+8+9=135
\(\frac{7}{9}+\frac{9}{10}=\frac{70}{90}+\frac{81}{90}=\frac{70+81}{90}=\frac{151}{90}\)
\(1\frac{1}{10}-\frac{3}{4}=\frac{11}{10}-\frac{3}{4}=\frac{22}{20}-\frac{15}{20}=\frac{22-15}{20}=\frac{7}{20}\)
\(2\frac{1}{4}\)x\(3\frac{2}{5}\)=\(\frac{9}{4}\)x\(\frac{17}{5}=\)\(\frac{9x17}{4x5}=\frac{153}{20}\)
\(\frac{2}{5}:\frac{7}{9}=\frac{2}{5}\)x\(\frac{9}{7}=\frac{2x9}{5x7}=\frac{18}{35}\)
a) \(\frac{3}{7}+\frac{2}{5}+\frac{1}{3}=\frac{3\cdot15}{7\cdot15}+\frac{2\cdot21}{5\cdot21}+\frac{1\cdot35}{3\cdot35}\)
\(=\frac{45}{105}+\frac{42}{105}+\frac{35}{105}=\frac{45+42+35}{105}=\frac{122}{105}\)
b) \(6-\left(\frac{3}{4}+\frac{2}{7}\right)=6-\left(\frac{21}{28}+\frac{8}{28}\right)=6-\frac{29}{28}=\frac{139}{26}\)
c) \(\frac{8}{9}-\frac{3}{7}:\frac{2}{9}\cdot\frac{3}{4}=\frac{8}{9}-\frac{27}{14}\cdot\frac{3}{4}=\frac{8}{9}-\frac{81}{56}=-\frac{281}{504}\)
hok tốt
.....
\(\frac{3}{7}+\frac{2}{5}+\frac{1}{3}\)
\(=\frac{29}{35}+\frac{1}{3}\)
\(=\frac{122}{105}\)
\(6-\left(\frac{3}{4}+\frac{2}{7}\right)\)
\(=6-\frac{29}{28}\)
\(=\frac{139}{28}\)
\(\frac{8}{9}-\frac{3}{7}\div\frac{2}{9}\times\frac{3}{4}\)
\(=\frac{8}{9}-\frac{27}{14}\times\frac{3}{4}\)
\(=\frac{8}{9}-\frac{81}{56}\)
\(=-\frac{281}{504}\)
\(a)9+\frac{24}{25}=\frac{9\cdot25+24}{25}=\frac{249}{25}\)
\(b)\frac{1}{20}+\frac{1}{4}+\frac{2}{5}=\frac{1}{20}+\frac{5}{20}+\frac{8}{20}=\frac{1+5+8}{20}=\frac{14}{20}=\frac{7}{10}\)
\(c)\frac{7}{12}+4=\frac{7}{12}+\frac{4}{1}=\frac{7+48}{12}=\frac{55}{12}\)
\(d)10+\frac{9}{8}=\frac{10}{1}+\frac{9}{8}=\frac{80+9}{8}=\frac{89}{8}\)
\(e)\frac{1}{4}+\frac{2}{25}+\frac{9}{100}=\frac{25}{100}+\frac{8}{100}+\frac{9}{100}=\frac{25+8+9}{100}=\frac{42}{100}=\frac{21}{50}\)
Còn 3 câu làm tương tự
Ba câu còn lại mình làm luôn :D
\(f)\frac{28}{90}+6=\frac{14}{45}+6=\frac{14}{45}+\frac{6}{1}=\frac{14+270}{45}=\frac{284}{45}\)
\(g)\frac{3}{7}+\frac{4}{9}+\frac{4}{7}+\frac{7}{11}=(\frac{3}{7}+\frac{4}{7})+\frac{4}{9}+\frac{4}{11}=1+\frac{4}{9}+\frac{4}{11}\)
\(=\frac{7}{7}+\frac{4}{9}+\frac{4}{11}=\frac{693+308+252}{693}=\frac{1253}{693}=\frac{179}{99}\)
\(h)\frac{1}{8}+\frac{1}{12}+\frac{3}{8}+\frac{5}{12}=(\frac{1}{8}+\frac{3}{8})+(\frac{1}{12}+\frac{5}{12})=\frac{4}{8}+\frac{6}{12}=\frac{1}{2}+\frac{1}{2}=1\)
a, không đủ thông tin
b, 12/27 - x = 2/9
x = 12/27 - 2/9
x = 12/27 - 6/27
x = 6/27
c, 4/5 * x = 9/7
x = 9/7 : 4/5
x = 9/7 * 5/4
x = 45/28
d, 31/29 : x = 9/7
x = 31/29 : 9/7
x = 31/29 * 7/9
x = 217/261
$\frac47+\frac29=\frac{36}{63}+\frac{14}{63}=\frac{50}{63}$
Giúp con với